EBK ORGANIC CHEMISTRY
EBK ORGANIC CHEMISTRY
8th Edition
ISBN: 8220102744127
Author: Bruice
Publisher: PEARSON
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Chapter 12.8, Problem 15P

(a)

Interpretation Introduction

Interpretation:

The hydrocarbon with molecular formula C4H10 that forms only two monochlorinated products has to be given.  Both the products should be achiral.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Chiral: Four different atoms attached to a carbon atom is called chiral molecule.

Achiral: A molecula has superimposable mirror images are called achiral.

Stereoisomers: Stereoisomers are molecules that have the same molecular formula and they differ only in arrangement of atom in three-dimensional space.

Enantiomers: A compound which is non-superimposable mirror image is called enantiomers.

Diastereomers: A compound which is non-superimposable and non-mirror image is called enantiomers

Racemic mixture: A racemic mixture is simply a mixture containing an equal amount of each enantiomer

(b)

Interpretation Introduction

Interpretation:

The hydrocarbon with molecular formula C4H10 that forms only three monochlorinated products has to be given.  One is achiral and two should be chiral products.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Chiral: Four different atoms attached to a carbon atom is called chiral molecule.

Achiral: A molecula has superimposable mirror images are called achiral.

Stereoisomers: Stereoisomers are molecules that have the same molecular formula and they differ only in arrangement of atom in three-dimensional space.

Enantiomers: A compound which is non-superimposable mirror image is called enantiomers.

Diastereomers: A compound which is non-superimposable and non-mirror image is called enantiomers

Racemic mixture: A racemic mixture is simply a mixture containing an equal amount of each enantiomer

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9 7 8 C 9 8 200 190 B 5 A -197.72 9 8 7 15 4 3 0: ང་ 200 190 180 147.52 134.98 170 160 150 140 130 120 110 100 90 90 OH 10 4 3 1 2 -143.04 140. 180 170 160 150 140 130 120 110 100 90 CI 3 5 1 2 141.89 140.07 200 190 180 170 160 150 140 130 120 110 100 ៖- 90 129. 126.25 80 70 60 -60 50 40 10 125.19 -129.21 80 70 3.0 20 20 -8 60 50 10 ppm -20 40 128.31 80 80 70 60 50 40 40 -70.27 3.0 20 10 ppm 00˚0-- 77.17 30 20 20 -45.36 10 ppm -0.00 26.48 22.32 ―30.10 ―-0.00
Assign all the carbons
C 5 4 3 CI 2 the Righ B A 5 4 3 The Lich. OH 10 4 5 3 1 LOOP- -147.52 T 77.17 -45.36 200 190 180 170 160 150 140 130 120 110 100 90 80 70 60 50 40 30 20 10 ppm B -126.25 77.03 200 190 180 170 160 150 140 130 120 110 100 90 80 70 60 50 40 30 20 10 ppm 200 190 180 170 160 150 140 130 120 110 100 90 80 TO LL <-50.00 70 60 50 40 30 20 10 ppm 45.06 30.18 -26.45 22.36 --0.00 45.07 7.5 1.93 2.05 -30.24 -22.36 C A 7 8 5 ° 4 3 7.5 7.0 6.5 6.0 5.5 5.0 4.5 4.0 3.5 3.0 2.5 2.0 1.5 1.0 ppm 9 8 5 4 3 ཡི་ OH 10 2 7.5 7.0 6.5 6.0 5.5 5.0 4.5 4.0 3.5 3.0 2.5 2.0 1.5 5 4 3 2 that th 7 I 7.0 6.5 6.0 5.5 5.0 4.5 4.0 3.5 3.0 2.5 2.0 1.5 115 2.21 4.00 1.0 ppm 6.96 2.76 5.01 1.0 ppm 6.30 1.00

Chapter 12 Solutions

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