Chapter 13.6, Problem 31WE

a.

To determine

To find: the slope of the line.

Answer to Problem 31WE

The slope of the line is $m=-2$ .

Explanation of Solution

Given information: The lines $6x+3y=10$ and $y=-2x+5$ .

Calculation:

The equation of slope is $y=mx+c$ where $m$ the slope is:

  $\begin{array}{l}y=-2x+\frac{10}{3}\\ m=-2\\ y=-2x+5\\ m=-2\end{array}$

b.

To determine

To explain: do the lines are intersecting.

Answer to Problem 31WE

The lines are not intersect

Explanation of Solution

Given information: The lines $6x+3y=10$ and $y=-2x+5$ .

  $m_1=m_2=-2$

So these lines are parallel and not intersect each other

c.

To determine

To explain: what happen when the equation solve algebraically.

Answer to Problem 31WE

The lines are parallel.

Explanation of Solution

Given information: The lines $6x+3y=10$ and $y=-2x+5$ .

Two lines $l\&k$ in a plane are said to be parallel if $lm$ is equal and are denoted by $l\parallel m$ .