Explanation Given: v D = 2.2 ft / s → + ∑ F x = m a x : F = W g v B 2 ρ cos θ + ↑ ∑ F y = m a y : N − W = − W g v B 2 ρ sin θ Or: N = W ( 1 − v B 2 g ρ sin θ ) Now F max = μ S N = μ S W ( 1 − v B 2 g ρ sin θ ) And for the component not to slide. F < F max Or: W g v B 2 ρ cos θ < μ S W ( 1 − v B 2 g ρ sin θ ) Or: μ S > cos θ g ρ v B 2 − sin θ We must determine the values of θ which maximize the above expression To determine (b) Value of θ for which sliding is impeding.

Vector Mechanics for Engineers: Dynamics

11th Edition

ISBN: 9780077687342

Author: Ferdinand P. Beer, E. Russell Johnston Jr., Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

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Chapter 12.1, Problem 12.62P

To determine

(a)

Minimum value of the coefficient of static friction between the component and BC.

To determine

(b)

Value of θ for which sliding is impeding.

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Chapter 12.1, Problem 12.61P

Chapter 12.1, Problem 12.63P

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(a) Minimum value of the coefficient of static friction between the component and BC.

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