Chapter 13.7, Problem 13WE

To determine

To find : an equation of line described

Answer to Problem 13WE

The equation is $y=\frac{1}{3}x+6$

Explanation of Solution

Given information :

The point is $\left(-3,5\right)$ and the slope is $\frac{1}{3}$

Formula used :

  $y-y_1=m\left(x-x_1\right)$

Calculation :

Then use the point and slope

Using $\left(-3,5\right)$ , the equation is

  $\begin{array}{l}y-5=\frac{1}{3}\left(x-\left(-3\right)\right)\\ y=\frac{1}{3}x+\frac{3}{3}+5\\ y=\frac{1}{3}x1+5\\ y=\frac{1}{3}x+6\end{array}$

Hence, the equation is $y=\frac{1}{3}x+6$ .