Chapter 13.1, Problem 41PPS

To determine

Calculate the equation.

Answer to Problem 41PPS

The value of N is ${54.9}^{\circ }$ .

Explanation of Solution

Given: It is given in the question that the equation is $\sin N=\frac{9}{11}$ .

Concept Used:

In this, use the concept of pythagoras theorem and trigonometric ratios and the formula will be $h^2=p^2+b^2$ , $\sin \theta =\frac{p}{h},\cos \theta =\frac{b}{h},\tan \theta =\frac{p}{b},\csc \theta =\frac{h}{p},\sec \theta =\frac{h}{b},\cot \theta =\frac{b}{p}$ .

Calculation:

Here, use the trigonometric ratios,

  $\begin{array}{l}\sin \theta =\frac{p}{h}\\ \sin N=\frac{9}{11}\\ N={\sin }^{-1}(\frac{9}{11})\\ N={54.9}^{\circ }\end{array}$

Conclusion:

The value of N is ${54.9}^{\circ }$ .