Chapter 13.7, Problem 14WE

To determine

To find : an equation of line described

Answer to Problem 14WE

The equation is $y=-\frac{2}{3}x-2$

Explanation of Solution

Given information :

The point is $\left(6,-6\right)$ and the slope is $-\frac{2}{3}$

Formula used :

  $y-y_1=m\left(x-x_1\right)$

Calculation :

Then use the point and slope

Using $\left(6,-6\right)$ , the equation is

  $\begin{array}{l}y-\left(-6\right)=-\frac{2}{3}\left(x-6\right)\\ y+6=-\frac{2}{3}x+\frac{12}{3}\\ y=-\frac{2}{3}x+4-6\\ y=-\frac{2}{3}x-2\end{array}$

Hence, the equation is $y=-\frac{2}{3}x-2$ .