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(a)
Interpretation:
Whether or not secondary and tertiary carbon atoms are present in the structures given has to be indicated.
Concept Introduction:
In a hydrocarbon structure, each and every carbon atoms are classified as primary, secondary, tertiary, and quaternary carbon atom.
If a carbon atom in an organic molecule is directly bonded to only one another carbon atom is known as primary carbon atom.
If a carbon atom in an organic molecule is directly bonded to two other carbon atoms is known as secondary carbon atom.
If a carbon atom in an organic molecule is directly bonded to three other carbon atoms is known as tertiary carbon atom.
If a carbon atom in an organic molecule is directly bonded to four another carbon atom is known as quaternary carbon atom.
These carbon atoms are denoted by notations as,
(b)
Interpretation:
Whether or not secondary and tertiary carbon atoms are present in the structures given has to be indicated.
Concept Introduction:
In a hydrocarbon structure, each and every carbon atoms are classified as primary, secondary, tertiary, and quaternary carbon atom.
If a carbon atom in an organic molecule is directly bonded to only one another carbon atom is known as primary carbon atom.
If a carbon atom in an organic molecule is directly bonded to two other carbon atoms is known as secondary carbon atom.
If a carbon atom in an organic molecule is directly bonded to three other carbon atoms is known as tertiary carbon atom.
If a carbon atom in an organic molecule is directly bonded to four another carbon atom is known as quaternary carbon atom.
These carbon atoms are denoted by notations as,
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Chapter 12 Solutions
Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card
- Nonearrow_forward3. A molecular form of "dicarbon", C2, can be generated in gas phase. Its bond dissociation energy has been determined at 599 kJ/mol. Use molecular orbital theory to explain why energy of dissociation for C₂+ is 513 kJ/mol, and that for C2² is 818 kJ/mol. (10 points)arrow_forward9.73 g of lead(IV) chloride contains enough Cl- ions to make ____ g of magnesium chloride.arrow_forward
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- 4. Assign the following molecules to proper point groups: Pyridine N 1,3,5-triazine N Narrow_forward7. a) Under normal conditions (room temperature & atmospheric pressure) potassium assumes bcc lattice. Atomic radius for 12-coordinate K atom is listed as 235 pm. What is the radius of potassium atom under normal conditions? (3 points) b) Titanium metal crystallyzes in hcp lattice. Under proper conditions nitrogen can be absorbed into the lattice of titanium resulting in an alloy of stoichiometry TiNo.2. Is this compound likely to be a substitutional or an interstitial alloy? (Radius of Ti (12-coordinate) is 147 pm; radius of N atom is 75 pm. (3 points)arrow_forwardcan someone answer the questions and draw out the complete mechanismarrow_forward
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