Thermodynamics: An Engineering Approach
8th Edition
ISBN: 9780073398174
Author: Yunus A. Cengel Dr., Michael A. Boles
Publisher: McGraw-Hill Education
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Chapter 12.6, Problem 88RP
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Two identical piston-cylinder devices are each filled with 1 kg air at T = 300 K and P = 2 bar. Next, one of the gases undergoes a reversible and isothermal expansion, and the other one expands isentropically.
Both of the gases stop expanding when their final volumes reach twice of their initial volumes.
[5] a) Sketch both of these processes on the same T-S plot. Indicate the direction of the expansion process on the plot. (No need to express the values for T and S on the plot)
[5] b) Sketch both of these processes on the same P-V plot. Indicate the direction of the expansion process on the plot. (No need to express the values for P and V on the plot)
[10] c) Calculate the heat transfer between the air and the surrounding for each process separately.
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One mole of an ideal gas, initially at 20 °C (293.15 K) and 1.50 bar, undergoes the following mechanically reversible changes. It is compressed isothermally to a point such that when it is heated at constant volume to 100 °C (373.15 K) its final pressure is 10 bar. Take Cp = (7/2)R and Cv = (5/2)R.
Hints:
Process 1 to 2: T1 = T2;
Process 2 to 3: (P2/T2) = (P3/T3), thus (P2/T1) = (P3/T3)
Use equations for isothermic and isochoric processes. Wtotal = W12 + W23 and Qtotal = Q12 + Q23.
What is the amount of work involved in the process?
What is the amount of heat transferred in the process?
One mole of an ideal gas, initially at 20 °C (293.15 K) and 1.50 bar, undergoes the following mechanically reversible changes. It is compressed isothermally to a point such that when it is heated at constant volume to 100 °C (373.15 K) its final pressure is 10 bar. Take Cp = (7/2)R and Cv = (5/2)R.
Hints:
Process 1 to 2: T1 = T2;
Process 2 to 3: (P2/T2) = (P3/T3), thus (P2/T1) = (P3/T3)
Use equations for isothermic and isochoric processes. Wtotal = W12 + W23 and Qtotal = Q12 + Q23.
What is the change in internal energy?
What is the change in enthalpy?
Chapter 12 Solutions
Thermodynamics: An Engineering Approach
Ch. 12.6 - What is the difference between partial...Ch. 12.6 - Consider a function z(x, y) and its partial...Ch. 12.6 - Prob. 3PCh. 12.6 - Conside the function z(x, y), its partial...Ch. 12.6 - Consider air at 350 K and 0.75 m3/kg. Using Eq....Ch. 12.6 - Consider air at 350 K and 0.75 m3/kg. Using Eq....Ch. 12.6 - 12–7 Nitrogen gas at 400 K and 300 kPa behaves as...Ch. 12.6 - Nitrogen gas at 800 R and 50 psia behaves as an...Ch. 12.6 - Prob. 9PCh. 12.6 - Using the equation of state P(v a) = RT, verify...
Ch. 12.6 - Prob. 11PCh. 12.6 - Verify the validity of the last Maxwell relation...Ch. 12.6 - Prob. 14PCh. 12.6 - Prob. 15PCh. 12.6 - Prob. 16PCh. 12.6 - Prob. 17PCh. 12.6 - Prove that (PT)=kk1(PT)v.Ch. 12.6 - Prob. 19PCh. 12.6 - Prob. 20PCh. 12.6 - Using the Clapeyron equation, estimate the...Ch. 12.6 - Prob. 22PCh. 12.6 - Prob. 23PCh. 12.6 - Determine the hfg of refrigerant-134a at 10F on...Ch. 12.6 - Prob. 25PCh. 12.6 - Prob. 26PCh. 12.6 - Prob. 27PCh. 12.6 - Prob. 28PCh. 12.6 - Prob. 29PCh. 12.6 - 12–30 Show that =
Ch. 12.6 - Prob. 31PCh. 12.6 - Prob. 32PCh. 12.6 - Prob. 33PCh. 12.6 - Prob. 34PCh. 12.6 - Prob. 35PCh. 12.6 - Prob. 36PCh. 12.6 - Determine the change in the internal energy of...Ch. 12.6 - Prob. 38PCh. 12.6 - Determine the change in the entropy of helium, in...Ch. 12.6 - Prob. 40PCh. 12.6 - Derive expressions for (a) u, (b) h, and (c) s for...Ch. 12.6 - Derive an expression for the specific heat...Ch. 12.6 - Show that cpcv=T(PT)V(VT)P.Ch. 12.6 - Prob. 44PCh. 12.6 - Prob. 45PCh. 12.6 - Derive an expression for the specific heat...Ch. 12.6 - Derive an expression for the isothermal...Ch. 12.6 - Show that = ( P/ T)v.Ch. 12.6 - Prob. 49PCh. 12.6 - Prob. 50PCh. 12.6 - Show that the enthalpy of an ideal gas is a...Ch. 12.6 - Prob. 52PCh. 12.6 - Prob. 53PCh. 12.6 - The pressure of a fluid always decreases during an...Ch. 12.6 - Does the Joule-Thomson coefficient of a substance...Ch. 12.6 - Will the temperature of helium change if it is...Ch. 12.6 - Prob. 59PCh. 12.6 - Prob. 60PCh. 12.6 - 12–61E Estimate the Joule-Thomson-coefficient of...Ch. 12.6 - Prob. 62PCh. 12.6 - Consider a gas whose equation of state is P(v a)...Ch. 12.6 - Prob. 64PCh. 12.6 - On the generalized enthalpy departure chart, the...Ch. 12.6 - Why is the generalized enthalpy departure chart...Ch. 12.6 - Prob. 67PCh. 12.6 - Prob. 68PCh. 12.6 - Prob. 69PCh. 12.6 - Prob. 70PCh. 12.6 - Prob. 71PCh. 12.6 - Prob. 72PCh. 12.6 - Prob. 73PCh. 12.6 - Prob. 75PCh. 12.6 - Propane is compressed isothermally by a...Ch. 12.6 - Prob. 78PCh. 12.6 - Prob. 80RPCh. 12.6 - Starting with the relation dh = T ds + vdP, show...Ch. 12.6 - Show that cv=T(vT)s(PT)vandcp=T(PT)s(vT)PCh. 12.6 - Temperature and pressure may be defined as...Ch. 12.6 - For ideal gases, the development of the...Ch. 12.6 - Prob. 85RPCh. 12.6 - For a homogeneous (single-phase) simple pure...Ch. 12.6 - For a homogeneous (single-phase) simple pure...Ch. 12.6 - Prob. 88RPCh. 12.6 - Estimate the cpof nitrogen at 300 kPa and 400 K,...Ch. 12.6 - Prob. 90RPCh. 12.6 - Prob. 91RPCh. 12.6 - An adiabatic 0.2-m3 storage tank that is initially...Ch. 12.6 - Prob. 93RPCh. 12.6 - Methane is to be adiabatically and reversibly...Ch. 12.6 - Prob. 96RPCh. 12.6 - Prob. 98RPCh. 12.6 - Prob. 99RPCh. 12.6 - Prob. 100FEPCh. 12.6 - Consider the liquidvapor saturation curve of a...Ch. 12.6 - Prob. 102FEPCh. 12.6 - For a gas whose equation of state is P(v b) = RT,...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Two identical piston-cylinder devices are each filled with 1 kg air at T = 300 K and P= 2 bar. Next, one of the gases undergoes a reversible and isothermal expansion, and the other one expands isentropically. Both of the gases stop expanding when their final volumes reach twice of their initial volumes. [a) Sketch both of these processes on the same T-S plot. Indicate the direction of the expansion process on the plot. (No need to express the values for T and S on the plot) b) Sketch both of these processes on the same P-V plot. Indicate the direction of the expansion process on the plot. (No need to express the values for P and V on the plot) [ c) Calculate the heat transfer between the air and the surrounding for each process separately.arrow_forwardDetermine the change in entropy of an ideal gas with constant heat capacity, CP=3.5R between the following States: P1= 1 bar, T1= 300k; V2= 0.025m³/mol;T2= 500karrow_forwardAn ideal gas with V = 5x105 cm³, P = 150x103 Pa and T = 293K is contained in a piston-cylinder. The gas is isothermally compressed with a constant external pressure of 400x103 Pa. Assuming the surroundings is at 293K and the gas Cp = 25R: %3D %3D %3D a. Determine the heat transfer during the process b. What is the entropy change of the system, surroundings, and overall? C. Is the process reversible, irreversible, or impossible?arrow_forward
