Chapter 13, Problem 17PT

To determine

To find: An Angle.

Answer to Problem 17PT

Required Angle $=\theta ={310}^0$

Explanation of Solution

Given information:

Sine and Tangent are negative

Given

Sine and Tangent are negative

We know

All trigonometric functions are positive in Quadrant-I

In Quadrant II only sine and cosecant functions are positive

In Quadrant III tan and cot functions are positive

In Quadrant IV cosine and secant functions are positive.

As we need both sine and tangent functions to be negative

It is possible only if the required angle present in Quadrant IV

Among the given options only angle ${310}^0$ is present in Quadrant IV

So,

Required Angle $=\theta ={310}^0$