(a)
Interpretation: Electronic configuration of a given ion is to be determined.
Concept introduction:
The arrangement of an element's electrons throughout several atomic orbitals is represented by the electronic configuration of that element.
(a)
Answer to Problem 85A
Explanation of Solution
The
(b)
Interpretation: Electronic configuration of a given ion is to be determined.
Concept introduction:
The arrangement of an element's electrons throughout several atomic orbitals is represented by the electronic configuration of that element.
(b)
Answer to Problem 85A
Explanation of Solution
The atomic number of S is 16. After gaining 2 electrons, the no. of electrons becomes 18. The electronic configuration of
(c)
Interpretation: Electronic configuration of a given ion is to be determined.
Concept introduction:
The arrangement of an element's electrons throughout several atomic orbitals is represented by the electronic configuration of that element.
(c)
Answer to Problem 85A
Explanation of Solution
The atomic number of Li is 3. After losing 1 electron, the no. of electrons becomes 2. The electronic configuration of
Chapter 13 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
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- Q1: Curved Arrows, Bronsted Acids & Bases, Lewis Acids & Bases Considering the following reactions: a) Predict the products to complete the reactions. b) Use curved electron-pushing arrows to show the mechanism for the reaction in the forward direction. Redraw some of the compounds to explicitly illustrate all bonds that are broken and all bonds that are formed. c) Label Bronsted acids and bases in the left side of the reactions. Label conjugate acids and bases in the right side of the reactions. d) Label Lewis acids and bases, nucleophiles and electrophiles in the left side of the reactions. A. + OH CH30: OH B. + HBr C. H₂SO4 D. CF 3. CH 3 + HCI N H fluoxetine antidepressant 1↓ JDownloadarrow_forwardDon't used Ai solutionarrow_forwardPart 3: AHm,system Mass of 1.00 M HCI Vol. of 1.00 M HCI Mass of NaOH(s) Total Mass in Calorimeter Mole product if HCI limiting reactant Trial 1 62.4009 1.511g Mole product if NaOH limiting reactant Limiting reactant Initial Temperature Final Temperature 23.8°C 37.6°C Change in Temperature AHm,system (calculated) Average AHm,system (calculated) (calculated) (calculated) Trial 2 64.006g 1.9599 (calculated) (calculated) (calculated) (calculated) (calculated) (calculated) 24.7°C 41.9°C (calculated) (calculated) (2 pts. each)arrow_forward
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