
Concept explainers
(a)
Interpretation: The Lewis and resonating structures of given compound PCl3is to be written and valence electrons are to be counted.
Concept introduction: Lewis structure shows sharing of electrons using dots. Each
(a)

Answer to Problem 4RQ
Sum of valence electrons of all atoms=26
Lewis structure with circles:
Explanation of Solution
Sum of valence electrons of all atoms=5+7+7+7=26
Lewis structure with circles:
Phosphorus has five electrons and chlorine has seven electrons in valence shell. Thus, each chlorine atom shares one electron with central phosphorus atom to complete the octet.
From Lewis structure, octet of phosphorus and chlorine is complete.
There is no resonance in it.
(b)
Interpretation: The Lewis and resonating structures of given compound Br2is to be written and valence electrons are to be counted.
Concept introduction: Lewis structure shows sharing of electrons using dots. Each atom has number of dots equal to valence electrons. Every atom shares electrons to complete eight electrons in valence shell. Resonating structures are drawn when one structure can’t explain all the properties of molecule.
(b)

Answer to Problem 4RQ
Sum of valence electrons of all atoms=14
Lewis structure with circles:
Explanation of Solution
Sum of valence electrons of all atoms=7+7=14
Lewis structure with circles:
Bromine belongs to 17th group. So, it has seven electrons in its valence shell. It requires one electron to complete its octet thus share one electron with other bromine atom.
From Lewis structure, octet of bromine is complete.
There is no resonance in
(c)
Interpretation: The lewis and resonating structures of given compound
Concept introduction: Lewis structure shows sharing of electrons using dots. Each atom has number of dots equal to valence electrons. Every atom shares electrons to complete eight electrons in valence shell. Resonating structures are drawn when one structure can’t explain all the properties of molecule.
(c)

Answer to Problem 4RQ
Sum of valence electrons of all atoms=18
Lewis structure with circles:
Resonating structure:
Explanation of Solution
Sum of valence electrons of all atoms=6+5+6+1=18
Lewis structure with circles:
Resonating structure:
Lewis structure of nitrite ion shows nitrogen shares its one electron with oxygen atom carrying negative charge to complete its octet and two electrons with neutral oxygen atom to complete their octet.
But, experiment shows both the N-O bond lengths are equal. So, it has resonance in which negative charge is equally spread on both oxygen atoms and both N-O bond lengths lie in between single and double bond.
From Lewis structure, octet of both oxygen and nitrogen is complete.
(d)
Interpretation: The lewis and resonating structures of given compound O3 is to be written and valence electrons are to be counted.
Concept introduction: Lewis structure shows sharing of electrons using dots. Each atom has number of dots equal to valence electrons. Every atom shares electrons to complete eight electrons in valence shell. Resonating structures are drawn when one structure can’t explain all the properties of molecule.
(d)

Answer to Problem 4RQ
Sum of valence electrons of all atoms=18
Lewis structure with circles:
Resonating structure:
Explanation of Solution
Sum of valence electrons of all atoms=6+6+6=18
Lewis structure with circles:
Resonating structure:
The formula of ozone is
From Lewis structure, octet of all oxygen is complete.
(e)
Interpretation: The lewis and resonating structures of given compound is to be written and valence electrons are to be counted.
Concept introduction: Lewis structure shows sharing of electrons using dots. Each atom has number of dots equal to valence electrons. Every atom shares electrons to complete eight electrons in valence shell. Resonating structures are drawn when one structure can’t explain all the properties of molecule.
(e)

Answer to Problem 4RQ
Sum of valence electrons of all atoms=10
Lewis structure with circles:
Explanation of Solution
Sum of valence electrons of all atoms=4+4+1+1=10
Lewis structure with circles:
Carbon atom has four electrons in valence shell. It shares one electron with hydrogen atom to complete doublet of hydrogen. Now, to complete octet it shares three electrons with other carbon atom to complete octet and thus forms triple bond.
From Lewis structure, octet of all carbon is complete and doublet of hydrogen is complete.
(f)
Interpretation: The lewis and resonating structures of given compound is to be written and valence electrons are to be counted.
Concept introduction: Lewis structure shows sharing of electrons using dots. Each atom has number of dots equal to valence electrons. Every atom shares electrons to complete eight electrons in valence shell. Resonating structures are drawn when one structure can’t explain all the properties of molecule.
(f)

Answer to Problem 4RQ
Sum of valence electrons of all atoms=18
Lewis structure with circles:
Explanation of Solution
Sum of valence electrons of all atoms=4+4+1+1+1+1+1+1=18
Lewis structure with circles:
Carbon has four electrons in valence shell. So, each carbon forms one single bond with other carbon atom and three single bonds with three hydrogen atoms.
From Lewis structure, octet of all carbon is complete and doublet of hydrogen is complete.
(g)
Interpretation: The lewis and resonating structures of given compound is to be written and valence electrons are to be counted.
Concept introduction: Lewis structure shows sharing of electrons using dots. Each atom has number of dots equal to valence electrons. Every atom shares electrons to complete eight electrons in valence shell. Resonating structures are drawn when one structure can’t explain all the properties of molecule.
(g)

