Chapter 13, Problem 5CR

To determine

To calculate: equation of the circle

Answer to Problem 5CR

The equation of the circle is obtained as ${(x+6)}^2+{(y+1)}^2=9$ .

Explanation of Solution

Given information: center and radius of the circle is $(-6,-1)$ and the radius of circle is $3$

Formula used:

Equation of circle is ${(x-h)}^2+{(y-k)}^2=r^2$ where $(h,k)$ is its center and $r$ is radius.

Calculation:

As the center is $(h,k)$ which is equal to $(-6,-1)$

Now comparing the two, we have $h=-6$ and $k=-1$ .

We have $r=3$

Now using this in the equation of circle we have ${(x-(-6))}^2+{(y-(-1))}^2=3^2$

Which is equal to ${(x+6)}^2+{(y+1)}^2=9$