The steps how the two products formed from reaction of methylenecyclohehane with NBS has to be given. Stereoisomers has to be disregarded. Concept introduction: Bromination of Allylic Carbons: N-bromosuccinimide (NBS) is used for the allylic bromination through radical reaction. Bromination of allylicc carbon requires low concentration of bromine and low concentration of hydrobromic acid. If high concentration of bromine and high concentration of hydrobromic acid which leads to the formation of bromonation in the double bond. Bromination reaction starts with the homolytic cleavage of N-Br bond in N-bromosuccinimide (NBS) which creates bromine radical to initiate the radical bromination reaction. NBS bromine radical removes the allylic hydrogen which forms hydrogen bromide and allylic radical in the first propagation step, the allylic radical is stabilized by the double bond in ring. This allylic radical reaction with bromine molecule and forms allylic bromide in the second propagation step which are shown above.

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Answer 1

Question

Chapter 12.9, Problem 18P

Interpretation Introduction

Interpretation:

The steps how the two products formed from reaction of methylenecyclohehane with NBS has to be given. Stereoisomers has to be disregarded.

Concept introduction:

Bromination of Allylic Carbons:

N-bromosuccinimide (NBS) is used for the allylic bromination through radical reaction. Bromination of allylicc carbon requires low concentration of bromine and low concentration of hydrobromic acid. If high concentration of bromine and high concentration of hydrobromic acid which leads to the formation of bromonation in the double bond.

Bromination reaction starts with the homolytic cleavage of N-Br bond in N-bromosuccinimide (NBS) which creates bromine radical to initiate the radical bromination reaction.

NBS bromine radical removes the allylic hydrogen which forms hydrogen bromide and allylic radical in the first propagation step, the allylic radical is stabilized by the double bond in ring. This allylic radical reaction with bromine molecule and forms allylic bromide in the second propagation step which are shown above.

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Answer 2

Question

Chapter 12.9, Problem 18P

Interpretation Introduction

Interpretation:

The steps how the two products formed from reaction of methylenecyclohehane with NBS has to be given. Stereoisomers has to be disregarded.

Concept introduction:

Bromination of Allylic Carbons:

N-bromosuccinimide (NBS) is used for the allylic bromination through radical reaction. Bromination of allylicc carbon requires low concentration of bromine and low concentration of hydrobromic acid. If high concentration of bromine and high concentration of hydrobromic acid which leads to the formation of bromonation in the double bond.

Bromination reaction starts with the homolytic cleavage of N-Br bond in N-bromosuccinimide (NBS) which creates bromine radical to initiate the radical bromination reaction.

NBS bromine radical removes the allylic hydrogen which forms hydrogen bromide and allylic radical in the first propagation step, the allylic radical is stabilized by the double bond in ring. This allylic radical reaction with bromine molecule and forms allylic bromide in the second propagation step which are shown above.

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Answer 3

Question

Chapter 12.9, Problem 18P

Interpretation Introduction

Interpretation:

The steps how the two products formed from reaction of methylenecyclohehane with NBS has to be given. Stereoisomers has to be disregarded.

Concept introduction:

Bromination of Allylic Carbons:

N-bromosuccinimide (NBS) is used for the allylic bromination through radical reaction. Bromination of allylicc carbon requires low concentration of bromine and low concentration of hydrobromic acid. If high concentration of bromine and high concentration of hydrobromic acid which leads to the formation of bromonation in the double bond.

Bromination reaction starts with the homolytic cleavage of N-Br bond in N-bromosuccinimide (NBS) which creates bromine radical to initiate the radical bromination reaction.

NBS bromine radical removes the allylic hydrogen which forms hydrogen bromide and allylic radical in the first propagation step, the allylic radical is stabilized by the double bond in ring. This allylic radical reaction with bromine molecule and forms allylic bromide in the second propagation step which are shown above.

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Answer 4

Question

Chapter 12.9, Problem 18P

Interpretation Introduction

Interpretation:

The steps how the two products formed from reaction of methylenecyclohehane with NBS has to be given. Stereoisomers has to be disregarded.

