(a)
Interpretation:
The major product of the given reaction should be given.
Concept introduction:
Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.
Bond strength depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.
Bromination of Allylic Carbons:
N-bromosuccinimide (NBS) is used for the allylic bromination through radical reaction. Bromination of allylic carbon requires low concentration of bromine and low concentration of hydrobromic acid. If high concentration of bromine and high concentration of hydrobromic acid are used, it leads to the formation of bromination in the double bond.
Bromination reaction starts with the homolytic cleavage of
NBS bromine radical removes the allylic hydrogen which forms hydrogen bromide and allylic radical in the first propagation step, the allylic radical is stabilized by the double bond in ring. This allylic radical reacts with bromine molecule and forms allylic bromide in the second propagation step which are shown above.
(b)
Interpretation:
The major product of the given reaction should be given.
Concept introduction:
Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.
Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.
Bromination of Allylic Carbons:
N-bromosuccinimide (NBS) is used for the allylic bromination through radical reaction. Bromination of allylic carbon requires low concentration of bromine and low concentration of hydrobromic acid. If high concentration of bromine and high concentration of hydrobromic acid are used, it leads to the formation of bromination in the double bond.
Bromination reaction starts with the homolytic cleavage of
NBS bromine radical removes the allylic hydrogen which forms hydrogen bromide and allylic radical in the first propagation step, the allylic radical is stabilized by the double bond in ring. This allylic radical reacts with bromine molecule and forms allylic bromide in the second propagation step which are shown above.
(c)
Interpretation:
The major product of the given reaction should be given.
Concept introduction:
Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.
Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.
Bromination of Allylic Carbons:
N-bromosuccinimide (NBS) is used for the allylic bromination through radical reaction. Bromination of allylic carbon requires low concentration of bromine and low concentration of hydrobromic acid. If high concentration of bromine and high concentration of hydrobromic acid are used, it leads to the formation of bromination in the double bond.
Bromination reaction starts with the homolytic cleavage of
NBS bromine radical removes the allylic hydrogen which forms hydrogen bromide and allylic radical in the first propagation step, the allylic radical is stabilized by the double bond in ring. This allylic radical reacts with bromine molecule and forms allylic bromide in the second propagation step which are shown above.
(d)
Interpretation:
The major product of the given reaction should be given.
Concept introduction:
Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.
Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.
Bromination of Allylic Carbons:
N-bromosuccinimide (NBS) is used for the allylic bromination through radical reaction. Bromination of allylic carbon requires low concentration of bromine and low concentration of hydrobromic acid. If high concentration of bromine and high concentration of hydrobromic acid are used, it leads to the formation of bromination in the double bond.
Bromination reaction starts with the homolytic cleavage of
NBS bromine radical removes the allylic hydrogen which forms hydrogen bromide and allylic radical in the first propagation step, the allylic radical is stabilized by the double bond in ring. This allylic radical reacts with bromine molecule and forms allylic bromide in the second propagation step which are shown above.
(e)
Interpretation:
The major product of the given reaction should be given.
Concept introduction:
Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.
Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.
Bromination of Allylic Carbons:
N-bromosuccinimide (NBS) is used for the allylic bromination through radical reaction. Bromination of allylic carbon requires low concentration of bromine and low concentration of hydrobromic acid. If high concentration of bromine and high concentration of hydrobromic acid are used, it leads to the formation of bromination in the double bond.
Bromination reaction starts with the homolytic cleavage of
NBS bromine radical removes the allylic hydrogen which forms hydrogen bromide and allylic radical in the first propagation step, the allylic radical is stabilized by the double bond in ring. This allylic radical reacts with bromine molecule and forms allylic bromide in the second propagation step which are shown above.
(f)
Interpretation:
The major product of the given reaction should be given.
Concept introduction:
Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.
Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.
Bromination of Allylic Carbons:
N-bromosuccinimide (NBS) is used for the allylic bromination through radical reaction. Bromination of allylic carbon requires low concentration of bromine and low concentration of hydrobromic acid. If high concentration of bromine and high concentration of hydrobromic acid are used, it leads to the formation of bromination in the double bond.
Bromination reaction starts with the homolytic cleavage of
NBS bromine radical removes the allylic hydrogen which forms hydrogen bromide and allylic radical in the first propagation step, the allylic radical is stabilized by the double bond in ring. This allylic radical reacts with bromine molecule and forms allylic bromide in the second propagation step which are shown above.
Want to see the full answer?
Check out a sample textbook solutionChapter 12 Solutions
EBK ORGANIC CHEMISTRY
- Two products are formed when methylenecyclohexane reacts with NBS? Show how each is formed. Disregard stereoisomers.arrow_forwardCoO7T07Q3769 Give the major product of the following reaction. H2 Ni CIarrow_forwardWhat is (are) the major organic product(s) obtained from the following reaction? Br2 O (2R,3R)-dibromobutane meso-2,3-dibromobutane O (2S,3S)-dibromobutane O Racemic mixturearrow_forward
- what is the structure of the substitution product in the following reaction and consider stereochemistry in deciding your product?arrow_forward4. What are the products obtained from the following elimination reaction? Indicate the major product. CH;CH2CCH3 H2O CI 5. a) Determine the major product that is formed when the alkyl halide reacts with a hydroxide ion in an elimination reaction. CH;CH,CH,CH,CCH3 Br b) For the major elimination product obtained in 5a), which stereoisomer (cis or trans) is obtained in greater yield? Draw the two isomers and provide the names of the compounds.arrow_forwardIndicate the products of the reaction with their name and stereochemistry: Å CH₂ CH3 C6H5 H₂O, H+arrow_forward
- What is(are) the major product(s) of the following reaction ? HC1 H;C ОНarrow_forwardDraw the alkene that would react with the reagent given to account for the product formed. ? + H₂O H₂SO4 CH3 CH3 CHCCH3 OH CH3 • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. Sn [F ChemDoodlearrow_forwardGive the Major product(s) and name the starting compound with stereochemistry: H2O H2O H2SO4 H,SO, HgSO,arrow_forward
- Predict the product of the following reaction. A OH HNO3, H2SO4 B Name the organic product without stereochemistry. What is the molecular formula of the product?arrow_forwardThe bicyclic alkene P can be prepared by thermal electrocyclic ring closure from cyclodecadiene Q or by photochemical electrocyclic ring closure from cyclodecadiene R. Draw the structures of Q and R, and indicate the stereochemistry of the process by which each reaction occurs.arrow_forwardDraw the two major organic products of the reaction in ether. Show the stereochemistry of the products. Are the products single enantiomers or racemic mixtures?arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY