Chapter 13.4, Problem 1CE

a.

To determine

To name the vector as an ordered pair.

Answer to Problem 1CE

The required solution is, $-\overrightarrow{AG}$ .

Explanation of Solution

Given information:The vector is $\overrightarrow{OB}$ .

  

Calculation:The required solution is obtained as,

  $\overrightarrow{OB}=\left(4,-3\right)=-\left(-4,3\right)=-\overrightarrow{AG}$

Hence, the required solution is, $-\overrightarrow{AG}$ .

b.

To determine

To name the vector as an ordered pair.

Answer to Problem 1CE

The required solution is, $\overrightarrow{BC}$ .

Explanation of Solution

Given information: The vector is $\overrightarrow{OD}$ .

  

Calculation: The required solution is obtained as,

  $\overrightarrow{OD}=\left(1,4\right)=\overrightarrow{BC}$

Hence, the required solution is, $\overrightarrow{BC}$ .

c.

To determine

To name the vector as an ordered pair.

Answer to Problem 1CE

The required solution is, $-5\overrightarrow{DO}-10\overrightarrow{EF}$ .

Explanation of Solution

Given information: The vector is $\overrightarrow{DE}$ .

  

Calculation: The required solution is obtained as,

  $\begin{array}{l}\overrightarrow{DE}=\left(-5,0\right)=\left(-5,-20\right)+\left(0,20\right)=-5\left(1,4\right)-10\left(0,-2\right)\\ =-5\overrightarrow{DO}-10\overrightarrow{EF}\end{array}$

Hence, the required solution is, $-5\overrightarrow{DO}-10\overrightarrow{EF}$ .

d.

To determine

To name the vector as an ordered pair.

Answer to Problem 1CE

The required solution is, $-\frac{1}{2}\overrightarrow{OD}-\frac{1}{10}\overrightarrow{DE}$ .

Explanation of Solution

Given information: The vector is $\overrightarrow{EF}$ .

  

Calculation: The required solution is obtained as,

  $\begin{array}{l}10\overrightarrow{EF}=10\left(,-2\right)=\left(-5,-20\right)+\left(5,0\right)=-5\left(1,5\right)-\left(0,-5\right)=-5\overrightarrow{OD}-\overrightarrow{DE}\\ \overrightarrow{EF}=-\frac{1}{2}\overrightarrow{OD}-\frac{1}{10}\overrightarrow{DE}\end{array}$

Hence, the required solution is, $-\frac{1}{2}\overrightarrow{OD}-\frac{1}{10}\overrightarrow{DE}$ .

e.

To determine

To name the vector as an ordered pair.

Answer to Problem 1CE

The required solution is, $\overrightarrow{OD}$ .

Explanation of Solution

Given information: The vector is $\overrightarrow{BC}$ .

  

Calculation: The required solution is obtained as,

  $\overrightarrow{BC}=\left(1,5\right)=\overrightarrow{OD}$

Hence, the required solution is, $\overrightarrow{OD}$ .

f.

To determine

To name the vector as an ordered pair.

Answer to Problem 1CE

The required solution is, $-\overrightarrow{OB}$ .

Explanation of Solution

Given information: The vector is $\overrightarrow{AG}$ .

  

Calculation: The required solution is obtained as,

  $\overrightarrow{AG}=\left(-4,3\right)=-\left(4,-3\right)=-\overrightarrow{OB}$

Hence, the required solution is, $-\overrightarrow{OB}$ .