Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
expand_more
expand_more
format_list_bulleted
Question
Chapter 13, Problem 97A
(a)
Interpretation Introduction
Interpretation: Between magnesium and mercury, the metal which is high in the activity series is to be identified.
Concept introduction:
An activity series is a form of element ordering system that rates each element's reactivity in relation to other elements.
(a)
Expert Solution
Answer to Problem 97A
Magnesium
Explanation of Solution
The activity series is a list of typical reduction potentials with the likelihood of compounds to be reduced listed in descending order. Metals towards the top of the series can produce positive ions more easily by losing electrons. Now, the above reaction is balanced.
Magnesium lose electrons more easily than mercury.
Thus, magnesium is higher in the activity series than mercury.
(b)
Interpretation Introduction
Interpretation: Between magnesium and mercury, the metal which is high in the activity series is to be identified.
Concept introduction:
An activity series is a form of element ordering system that rates each element's reactivity in relation to other elements.
(b)
Expert Solution
Answer to Problem 97A
Lithium
Explanation of Solution
The activity series is a list of typical reduction potentials with the likelihood of compounds to be reduced listed in descending order. Metals towards the top of the series can produce positive ions more easily by losing electrons. Now, the above reaction is balanced.
Lithium loses electrons more easily than potassium.
Thus, lithium is higher in the activity series than potassium.
Chapter 13 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
Ch. 13.1 - Prob. 1SPCh. 13.1 - Prob. 2SPCh. 13.1 - Prob. 3LCCh. 13.1 - Prob. 4LCCh. 13.1 - Prob. 5LCCh. 13.1 - Prob. 6LCCh. 13.1 - Prob. 7LCCh. 13.1 - Prob. 8LCCh. 13.1 - Prob. 9LCCh. 13.2 - Prob. 10LC
Ch. 13.2 - Prob. 11LCCh. 13.2 - Prob. 12LCCh. 13.2 - Prob. 13LCCh. 13.2 - Prob. 15LCCh. 13.2 - Prob. 16LCCh. 13.2 - Prob. 17LCCh. 13.3 - Prob. 18LCCh. 13.3 - Prob. 19LCCh. 13.3 - Prob. 20LCCh. 13.3 - Prob. 21LCCh. 13.3 - Prob. 22LCCh. 13.3 - Prob. 23LCCh. 13.3 - Prob. 24LCCh. 13.4 - Prob. 25LCCh. 13.4 - Prob. 26LCCh. 13.4 - Prob. 27LCCh. 13.4 - Prob. 29LCCh. 13.4 - Prob. 30LCCh. 13 - Prob. 31ACh. 13 - Prob. 32ACh. 13 - Prob. 33ACh. 13 - Prob. 34ACh. 13 - Prob. 35ACh. 13 - Prob. 36ACh. 13 - Prob. 37ACh. 13 - Prob. 38ACh. 13 - Prob. 39ACh. 13 - Prob. 40ACh. 13 - Prob. 41ACh. 13 - Prob. 42ACh. 13 - Prob. 43ACh. 13 - Prob. 44ACh. 13 - Prob. 45ACh. 13 - Prob. 46ACh. 13 - Prob. 47ACh. 13 - Prob. 49ACh. 13 - Prob. 50ACh. 13 - Prob. 51ACh. 13 - Prob. 52ACh. 13 - Prob. 53ACh. 13 - Prob. 54ACh. 13 - Prob. 55ACh. 13 - Prob. 57ACh. 13 - Prob. 58ACh. 13 - Prob. 60ACh. 13 - Prob. 61ACh. 13 - Prob. 62ACh. 13 - Prob. 63ACh. 13 - Prob. 64ACh. 13 - Prob. 67ACh. 13 - Prob. 68ACh. 13 - Prob. 69ACh. 13 - Prob. 70ACh. 13 - Prob. 71ACh. 13 - Prob. 72ACh. 13 - Prob. 73ACh. 13 - Prob. 74ACh. 13 - Prob. 75ACh. 13 - Prob. 76ACh. 13 - Prob. 77ACh. 13 - Prob. 78ACh. 13 - Prob. 79ACh. 13 - Prob. 80ACh. 13 - Prob. 81ACh. 13 - Prob. 82ACh. 13 - Prob. 83ACh. 13 - Prob. 84ACh. 13 - Prob. 85ACh. 13 - Prob. 86ACh. 13 - Prob. 87ACh. 13 - Prob. 88ACh. 13 - Prob. 89ACh. 13 - Prob. 90ACh. 13 - Prob. 91ACh. 13 - Prob. 92ACh. 13 - Prob. 93ACh. 13 - Prob. 94ACh. 13 - Prob. 95ACh. 13 - Prob. 96ACh. 13 - Prob. 97ACh. 13 - Prob. 98ACh. 13 - Prob. 99ACh. 13 - Prob. 100ACh. 13 - Prob. 101ACh. 13 - Prob. 102ACh. 13 - Prob. 1STPCh. 13 - Prob. 2STPCh. 13 - Prob. 3STPCh. 13 - Prob. 4STPCh. 13 - Prob. 5STPCh. 13 - Prob. 6STPCh. 13 - Prob. 7STPCh. 13 - Prob. 8STPCh. 13 - Prob. 9STPCh. 13 - Prob. 10STP
Knowledge Booster
Similar questions
- 3. Name this ether correctly. H₁C H3C CH3 CH3 4. Show the best way to make the ether in #3 by a Williamson Ether Synthesis. Start from an alcohol or phenol. 5. Draw the structure of an example of a sulfide.arrow_forward1. Which one(s) of these can be oxidized with CrO3 ? (could be more than one) a) triphenylmethanol b) 2-pentanol c) Ethyl alcohol d) CH3 2. Write in all the product(s) of this reaction. Label them as "major" or "minor". 2-methyl-2-hexanol H2SO4, heatarrow_forward3) Determine if the pairs are constitutional isomers, enantiomers, diastereomers, or mesocompounds. (4 points)arrow_forward
- In the decomposition reaction in solution B → C, only species C absorbs UV radiation, but neither B nor the solvent absorbs. If we call At the absorbance measured at any time, A0 the absorbance at the beginning of the reaction, and A∞ the absorbance at the end of the reaction, which of the expressions is valid? We assume that Beer's law is fulfilled.arrow_forward> You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products: 1. ☑ CI 2. H3O+ O Draw the missing reagent X you think will make this synthesis work in the drawing area below. If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. Explanation Check ? DO 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibilityarrow_forwardDon't use ai to answer I will report you answerarrow_forward
- Consider a solution of 0.00304 moles of 4-nitrobenzoic acid (pKa = 3.442) dissolved in 25 mL water and titrated with 0.0991 M NaOH. Calculate the pH at the equivalence pointarrow_forwardWhat is the name of the following compound? SiMe3arrow_forwardK Draw the starting structure that would lead to the major product shown under the provided conditions. Drawing 1. NaNH2 2. PhCH2Br 4 57°F Sunny Q Searcharrow_forward
- 7 Draw the starting alkyl bromide that would produce this alkyne under these conditions. F Drawing 1. NaNH2, A 2. H3O+ £ 4 Temps to rise Tomorrow Q Search H2arrow_forward7 Comment on the general features of the predicted (extremely simplified) ¹H- NMR spectrum of lycopene that is provided below. 00 6 57 PPM 3 2 1 0arrow_forwardIndicate the compound formula: dimethyl iodide (propyl) sulfonium.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY