Chapter 13, Problem 26A

Interpretation Introduction

Interpretation:

The mass of hydrogen gas have to be calculated.

Concept Introduction:

The ideal gas law was derived by combining three important laws of the gases. The ideal gas law can be expressed as-

  $\begin{array}{l}V\propto \frac{\mathrm{n}T}{P}\\ \mathrm{PV}=nRT\end{array}$ Where, R is universal gas constant.

The ideal gas law consists of all the variables of a gas such as pressure (P), volume (V), number of moles (n) and temperature (T).

Answer to Problem 26A

Mass of hydrogen gas is 3.62 gm.

Explanation of Solution

Data given:

Pressure = 1.09 atm

Volume = 40.9 L

Temperature = 27 °C = 300 K

R = 0.082 L atm/mol K

  $\begin{array}{l}PV=nRT\\ n=\frac{PV}{RT}\\ =\frac{1.09atm\times 40.9L}{0.082Latm/molK\times 300K}=1.81mol\end{array}$

Number of moles of hydrogen = 1.81 mol

Mass of hydrogen gas = $1.81mol\times 2gm/mol=3.62gm$