(a)
Interpretation:
The product formed in the given reaction has to be shown with the stereochemistry.
Concept Introduction:
Grignard reagent: Alkyl, vinyl, or aryl-magnesium halides are called as Grignard reagents.
The chemical formula of the Grignard reagent is
Grignard reaction with
Grignard regent reacts with ketone followed by acidic work up to form secondary or tertiary alcohol.
General scheme:
Stereocenter: In the product of a
(b)
Interpretation:
The product formed in the given reaction has to be shown with the stereochemistry.
Concept Introduction:
It reduces
General scheme:
Stereocenter: In the product of a chemical reaction, if a carbon atom has been attached with four different carbon atoms, then it is known as chiral carbon atom or stereocenter in the product. The bond of the functional group because of which a new chiral carbon is supposed to form has to be represented in solid wedge bond.
(c)
Interpretation:
The product formed in the given reaction has to be shown with the stereochemistry.
Concept Introduction:
Imine formation:
Aldehyde or ketone reacts with a primary
Example for the formation of imine is shown here:
- Imines contain
- Imines are also called as Schiff bases, named after Hugo Schiff who described their formation.
Stereocenter: In the product of a chemical reaction, if a carbon atom has been attached with four different carbon atoms, then it is known as chiral carbon atom or stereocenter in the product. The bond of the functional group because of which a new chiral carbon is supposed to form has to be represented in solid wedge bond.
(d)
Interpretation:
The product formed in the given reaction has to be shown with the stereochemistry.
Concept Introduction:
It reduces aldehydes, ketones and esters into alcohol.
Conversion of ester into alcohol:
Stereocenter: In the product of a chemical reaction, if a carbon atom has been attached with four different carbon atoms, then it is known as chiral carbon atom or stereocenter in the product. The bond of the functional group because of which a new chiral carbon is supposed to form has to be represented in solid wedge bond.
Want to see the full answer?
Check out a sample textbook solution
Chapter 12 Solutions
Essential Organic Chemistry, Global Edition
- Draw a structural formula for the major product of the reaction shown. -CH₂CH3 Br₂ H₂O • Show product stereochemistry IF the reactant alkene has both carbons of the double bond within a ring. • Do not show stereochemistry in other cases. • If the reaction produces a racemic mixture, just draw one stereoisomer.arrow_forwardDraw a structural formula for the major product of the reaction shown.arrow_forwardDraw the neutral organic starting material that will react with Br₂ to form 2-(bromomethyl)tetrahydrofuran. Draw the neutral organic starting material. [= Br₂ CH₂Cl₂arrow_forward
- Draw the alkene that would react with the reagent given to account for the product formed. CH3 HCI CH3 CHCCH, ? + Či CH3 You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one.arrow_forwardReview Topics] [References] Draw a structural formula for the major product of the reaction shown. CH;CH2 c=CHCH3 CH;CH2 Br2 H20 • Show product stereochemistry IF the reactant alkene has both carbons of the double bond within a ring. • Do not show stereochemistry in other cases. • If the reaction produces a racemic mixture, just draw one stereoisomer. Previous Next ChemDoodle Save and Ex tv ill I 11 МacBook Air DII DD F12 F11 F10 80 888 F9 F7 FB F6 F5 F4 F3 * & $ %3D 5 6. 7 8 9. 4 { P E R T Y H J K F + * COarrow_forwardFollow the arrows to predict the intermediate and product of this reaction. Include all lone pairs. Use wedges and dashes to indicate stereochemistry. Ignore inorganic byproducts.arrow_forward
- The following compounds have the same molecular formula as benzene. How many monobrominated products could each form? a. How many dibrominated products could each of the preceding compounds form? (Do not include stereoisomers.) b. How many dibrominated products could each of the compounds form if stereoisomers are included?arrow_forwardQuestion 5 pleasearrow_forwarda. The following compounds have the same molecular formula as benzene. How many monobrominated products could each form? 1. HC‚CC‚CCH2CH3 2. CH2“CHC‚CCH“CH2 b. How many dibrominated products could each of the preceding compounds form? (Do not include stereoisomers.) c. How many dibrominated products could each of the compounds form if stereoisomers are included?arrow_forward
- 08.20b 1) ВН, THF 2) H,O2, NaOH Modify the given carbon skeleton to draw the major product(s) of the given reaction. If a racemic mixture of enantiomers is expected, draw both enantiomers. Note: you can select a structure and use Copy and Paste to save drawing time. CHarrow_forwardDraw the product(s) of the following reactions. Na / NH3(1) -CEC-CH, • Consider E'Z stereochemistry of alkenes. Separate multiple products using the + sign from the drop-down menu. If no reaction occurs, draw the organic starting material.arrow_forwardGive IUPAC names for the following structures. When appropriate, abbreviate ortho (o), meta (m), and para (p), no italics, if you elect to use these terms. CH₂CH₂CHCHCHSCHCH₂ I T CH₁ CH₂ 1st structure: CH3 CH3 I 2nd structure: Submit Submit Answer Try Another Version OCH3 CH₂CCH₂ OCH3 10 item attempts remainingarrow_forward
Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning