Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN: 9780547587776
Author: HOLT MCDOUGAL
Publisher: HOLT MCDOUGAL
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 11.9, Problem 13E
a.
To determine
To find the probability of choosing 2 blue socks.
a.
Expert Solution
Answer to Problem 13E
The probability of choosing 2 blue socks is
Explanation of Solution
Given information:
A drawer contains 4 blue socks, 6 gray socks, and 8 black socks.
Calculation:
Let P be the probability of choosing 2 blue socks.
Total number of blue socks is 4.
Total number of socks
Therefore,
Probability of choosing blue socks in first selection is
Probability of choosing blue socks in second selection is
Probability of choosing 2 blue socks is
Hence,
The probability of choosing 2 blue socks is
b.
To determine
To find the probability of choosing 2 blue socks.
b.
Expert Solution
Answer to Problem 13E
The probability of choosing 2 gray socks is
Explanation of Solution
Given information:
A drawer contains 4 blue socks, 6 gray socks, and 8 black socks.
Calculation:
Let P be the probability of choosing 2 blue socks.
Total number of gray socks is 6.
Total number of socks
Therefore,
Probability of choosing gray socks in first selection is
Probability of choosing gray socks in second selection is
Probability of choosing 2 blue socks is
Hence,
The probability of choosing 2 gray socks is
c.
To determine
To find the probability of choosing 2 black socks.
c.
Expert Solution
Answer to Problem 13E
The probability of choosing 2 black socks is
Explanation of Solution
Given information:
A drawer contains 4 blue socks, 6 gray socks, and 8 black socks.
Calculation:
Let P be the probability of choosing 2 black socks.
Total number of black socks is 8.
Total number of socks
Therefore,
Probability of choosing black socks in first selection is
Probability of choosing black socks in second selection is
Probability of choosing 2 black socks is
Hence,
The probability of choosing 2 black socks is
d.
To determine
To find the probability of choosing same color socks.
d.
Expert Solution
Answer to Problem 13E
The probability of choosing same color socksis
Explanation of Solution
Given information:
A drawer contains 4 blue socks, 6 gray socks, and 8 black socks.
Calculation:
Let P be the probability of choosing same color socks.
The probability of choosing 2 blue socks is
The probability of choosing 2 gray socks is
The probability of choosing 2 black socks is
Hence,
The probability of choosing same color socks is
Chapter 11 Solutions
