(a)
Interpretation: The major product of the given reaction has to be found.
Concept Introduction:
Major product in the reaction of
General scheme:
It can be observed that the conjugate addition product has been formed by the addition of basic anion to the beta-carbon atom and that of hydrogen atom to the alpha-carbon carbon atom.
The examples for the weak bases are:
(b)
Interpretation: The major product of the given reaction has to be found.
Concept Introduction:
Major product in the reaction of
General scheme:
It can be observed that the conjugate addition product has been formed by the addition of basic anion to the beta-carbon atom and that of hydrogen atom to the alpha-carbon carbon atom.
The examples for the weak bases are:
(c)
Interpretation: The major product of the given reaction has to be found.
Concept Introduction:
Major product in the reaction of
General scheme:
It can be observed that the conjugate addition product has been formed by the addition of basic anion to the beta-carbon atom and that of hydrogen atom to the alpha-carbon carbon atom.
The examples for the weak bases are:
Major product in the reaction of
General scheme:
It can be observed that the direct addition product has been formed from the direct reaction of the strong base with the carbonyl
The examples for the strong bases are:
(d)
Interpretation: The major product of the given reaction has to be found.
Concept Introduction:
Major product in the reaction of
General scheme:
It can be observed that the conjugate addition product has been formed by the addition of basic anion to the beta-carbon atom and that of hydrogen atom to the alpha-carbon carbon atom.
The examples for the weak bases are:
Major product in the reaction of
General scheme:
It can be observed that the direct addition product has been formed from the direct reaction of the strong base with the carbonyl functional group of the
The examples for the strong bases are:

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Chapter 12 Solutions
Essential Organic Chemistry, Global Edition
- What is the name of the following compound? SiMe3arrow_forwardK Draw the starting structure that would lead to the major product shown under the provided conditions. Drawing 1. NaNH2 2. PhCH2Br 4 57°F Sunny Q Searcharrow_forward7 Draw the starting alkyl bromide that would produce this alkyne under these conditions. F Drawing 1. NaNH2, A 2. H3O+ £ 4 Temps to rise Tomorrow Q Search H2arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
