Chapter 13, Problem 16A

Interpretation Introduction

Interpretation:

The new volume of the gas have to be calculated.

Concept Introduction:

Charles’s law: The volume of a given amount of gas is proportional to its temperature (in K) of the gas at constant pressure.

The relationship between volume of a gas and temperature is expressed as-

  $\begin{array}{l}V\propto T\\ \mathrm{or},\frac{V}{T}=Constant\end{array}$ When P is constant.

Charles’s law can also be expressed in mathematical form as-

  $\frac{V_1}{T_1}=\frac{V_2}{T_2}$

In the above equation, V₁ is initial volume and T₁ is initial temperature, while V₂ is final or new volume and T₂ is final or new temperature.

Answer to Problem 16A

The new volume of the gas is 50.5 mL.

Explanation of Solution

Data given: V₁ =5.00 L

T₁ = 24 °C = (273 + 24) K = 297 K

T₂ = -272 °C = (273 - 272) K = 3 K

  $\begin{array}{l}\frac{V_1}{T_1}=\frac{V_2}{T_2}\\ V_2=\frac{V_1\times T_2}{T_1}=\frac{5.00L\times 3K}{297K}\\ =0.0505L=50.5mL\end{array}$