Chapter 13.4, Problem 67S

To determine

To find:Evaluate each expression.

Answer to Problem 67S

  $w^2+y^2-6xz=56.25$

Explanation of Solution

Given information:

  $\begin{array}{l}w=6\\ x=-4\\ y=1.5\\ z=\frac{3}{4}\end{array}$

  $w^2+y^2-6xz$

  $w^2+y^2-6xz$

On substituting values

We get

  $\begin{array}{l}{w}^2+y^2-6xz=6^2+{\left(1.5\right)}^2-6\left(-4\right)\left(\frac{3}{4}\right)\\ \Rightarrow w^2+y^2-6xz=36+2.25+24\left(\frac{3}{4}\right)\\ \Rightarrow w^2+y^2-6xz=36+2.25+24\left(\frac{3}{4}\right)\\ \Rightarrow w^2+y^2-6xz=36+2.25+\frac{72}{4}\\ \Rightarrow w^2+y^2-6xz=36+2.25+18\\ \Rightarrow w^2+y^2-6xz=56.25\end{array}$

Therefore,

  $w^2+y^2-6xz=56.25$