Explanation Given information: Weight of block B: W B = 12 l b Weight of wedge A: W A = 30 l b Friction is negligible. Calculations: From the free body and kinetic diagram of block B: Applying force balance in y-direction: ∑ F y = m a y ; N A B − m B g = − m B a A sin 30 ∘ N A B = m B ( g − a A sin 30 ∘ ) ................ ( 2 ) Now, from the free body and the kinetic diagram of the wedge A: Applying the force balance equation along 30 o with the horizontal: m A g sin 30 ∘ + N A B sin 30 ∘ = m A a A substituting, N A B from eq To determine (b) The acceleration of B relative to A immediately after the system is released from rest.

Vector Mechanics for Engineers: Dynamics

11th Edition

ISBN: 9780077687342

Author: Ferdinand P. Beer, E. Russell Johnston Jr., Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

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Chapter 12, Problem 12.124RP

To determine

(a)

The acceleration of A immediately after the system is released from rest.

To determine

(b)

The acceleration of B relative to A immediately after the system is released from rest.

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Chapter 12, Problem 12.123RP

Chapter 12, Problem 12.125RP

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(a) The acceleration of A immediately after the system is released from rest.

Solution Summary: The author calculates the acceleration of A immediately after the system is released from rest.