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Ch. 11.1 - Prob. 1CCh. 11.1 - Prob. 1ECh. 11.1 - Prob. 2ECh. 11.1 - Prob. 3ECh. 11.1 - Prob. 4ECh. 11.1 - Prob. 5ECh. 11.1 - Prob. 6ECh. 11.1 - Prob. 7ECh. 11.1 - Prob. 8ECh. 11.1 - Prob. 9E
Ch. 11.1 - Prob. 10ECh. 11.1 - Prob. 11ECh. 11.1 - Prob. 12ECh. 11.1 - Prob. 13ECh. 11.1 - Prob. 14ECh. 11.1 - Prob. 15ECh. 11.1 - Prob. 16ECh. 11.1 - Prob. 17ECh. 11.1 - Prob. 18ECh. 11.1 - Prob. 19ECh. 11.1 - Prob. 20ECh. 11.1 - Prob. 21ECh. 11.1 - Prob. 22ECh. 11.1 - Prob. 23ECh. 11.1 - Prob. 24ECh. 11.1 - Prob. 25ECh. 11.1 - Prob. 26ECh. 11.1 - Prob. 27ECh. 11.1 - Prob. 28ECh. 11.1 - Prob. 29ECh. 11.1 - Prob. 30ECh. 11.2 - Prob. 1CCh. 11.2 - Prob. 1ECh. 11.2 - Prob. 2ECh. 11.2 - Prob. 3ECh. 11.2 - Prob. 4ECh. 11.2 - Prob. 5ECh. 11.2 - Prob. 6ECh. 11.2 - Prob. 7ECh. 11.2 - Prob. 8ECh. 11.2 - Prob. 9ECh. 11.2 - Prob. 10ECh. 11.2 - Prob. 11ECh. 11.2 - Prob. 12ECh. 11.2 - Prob. 13ECh. 11.2 - Prob. 14ECh. 11.2 - Prob. 15ECh. 11.2 - Prob. 16ECh. 11.2 - Prob. 17ECh. 11.2 - Prob. 18ECh. 11.2 - Prob. 19ECh. 11.2 - Prob. 20ECh. 11.2 - Prob. 21ECh. 11.2 - Prob. 22ECh. 11.2 - Prob. 23ECh. 11.3 - Prob. 1CCh. 11.3 - Prob. 2CCh. 11.3 - Prob. 1ECh. 11.3 - Prob. 2ECh. 11.3 - Prob. 3ECh. 11.3 - Prob. 4ECh. 11.3 - Prob. 5ECh. 11.3 - Prob. 6ECh. 11.3 - Prob. 7ECh. 11.3 - Prob. 8ECh. 11.3 - Prob. 9ECh. 11.3 - Prob. 10ECh. 11.3 - Prob. 11ECh. 11.3 - Prob. 12ECh. 11.3 - Prob. 13ECh. 11.3 - Prob. 14ECh. 11.3 - Prob. 15ECh. 11.3 - Prob. 16ECh. 11.3 - Prob. 17ECh. 11.3 - Prob. 18ECh. 11.3 - Prob. 19ECh. 11.3 - Prob. 20ECh. 11.3 - Prob. 21ECh. 11.3 - Prob. 22ECh. 11.3 - Prob. 23ECh. 11.3 - Prob. 24ECh. 11.3 - Prob. 25ECh. 11.3 - Prob. 26ECh. 11.4 - Prob. 1CCh. 11.4 - Prob. 1ECh. 11.4 - Prob. 2ECh. 11.4 - Prob. 3ECh. 11.4 - Prob. 4ECh. 11.4 - Prob. 5ECh. 11.4 - Prob. 6ECh. 11.4 - Prob. 7ECh. 11.4 - Prob. 8ECh. 11.4 - Prob. 9ECh. 11.4 - Prob. 10ECh. 11.4 - Prob. 11ECh. 11.4 - Prob. 12ECh. 11.4 - Prob. 13ECh. 11.4 - Prob. 14ECh. 11.4 - Prob. 15ECh. 11.4 - Prob. 16ECh. 11.4 - Prob. 17ECh. 11.4 - Prob. 18ECh. 11.4 - Prob. 19ECh. 11.4 - Prob. 20ECh. 11.4 - Prob. 21ECh. 11.4 - Prob. 22ECh. 11.4 - Prob. 23ECh. 11.4 - Prob. 24ECh. 11.4 - Prob. 25ECh. 11.4 - Prob. 26ECh. 11.4 - Prob. 27ECh. 11.5 - Prob. 1CCh. 11.5 - Prob. 1ECh. 11.5 - Prob. 2ECh. 11.5 - Prob. 3ECh. 11.5 - Prob. 4ECh. 11.5 - Prob. 5ECh. 11.5 - Prob. 6ECh. 11.5 - Prob. 7ECh. 11.5 - Prob. 8ECh. 11.5 - Prob. 9ECh. 11.5 - Prob. 10ECh. 11.5 - Prob. 11ECh. 11.5 - Prob. 12ECh. 11.5 - Prob. 13ECh. 11.5 - Prob. 14ECh. 11.5 - Prob. 