Concept introduction:

Bromination of Allylic Carbons:

N-bromosuccinimide (NBS) is used for the allylic bromination through radical reaction. Bromination of allylicc carbon requires low concentration of bromine and low concentration of hydrobromic acid. If high concentration of bromine and high concentration of hydrobromic acid which leads to the formation of bromonation in the double bond.

Bromination reaction starts with the homolytic cleavage of N-Br bond in N-bromosuccinimide (NBS) which creates bromine radical to initiate the radical bromination reaction.

NBS bromine radical removes the allylic hydrogen which forms hydrogen bromide and allylic radical in the first propagation step, the allylic radical is stabilized by the double bond in ring. This allylic radical reaction with bromine molecule and forms allylic bromide in the second propagation step which are shown above.

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Answer 5

Chapter 12.9, Problem 18P

Interpretation Introduction

Interpretation:

The steps how the two products formed from reaction of methylenecyclohehane with NBS has to be given. Stereoisomers has to be disregarded.

Concept introduction:

Bromination of Allylic Carbons:

N-bromosuccinimide (NBS) is used for the allylic bromination through radical reaction. Bromination of allylicc carbon requires low concentration of bromine and low concentration of hydrobromic acid. If high concentration of bromine and high concentration of hydrobromic acid which leads to the formation of bromonation in the double bond.

Bromination reaction starts with the homolytic cleavage of N-Br bond in N-bromosuccinimide (NBS) which creates bromine radical to initiate the radical bromination reaction.

NBS bromine radical removes the allylic hydrogen which forms hydrogen bromide and allylic radical in the first propagation step, the allylic radical is stabilized by the double bond in ring. This allylic radical reaction with bromine molecule and forms allylic bromide in the second propagation step which are shown above.

Answer 6

Chapter 12.9, Problem 18P

Interpretation Introduction

Interpretation:

The steps how the two products formed from reaction of methylenecyclohehane with NBS has to be given. Stereoisomers has to be disregarded.

Concept introduction:

Bromination of Allylic Carbons:

N-bromosuccinimide (NBS) is used for the allylic bromination through radical reaction. Bromination of allylicc carbon requires low concentration of bromine and low concentration of hydrobromic acid. If high concentration of bromine and high concentration of hydrobromic acid which leads to the formation of bromonation in the double bond.

Bromination reaction starts with the homolytic cleavage of N-Br bond in N-bromosuccinimide (NBS) which creates bromine radical to initiate the radical bromination reaction.

NBS bromine radical removes the allylic hydrogen which forms hydrogen bromide and allylic radical in the first propagation step, the allylic radical is stabilized by the double bond in ring. This allylic radical reaction with bromine molecule and forms allylic bromide in the second propagation step which are shown above.

Answer 7

Chapter 12.9, Problem 18P

Interpretation Introduction

Interpretation:

The steps how the two products formed from reaction of methylenecyclohehane with NBS has to be given. Stereoisomers has to be disregarded.

Concept introduction:

Bromination of Allylic Carbons:

N-bromosuccinimide (NBS) is used for the allylic bromination through radical reaction. Bromination of allylicc carbon requires low concentration of bromine and low concentration of hydrobromic acid. If high concentration of bromine and high concentration of hydrobromic acid which leads to the formation of bromonation in the double bond.

Bromination reaction starts with the homolytic cleavage of N-Br bond in N-bromosuccinimide (NBS) which creates bromine radical to initiate the radical bromination reaction.

NBS bromine radical removes the allylic hydrogen which forms hydrogen bromide and allylic radical in the first propagation step, the allylic radical is stabilized by the double bond in ring. This allylic radical reaction with bromine molecule and forms allylic bromide in the second propagation step which are shown above.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 12.2 - Prob. 1P Ch. 12.2 - Write the steps for formation of...Ch. 12.3 - Prob. 3P Ch. 12.4 - How many alkyl chlorides are obtained from...Ch. 12.4 - Prob. 6P Ch. 12.5 - Prob. 8P Ch. 12.5 - a. Would chlorination or bromination produce a...Ch. 12.5 - Show how the following compounds could be prepared...Ch. 12.6 - Prob. 12P Ch. 12.7 - Prob. 13P

Solution Summary: The author explains that N-bromosuccinimide (NBS) is used for the allylic bromination through radical reaction.

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