![Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card](https://www.bartleby.com/isbn_cover_images/9781305717534/9781305717534_largeCoverImage.gif)
Concept explainers
(a)
Interpretation:
The total number of hydrogen atoms present in a cycloalkane that contains eight carbon atoms has to be identified.
Concept Introduction:
Organic compounds are the important basis of life. They include gasoline, coal, dyes, and clothing fibers etc. The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds. Organic compounds are found in earth also apart from living organisms. All the organic compounds contain the element carbon. Urea was synthesized in the laboratory which is an organic compound.
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and
Cycloalkanes are a class of saturated hydrocarbons that contain a ring of carbon atoms with or without alkyl substituents on it. The general molecular formula for cycloalkanes is
(a)
![Check Mark](/static/check-mark.png)
Answer to Problem 12.93EP
The total number of hydrogen atoms present is 16.
Explanation of Solution
Cycloalkanes are saturated hydrocarbons that contain only single bonds between carbon atoms with a ring structure. The general molecular formula for cycloalkane is
The total number of hydrogen atoms that will be present in the given cycloalkane is found to be sixteen.
The total number of hydrogen atoms present in the cycloalkane containing eight carbon atoms is sixteen.
(b)
Interpretation:
The total number of carbon atoms present in cycloalkane that contains twelve hydrogen atoms has to be identified.
Concept Introduction:
Organic compounds are the important basis of life. They include gasoline, coal, dyes, and clothing fibers etc. The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds. Organic compounds are found in earth also apart from living organisms. All the organic compounds contain the element carbon. Urea was synthesized in the laboratory which is an organic compound.
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and unsaturated hydrocarbons. The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon. The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.
Cycloalkanes are a class of saturated hydrocarbons that contain a ring of carbon atoms with or without alkyl substituents on it. The general molecular formula for cycloalkanes is
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 12.93EP
The total number of carbon atoms present is 6.
Explanation of Solution
Cycloalkanes are saturated hydrocarbons that contain only single bonds between carbon atoms with a ring structure. The general molecular formula for cycloalkane is
The total number of carbon atoms that will be present in the given cycloalkane is found to be six.
The total number of carbon atoms present in the alkane containing twelve hydrogen atoms is six.
(c)
Interpretation:
The total number of carbon atoms present in cycloalkane when the total atoms present in it was 15 has to be identified.
Concept Introduction:
Organic compounds are the important basis of life. They include gasoline, coal, dyes, and clothing fibers etc. The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds. Organic compounds are found in earth also apart from living organisms. All the organic compounds contain the element carbon. Urea was synthesized in the laboratory which is an organic compound.
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and unsaturated hydrocarbons. The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon. The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.
Cycloalkanes are a class of saturated hydrocarbons that contain a ring of carbon atoms with or without alkyl substituents on it. The general molecular formula for cycloalkanes is
(c)
![Check Mark](/static/check-mark.png)
Answer to Problem 12.93EP
The total number of carbon atoms present is 5.
Explanation of Solution
Cycloalkanes are saturated hydrocarbons that contain only single bonds between carbon atoms with no ring structure. The general molecular formula for cycloalkane is
The total number of carbon atoms that will be present in the given cycloalkane is found to be five.
The total number of carbon atoms present in the cycloalkane containing a total of 15 atoms is five.
(d)
Interpretation:
The total number of covalent bonds present in the cycloalkane that contains five carbon atoms has to be identified.
Concept Introduction:
Organic compounds are the important basis of life. They include gasoline, coal, dyes, and clothing fibers etc. The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds. Organic compounds are found in earth also apart from living organisms. All the organic compounds contain the element carbon. Urea was synthesized in the laboratory which is an organic compound.
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and unsaturated hydrocarbons. The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon. The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.
Cycloalkanes are a class of saturated hydrocarbons that contain a ring of carbon atoms with or without alkyl substituents on it. The general molecular formula for cycloalkanes is
(d)
![Check Mark](/static/check-mark.png)
Answer to Problem 12.93EP
The total number of covalent bonds present is 15.
Explanation of Solution
Cycloalkanes are saturated hydrocarbons that contain only single bonds between carbon atoms with ring structure. The general molecular formula for cycloalkane is
From the formula obtained for the cycloalkane, it is clear that there are ten hydrogen atoms and five carbon atoms. Each hydrogen atom will be bonded to carbon atom through a covalent bond. Each carbon atom will be bonded to other carbon atom through a covalent bond in a cylic fashion. Hence, a total of 15 covalent bonds will be present in the cycloalkane that contains five carbon atoms.
The total number of covalent bonds present in the cycloalkane that contains five carbon atoms is 15.