15ECh. 11.5 - Prob. 16ECh. 11.5 - Prob. 17ECh. 11.5 - Prob. 18ECh. 11.5 - Prob. 19ECh. 11.5 - Prob. 20ECh. 11.5 - Prob. 21ECh. 11.5 - Prob. 22ECh. 11.5 - Prob. 23ECh. 11.5 - Prob. 24ECh. 11.5 - Prob. 25ECh. 11.5 - Prob. 26ECh. 11.6 - Prob. 1CCh. 11.6 - Prob. 2CCh. 11.6 - Prob. 3CCh. 11.6 - Prob. 4CCh. 11.6 - Prob. 5CCh. 11.6 - Prob. 6CCh. 11.6 - Prob. 7CCh. 11.6 - Prob. 8CCh. 11.6 - Prob. 1ECh. 11.6 - Prob. 2ECh. 11.6 - Prob. 3ECh. 11.6 - Prob. 4ECh. 11.6 - Prob. 5ECh. 11.6 - Prob. 6ECh. 11.6 - Prob. 7ECh. 11.6 - Prob. 8ECh. 11.6 - Prob. 9ECh. 11.6 - Prob. 10ECh. 11.6 - Prob. 11ECh. 11.6 - Prob. 12ECh. 11.6 - Prob. 13ECh. 11.6 - Prob. 14ECh. 11.6 - Prob. 15ECh. 11.6 - Prob. 16ECh. 11.6 - Prob. 17ECh. 11.6 - Prob. 18ECh. 11.6 - Prob. 19ECh. 11.6 - Prob. 20ECh. 11.6 - Prob. 21ECh. 11.6 - Prob. 22ECh. 11.6 - Prob. 23ECh. 11.6 - Prob. 24ECh. 11.6 - Prob. 25ECh. 11.6 - Prob. 26ECh. 11.6 - Prob. 27ECh. 11.6 - Prob. 28ECh. 11.6 - Prob. 29ECh. 11.6 - Prob. 30ECh. 11.6 - Prob. 31ECh. 11.6 - Prob. 32ECh. 11.6 - Prob. 33ECh. 11.6 - Prob. 34ECh. 11.6 - Prob. 35ECh. 11.6 - Prob. 36ECh. 11.6 - Prob. 37ECh. 11.6 - Prob. 38ECh. 11.6 - Prob. 39ECh. 11.6 - Prob. 40ECh. 11.6 - Prob. 41ECh. 11.6 - Prob. 42ECh. 11.6 - Prob. 43ECh. 11.6 - Prob. 44ECh. 11.6 - Prob. 45ECh. 11.6 - Prob. 46ECh. 11.6 - Prob. 47ECh. 11.6 - Prob. 48ECh. 11.6 - Prob. 49ECh. 11.6 - Prob. 50ECh. 11.7 - Prob. 1CCh. 11.7 - Prob. 2CCh. 11.7 - Prob. 3CCh. 11.7 - Prob. 4CCh. 11.7 - Prob. 5CCh. 11.7 - Prob. 6CCh. 11.7 - Prob. 7CCh. 11.7 - Prob. 1ECh. 11.7 - Prob. 2ECh. 11.7 - Prob. 3ECh. 11.7 - Prob. 4ECh. 11.7 - Prob. 5ECh. 11.7 - Prob. 6ECh. 11.7 - Prob. 7ECh. 11.7 - Prob. 8ECh. 11.7 - Prob. 9ECh. 11.7 - Prob. 10ECh. 11.7 - Prob. 11ECh. 11.7 - Prob. 12ECh. 11.7 - Prob. 13ECh. 11.7 - Prob. 14ECh. 11.7 - Prob. 15ECh. 11.7 - Prob. 16ECh. 11.7 - Prob. 17ECh. 11.7 - Prob. 18ECh. 11.7 - Prob. 19ECh. 11.7 - Prob. 20ECh. 11.7 - Prob. 21ECh. 11.7 - Prob. 22ECh. 11.7 - Prob. 23ECh. 11.7 - Prob. 24ECh. 11.7 - Prob. 25ECh. 11.7 - Prob. 26ECh. 11.7 - Prob. 27ECh. 11.7 - Prob. 28ECh. 11.7 - Prob. 29ECh. 11.7 - Prob. 30ECh. 11.7 - Prob. 31ECh. 11.7 - Prob. 32ECh. 11.7 - Prob. 33ECh. 11.7 - Prob. 34ECh. 11.7 - Prob. 35ECh. 11.7 - Prob. 36ECh. 11.7 - Prob. 37ECh. 11.7 - Prob. 38ECh. 11.7 - Prob. 39ECh. 11.7 - Prob. 40ECh. 11.7 - Prob. 41ECh. 11.8 - Prob. 1CCh. 11.8 - Prob. 2CCh. 11.8 - Prob. 1ECh. 11.8 - Prob. 2ECh. 11.8 - Prob. 3ECh. 11.8 - Prob. 4ECh. 11.8 - Prob. 5ECh. 11.8 - Prob. 6ECh. 11.8 - Prob. 7ECh. 11.8 - Prob. 8ECh. 11.8 - Prob. 9ECh. 11.8 - Prob. 10ECh. 11.8 - Prob. 11ECh. 11.8 - Prob. 12ECh. 11.8 - Prob. 13ECh. 11.8 - Prob. 14ECh. 11.8 - Prob. 15ECh. 11.8 - Prob. 16ECh. 11.8 - Prob. 17ECh. 11.8 - Prob. 18ECh. 11.8 - Prob. 19ECh. 11.8 - Prob. 20ECh. 11.8 - Prob. 21ECh. 11.8 - Prob. 22ECh. 11.8 - Prob. 23ECh. 11.8 - Prob. 24ECh. 11.8 - Prob. 25ECh. 11.8 - Prob. 26ECh. 11.8 - Prob. 27ECh. 11.8 - Prob. 28ECh. 11.8 - Prob. 29ECh. 11.8 - Prob. 30ECh. 11.8 - Prob. 31ECh. 11.8 - Prob. 32ECh. 11.8 - Prob. 33ECh. 11.8 - Prob. 34ECh. 11.8 - Prob. 35ECh. 11.8 - Prob. 36ECh. 11.8 - Prob. 37ECh. 11.8 - Prob. 38ECh. 11.8 - Prob. 39ECh. 11.8 - Prob. 40ECh. 11.9 - Prob. 1CCh. 11.9 - Prob. 2CCh. 11.9 - Prob. 3CCh. 11.9 - Prob. 4CCh. 11.9 - Prob. 1ECh. 11.9 - Prob. 2ECh. 11.9 - Prob. 3ECh. 11.9 - Prob. 4ECh. 11.9 - Prob. 5ECh. 11.9 - Prob. 6ECh. 11.9 - Prob. 7ECh. 11.9 - Prob. 8ECh. 11.9 - Prob. 9ECh. 11.9 - Prob. 10ECh. 11.9 - Prob. 11ECh. 11.9 - Prob. 12ECh. 11.9 - Prob. 13ECh. 11.9 - Prob. 14ECh. 11.9 - Prob. 15ECh. 11.9 - Prob. 16ECh. 11.9 - Prob. 17ECh. 11.9 - Prob. 18ECh. 11.9 - Prob. 20ECh. 11.9 - Prob. 21ECh. 11.9 - Prob. 22ECh. 11.9 - Prob. 23ECh. 11.9 - Prob. 24ECh. 11.9 - Prob. 25ECh. 11.9 - Prob. 26ECh. 11 - Prob. 1PSQCh. 11 - Prob. 2PSQCh. 11 - Prob. 3PSQCh. 11 - Prob. 4PSQCh. 11 - Prob. 5PSQCh. 11 - Prob. 6PSQCh. 11 - Prob. 7PSQCh. 11 - Prob. 8PSQCh. 11 - Prob. 9PSQCh. 11 - Prob. 10PSQCh. 11 - Prob. 11PSQCh. 11 - Prob. 1MCQCh. 11 - Prob. 2MCQCh. 11 - Prob. 3MCQCh. 11 - Prob. 4MCQCh. 11 - Prob. 5MCQCh. 11 - Prob. 6MCQCh. 11 - Prob. 7MCQCh. 11 - Prob. 1CRCh. 11 - Prob. 2CRCh. 11 - Prob. 3CRCh. 11 - Prob. 4CRCh. 11 - Prob. 5CRCh. 11 - Prob. 6CRCh. 11 - Prob. 7CRCh. 11 - Prob. 8CRCh. 11 - Prob. 9CRCh. 11 - Prob. 10CRCh. 11 - Prob. 11CRCh. 11 - Prob. 12CRCh. 11 - Prob. 13CRCh. 11 - Prob. 14CRCh. 11 - Prob. 15CRCh. 11 - Prob. 1CTCh. 11 - Prob. 2CTCh. 11 - Prob. 3CTCh. 11 - Prob. 4CTCh. 11 - Prob. 5CTCh. 11 - Prob. 6CTCh. 11 - Prob. 7CTCh. 11 - Prob. 8CTCh. 11 - Prob. 9CTCh. 11 - Prob. 10CTCh. 11 - Prob. 11CTCh. 11 - Prob. 12CTCh. 11 - Prob. 13CTCh. 11 - Prob. 14CTCh. 11 - Prob. 15CTCh. 11 - Prob. 16CTCh. 11 - Prob. 17CTCh. 11 - Prob. 18CTCh. 11 - Prob. 19CTCh. 11 - Prob. 1CSTCh. 11 - Prob. 2CSTCh. 11 - Prob. 3CSTCh. 11 - Prob. 4CSTCh. 11 - Prob. 5CSTCh. 11 - Prob. 6CSTCh. 11 - Prob. 7CSTCh. 11 - Prob. 8CSTCh. 11 - Prob. 9CSTCh. 11 - Prob. 10CST
Additional Math Textbook Solutions
Find more solutions based on key concepts
Whether the ‘Physicians Committee for Responsible Medicine’ has the potential to create a bias in a statistical...
