Chapter 13.7, Problem 24PPS

To determine

To find: Period and graph of the function.

Answer to Problem 24PPS

Period $={360}^0$

Explanation of Solution

Given information:

  $y=3\sec \theta$

Concept:

If function is in the form

  $y=a\sec b\theta$

Then

Amplitude $=undefined$

Period $=\frac{{360}^0}{\left|b\right|}$

Given

  $y=3\sec \theta$

On comparing with $y=a\sec b\theta$

We get

  $\begin{array}{l}a=3\\ b=1\end{array}$

Therefore,

Amplitude $=undefined$

Period $=\frac{{360}^0}{\left|b\right|}$

  $\Rightarrow$ Period $=\frac{{360}^0}{\left|1\right|}$

  $\Rightarrow$ Period $={360}^0$

Therefore,

Period $={360}^0$

Graph of given function is

  

X-axis represents $\theta$ .