
Concept explainers
Interpretation:
The way periodic table helps to calculate number of electrons lost by a metal is to be explained.
Concept introduction:
Ionic bonds are formed when there is complete transfer of electrons from one atom to another forming the bonds.

Answer to Problem 1RQ
Group number of metal gives this information.
Sodium belongs to group-I . So, it loses one electron to form ion in an ionic compound.
Magnesium belongs to group-II. So it loses two electrons to form ion in an ionic compound
Explanation of Solution
Periodic table helps to calculate number of electrons lost by a certain metal to form an ion in the ionic compound.
For example:
Group-I metals can loss one electron.
Group-II metals can loss two electrons.
Thus periodic table gives the information of number of electrons lost by metal.
Chapter 12 Solutions
World of Chemistry
- OH 1. NaOCH2CH3 Q 2. CH3CH2Br (1 equiv) H3O+ Select to Draw 1. NaOCH2 CH3 2. CH3Br (1 equiv) heat Select to Edit Select to Drawarrow_forwardComplete and balance the following half-reaction in acidic solution. Be sure to include the proper phases for all species within the reaction. S₂O₃²⁻(aq) → S₄O₆²⁻(aq)arrow_forwardQ Select to Edit NH3 (CH3)2CHCI (1 equiv) AICI 3 Select to Draw cat. H2SO4 SO3 (1 equiv) HO SOCl2 pyridine Select to Edit >arrow_forward
- Complete and balance the following half-reaction in basic solution. Be sure to include the proper phases for all species within the reaction. Zn(s) → Zn(OH)₄²⁻(aq)arrow_forwardb. ὋΗ CH3CH2OH H2SO4arrow_forwardFor the reaction A (g) → 3 B (g), Kp = 0.379 at 298 K. What is the value of ∆G for this reaction at 298 K when the partial pressures of A and B are 5.70 atm and 0.250 atm?arrow_forward
- 14. Calculate the concentrations of Ag+, Ag(S2O3), and Ag(S2O3)23- in a solution prepared by mixing 150.0 mL of 1.00×10-3 M AgNO3 with 200.0 mL of 5.00 M Na2S2O3 Ag+ + S20 Ag(S203)¯ K₁ = 7.4 × 108 Ag(S203)¯ + S20¯ = Ag(S203) K₂ = 3.9 x 104arrow_forwardΗΝ, cyclohexanone pH 4-5 Draw Enamine I I CH3CH2Br THF, reflux H3O+ I Drawing Draw Iminium Ionarrow_forward:0: :0: Select to Add Arrows :0: (CH3)2NH :0: ■ Select to Add Arrows :0: :0: (CH3)2NH ■ Select to Add Arrowsarrow_forward
- Draw the product of the following H action sequence. Ignore any inorganic byproducts formed. 1. (CH3CH2)2CuLi, THF 2. CH3Br Q Atoms, Bonds and Rings H Charges ㅁarrow_forwardPlease help me with this the problem is so confusingarrow_forward14 Question (1 point) Disiamylborane adds to a triple bond to give an alkenylborane. Upon oxidation with OH, H2O2, the alkenylborane will form an enol that tautomerizes to an aldehyde. In the first box below, draw the mechanism arrows for the reaction of disiamylborane with the alkyne, and in the last box draw the structure of the aldehyde. 4th attempt Feedback i > 3rd attempt OH, H2O2 i See Periodic Table See Hintarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