Want to see more full solutions like this?
Chapter 12 Solutions
Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card
- Curved arrows are used to illustrate the flow of electrons using the provided starting and product structures draw the curved electron pushing arrows for the following reaction or mechanistic steps Ether(solvent)arrow_forwardThis deals with synthetic organic chemistry. Please fill in the blanks appropriately.arrow_forwardUse the References to access important values if needed for this question. What is the IUPAC name of each of the the following? 0 CH3CHCNH₂ CH3 CH3CHCNHCH2CH3 CH3arrow_forward
- You have now performed a liquid-liquid extraction protocol in Experiment 4. In doing so, you manipulated and exploited the acid-base chemistry of one or more of the compounds in your mixture to facilitate their separation into different phases. The key to understanding how liquid- liquid extractions work is by knowing which layer a compound is in, and in what protonation state. The following liquid-liquid extraction is different from the one you performed in Experiment 4, but it uses the same type of logic. Your task is to show how to separate apart Compound A and Compound B. . Complete the following flowchart of a liquid-liquid extraction. Handwritten work is encouraged. • Draw by hand (neatly) only the appropriate organic compound(s) in the boxes. . Specify the reagent(s)/chemicals (name is fine) and concentration as required in Boxes 4 and 5. • Box 7a requires the solvent (name is fine). • Box 7b requires one inorganic compound. • You can neatly complete this assignment by hand and…arrow_forwardb) Elucidate compound D w) mt at 170 nd shows c-1 stretch at 550cm;' The compound has the ff electronic transitions: 0%o* and no a* 1H NMR Spectrum (CDCl3, 400 MHz) 3.5 3.0 2.5 2.0 1.5 1.0 0.5 ppm 13C{H} NMR Spectrum (CDCl3, 100 MHz) Solvent 80 70 60 50 40 30 20 10 0 ppm ppm ¹H-13C me-HSQC Spectrum ppm (CDCl3, 400 MHz) 5 ¹H-¹H COSY Spectrum (CDCl3, 400 MHz) 0.5 10 3.5 3.0 2.5 2.0 1.5 1.0 10 15 20 20 25 30 30 -35 -1.0 1.5 -2.0 -2.5 3.0 -3.5 0.5 ppm 3.5 3.0 2.5 2.0 1.5 1.0 0.5 ppmarrow_forwardShow work with explanation. don't give Ai generated solutionarrow_forward
- Redraw the flowchartarrow_forwardredraw the flowchart with boxes and molecules written in themarrow_forwardPart I. a) Elucidate the structure of compound A using the following information. • mass spectrum: m+ = 102, m/2=57 312=29 • IR spectrum: 1002.5 % TRANSMITTANCE Ngg 50 40 30 20 90 80 70 60 MICRONS 5 8 9 10 12 13 14 15 16 19 1740 cm M 10 0 4000 3600 3200 2800 2400 2000 1800 1600 13 • CNMR 'H -NMR Peak 8 ppm (H) Integration multiplicity a 1.5 (3H) triplet b 1.3 1.5 (3H) triplet C 2.3 1 (2H) quartet d 4.1 1 (2H) quartet & ppm (c) 10 15 28 60 177 (C=0) b) Elucidate the structure of compound B using the following information 13C/DEPT NMR 150.9 MHz IIL 1400 WAVENUMBERS (CM-1) DEPT-90 DEPT-135 85 80 75 70 65 60 55 50 45 40 35 30 25 20 ppm 1200 1000 800 600 400arrow_forward
- • Part II. a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below: • IR spectra % TRANSMITTANCE 1002.5 90 80 70 60 50 40 30 20 10 0 4000 3600 3200 2800 2400 2000 1800 1600 • Information from 'HAMR MICRONS 8 9 10 11 14 15 16 19 25 1400 WAVENUMBERS (CM-1) 1200 1000 800 600 400 peak 8 ppm Integration multiplicity a 2.1 1.5 (3H) Singlet b 3.6 1 (2H) singlet с 3.8 1.5 (3H) Singlet d 6.8 1(2H) doublet 7.1 1(2H) doublet Information from 13C-nmR Normal carbon 29ppm Dept 135 Dept -90 + NO peak NO peak 50 ppm 55 ppm + NO peak 114 ppm t 126 ppm No peak NO peak 130 ppm t + 159 ppm No peak NO peak 207 ppm по реак NO peakarrow_forwardCould you redraw these and also explain how to solve them for me pleasarrow_forwardNonearrow_forward
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage LearningIntroductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning
- Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305960060/9781305960060_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305079250/9781305079250_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337399425/9781337399425_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305081079/9781305081079_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781285853918/9781285853918_smallCoverImage.gif)