- Can you re-derive the adiabatic equation of state Vf /Vi = (Ti / Tf) ^(Cv/nR), from ∂V/∂T)s = Cv/P ?arrow_forwardA perfect gas undergoes a reversible isothermal expansion to a final volume. If the same gas at the same initial state undergoes a reversible adiabatic expansion resulting in the same final volume, -how do its the pressure, temperature, and internal energy compare with the reversible isothermal expansion at the same final volume? -how does the work done by the gas compare with the reversible isothermal expansion?arrow_forwardQ 2 Helium (He) is compressed in an adiabatic compressor from an initial state of 0.9653 bar and 10°C to a final temperature of 160°C as shown in Figure Q 2. Sketch the actual and ideal compression processes on T-s diagram and determine the compressor pressure ratio and ideal specific work input if the reversible adiabatic or isentropic efficiency of the compressor is 89%. Take, for helium, M = 4.003 kg/kmol and Cp = 5.1926 kJ/(kg-K). [Hint: Use the concepts of steady-flow energy equation, SFEE, and the isentropic effi- ciency. See Portal materials for combined Weeks 15 and Week 16.]. 2 = 160°C P2=? Electric motor Не Compressor t1= 10°C P1= 0.9653 bar Figure for Q 2arrow_forward
- 6. A closed gaseous system undergoes a reversible process in which 28 BTU of heat are rejected and the volume changes from 5 cu.ft. to 20 cu.ft. The pressure is constant at 20 psia. Determine the change in internal energy of the system in BTU. (Use 1 BTU = 778 ft- lb) 83.53 -27.53 -83.53arrow_forwardAn ideal gas, initially at 30°C and 100 kPa, undergoes the following cyclic processes in a closed system: (a) In mechanically reversible processes, it is first compressed adiabatically to 500 kPa, then cooled at a constant pressure of 500 kPa to 30°C, and finally expanded isothermally to its original state. (b) The cycle traverses exactly the same changes of state, but each step is irreversible with an efficiency of 80% compared with the corresponding mechanically reversible process. Note: The initial step can no longer be adiabatic. Calculate Q, W, ∆U, and ∆H for each step of the process and for the cycle. Take CP = (7/2)R and CV = (5/2)R.arrow_forwardNeed asaparrow_forward
- A rigid vessel of 0.075 m3 volume contains an ideal gas, CV = 5/2 R at 540 K and 1 bar. If heat in the amount of 15,800 J is transferred to the gas, determine its entropy change.arrow_forwardCarbon dioxide (molar mass 44 kg/mol) expands reversibly in a perfectly thermally insulated cylinder from 3.7 bar, 220 degrees Celsius to a volume of 0,085 m³. If the initial volume occupied was 0,02 m³, calculate the gas constant, adiabatic index,final pressure and work input. Assume nitrogen to be a perfect gas and take cv=0,63 KJ/kgKarrow_forwardIn a chemical plant, O₂ is compressed steadily from 30 °C and 1 bar to 5 bar. The flowrate of O₂ is 0.16 kg/s. During the compression, 5000 J/s amount of heat is supplied from a heat bath at 100 °C. The compression operates reversibly, with negligible change in kinetic and potential energy. Determine the work supplied to the compressor and the temperature of O₂ leaving the compressor. O₂ is assumed as an ideal gas with Cv = 1.5R.arrow_forward
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