Chapter 12, Problem 41A

Interpretation Introduction

Interpretation:

The geometric structure of $B{F}_3$ is to be drawn and the bond angle is to be written.

Concept introduction:

Structure of molecule can be drawn using VSEPR theory. The total number of bonding and non-bonding pairs of electrons tells about the geometry of the molecule.

The valence electrons are the electrons present in outermost shell.

Answer to Problem 41A

Geometric structure is trigonal planar.

3 pairs of electrons are surrounding the boron in $B{F}_3$ .

The bond angle of $F-B-F$ is $120\text{'}$

Explanation of Solution

Lewis structure of $B{F}_3$is:

  

Structure shows in $B{F}_3$ central atom boron has three bond pairs and no lone pair. In total it has 3 pairs of electrons. Thus, its geometry is trigonal planar according to VSEPR theory.

Thus, 3 pairs of electrons are surrounding the nitrogen in ammonia.

A normal trigonal planar geometry has bond angle of $120\text{'}$

Conclusion

Thus, $B{F}_3$ is trigonal planar