Answer to Problem 4RQ
Sum of valence electrons of all atoms=10
Lewis structure with circles:
Explanation of Solution
Sum of valence electrons of all atoms=1+4+5=10
Lewis structure with circles:
Lewis structure shows there is single bond between carbon and hydrogen and triple bond between carbon and nitrogen.
From Lewis structure, octet of nitrogen and carbon is complete and doublet of hydrogen is complete.
(h)
Interpretation: The lewis and resonating structures of given compound is to be written and valence electrons are to be counted.
Concept introduction: Lewis structure shows sharing of electrons using dots. Each atom has number of dots equal to valence electrons. Every atom shares electrons to complete eight electrons in valence shell. Resonating structures are drawn when one structure can’t explain all the properties of molecule.
(h)

Answer to Problem 4RQ
Sum of valence electrons of all atoms=23
Lewis structure with circles:
Resonating structure:
Explanation of Solution
Sum of valence electrons of all atoms=4+6+6+6+1=23
Lewis structure with circles:
Resonating structure:
Lewis structure of carbonate ion shows one oxygen atom is bonded to carbon by double bond and two oxygen ions are bonded by single bonded. But in actual all the C-O bond lengths in carbonate ion is same. So, resonating structures of carbonate ions are formed. In resonance hybrid two unit negative charge is equally spread on three oxygen atoms and bond length of C-O lies in between double and single bond.
Lewis structure shows octet of oxygen and carbon is complete.
Chapter 12 Solutions
World of Chemistry
- Highlight each glycosidic bond in the molecule below. Then answer the questions in the table under the drawing area. HO- HO- -0 OH OH HO NG HO- HO- OH OH OH OH NG OHarrow_forward€ + Suppose the molecule in the drawing area below were reacted with H₂ over a platinum catalyst. Edit the molecule to show what would happen to it. That is, turn it into the product of the reaction. Also, write the name of the product molecule under the drawing area. Name: ☐ H C=0 X H- OH HO- H HO- -H CH₂OH ×arrow_forwardDraw the Haworth projection of the disaccharide made by joining D-glucose and D-mannose with a ẞ(1-4) glycosidic bond. If the disaccharide has more than one anomer, you can draw any of them. Click and drag to start drawing a structure. Xarrow_forward
- Epoxides can be opened in aqueous acid or aqueous base to produce diols (molecules with two OH groups). In this question, you'll explore the mechanism of epoxide opening in aqueous acid. 2nd attempt Be sure to show all four bonds at stereocenters using hash and wedge lines. 0 0 Draw curved arrows to show how the epoxide reacts with hydronium ion. 100 +1: 1st attempt Feedback Be sure to show all four bonds at stereocenters using hash and wedge lines. See Periodic Table See Hint H A 5 F F Hr See Periodic Table See Hintarrow_forward03 Question (1 point) For the reaction below, draw both of the major organic products. Be sure to consider stereochemistry. > 1. CH₂CH₂MgBr 2. H₂O 3rd attempt Draw all four bonds at chiral centers. Draw all stereoisomers formed. Draw the structures here. e 130 AN H See Periodic Table See Hint P C Brarrow_forwardYou may wish to address the following issues in your response if they are pertinent to the reaction(s) you propose to employ:1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Please make it in detail and draw it out too in what step what happens. Thank you for helping me!arrow_forward
- 1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Everything in detail and draw out and write it.arrow_forwardCalculating the pH at equivalence of a titration 3/5 Izabella A chemist titrates 120.0 mL of a 0.7191M dimethylamine ((CH3)2NH) solution with 0.5501 M HBr solution at 25 °C. Calculate the pH at equivalence. The pk of dimethylamine is 3.27. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added. pH = ☐ ✓ 18 Ar Boarrow_forwardAlcohols can be synthesized using an acid-catalyzed hydration of an alkene. An alkene is combined with aqueous acid (e.. sulfuric acid in water). The reaction mechanism typically involves a carbocation intermediate. > 3rd attempt 3343 10 8 Draw arrows to show the reaction between the alkene and hydronium ion. that 2nd attempt Feedback 1st attempt تعمال Ju See Periodic Table See Hint F D Ju See Periodic Table See Hintarrow_forward
- Draw the simplified curved arrow mechanism for the reaction of acetone and CHgLi to give the major product. 4th attempt Π Draw the simplified curved arrow mechanism T 3rd attempt Feedback Ju See Periodic Table See Hint H -H H -I H F See Periodic Table See Hintarrow_forwardSelect the correct reagent to accomplish the first step of this reaction. Then draw a mechanism on the Grignard reagent using curved arrow notation to show how it is converted to the final product. 4th attempt Part 1 (0.5 point) Select the correct reagent to accomplish the first step of this reaction. Choose one: OA Mg in ethanol (EtOH) OB. 2 Li in THF O C. Li in THF D. Mg in THF O E Mg in H2O Part 2 (0.5 point) Br Part 1 Bri Mg CH B CH, 1 Draw intermediate here, but no arrows. © TE See Periodic Table See Hint See Hint ין Harrow_forwardSelect the product for the following reaction. HO HO PCC OH ○ OH O HO ○ HO HO HOarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





