Chapter 13.5, Problem 7ST1

To determine

To find: the center of the circle

Answer to Problem 7ST1

The center of the circle is $\left(-2,3\right)$

Explanation of Solution

Given information: The radius is ${\left(x+2\right)}^2+{\left(y-3\right)}^2=36$

Calculation:

  $\begin{array}{l}center\left(x_1,y_1\right)\text{ and radius }r\\ \Rightarrow {\left(x-x_1\right)}^2+{\left(y-y_1\right)}^2=r^2\\ \Rightarrow {\left(x+2\right)}^2+{\left(y-3\right)}^2=36\end{array}$

So, the center is $\left(-2,3\right)$ and the radius is $6$