Chapter 12, Problem 56A

(a)

Interpretation Introduction

Interpretation:

The element having more electronegativity is to be chosen.

Concept introduction:

Electronegativity tells the power of an atom to attract pair of electrons which are shared between the atoms

Eelectronegativity increases in a period and decreases in the group.

Answer to Problem 56A

  $\mathrm{O}$

Explanation of Solution

  $\mathrm{O}$ and $\mathrm{S}\mathrm{e}$ belongs to 16^th group.

Electronegativity increases in a period and decreases in the group.

Therefore, $\mathrm{O}$ is more electronegative than $\mathrm{S}\mathrm{e}$

(b)

Interpretation Introduction

Interpretation:

The element having more electronegativity is to be chosen.

Concept introduction:

Electronegativity tells the power of an atom to attract pair of electrons which are shared between the atoms

Electronegativity increases in a period and decreases in the group.

Answer to Problem 56A

  $\mathrm{L}\mathrm{i}$

Explanation of Solution

  $\mathrm{L}\mathrm{i}$ and $\mathrm{C}\mathrm{s}$ belongs to first group.

Electronegativity increases in a period and decreases in the group.

Therefore, $\mathrm{L}\mathrm{i}$ is more electronegative than $\mathrm{C}\mathrm{s}$

(c)

Interpretation Introduction

Interpretation:

The element having more electronegativity is to be chosen.

Concept introduction:

Electronegativity tells the power of an atom to attract pair of electrons which are shared between the atoms

Electronegativity increases in a period and decreases in the group.

Answer to Problem 56A

  $\mathrm{N}$

Explanation of Solution

Nitrogen belongs to 15^th group and $\mathrm{G}\mathrm{e}$ belongs to 14th group.

Electronegativity increases in a period and decreases in the group.

Therefore, $\mathrm{N}$ is more electronegative than $\mathrm{G}\mathrm{e}$