Elementary Statistics
In Exercises 7–10, use the same population of {4, 5, 9} that was used in Examples 2 and 5. As in Examples 2 and...
Elementary Statistics (13th Edition)
Fill in each blank so that the resulting statement is true. The quadratic function f(x)=a(xh)2+k,a0, is in ____...
Algebra and Trigonometry (6th Edition)
Angular size A boat sails directly toward a 150-meter skyscraper that stands on the edge of a harbor. The angul...
Calculus: Early Transcendentals (2nd Edition)
Fill in each blank so that the resulting statement is true.
1. A combination of numbers, variables, and opera...
College Algebra (7th Edition)
The table by using the given graph of h.
Calculus for Business, Economics, Life Sciences, and Social Sciences (14th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.Similar questions
- Let 2 A = 4 3 -4 0 1 (a) Show that v = eigenvalue. () is an eigenvector of A and find the corresponding (b) Find the characteristic polynomial of A and factorise it. Hint: the answer to (a) may be useful. (c) Determine all eigenvalues of A and find bases for the corresponding eigenspaces. (d) Find an invertible matrix P and a diagonal matrix D such that P-¹AP = D.arrow_forward(c) Let 6 0 0 A = -10 4 8 5 1 2 (i) Find the characteristic polynomial of A and factorise it. (ii) Determine all eigenvalues of A and find bases for the corresponding eigenspaces. (iii) Is A diagonalisable? Give reasons for your answer.arrow_forwardmost 2, and let Let P2 denote the vector space of polynomials of degree at D: P2➡ P2 be the transformation that sends a polynomial p(t) = at² + bt+c in P2 to its derivative p'(t) 2at+b, that is, D(p) = p'. (a) Prove that D is a linear transformation. (b) Find a basis for the kernel ker(D) of the linear transformation D and compute its nullity. (c) Find a basis for the image im(D) of the linear transformation D and compute its rank. (d) Verify that the Rank-Nullity Theorem holds for the linear transformation D. (e) Find the matrix representation of D in the standard basis (1,t, t2) of P2.arrow_forward
- (c) Let A = -1 3 -4 12 3 3 -9 (i) Find bases for row(A), col(A) and N(A). (ii) Determine the rank and nullity of A, and verify that the Rank-Nullity Theorem holds for the above matrix A.arrow_forward-(0)-(0)-(0) X1 = x2 = x3 = 1 (a) Show that the vectors X1, X2, X3 form a basis for R³. y= (b) Find the coordinate vector [y] B of y in the basis B = (x1, x2, x3).arrow_forwardLet A 1 - 13 (1³ ³) 3). (i) Compute A2, A3, A4. (ii) Show that A is invertible and find A-¹.arrow_forward
- Let H = {(a a12 a21 a22, | a1 + a2 = 0} . € R²x²: a11 + a22 (i) Show that H is a subspace of R2×2 (ii) Find a basis of H and determine dim H.arrow_forward2 5 A=1 2 -2 b=2 3 1 -1 3 (a) Calculate det(A). (b) Using (a), deduce that the system Ax = b where x = (x1, x2, x3) is consistent and determine x2 using Cramer's rule.arrow_forwardConsider the least squares problem Ax = b, where 12 -09-0 A 1 3 1 4 and b = (a) Write down the corresponding normal equations. (b) Determine the set of least squares solutions to the problem.arrow_forward
- The function f(x) is represented by the equation, f(x) = x³ + 8x² + x − 42. Part A: Does f(x) have zeros located at -7, 2, -3? Explain without using technology and show all work. Part B: Describe the end behavior of f(x) without using technology.arrow_forwardHow does the graph of f(x) = (x − 9)4 – 3 compare to the parent function g(x) = x²?arrow_forwardFind the x-intercepts and the y-intercept of the graph of f(x) = (x − 5)(x − 2)(x − 1) without using technology. Show all work.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Algebra and Trigonometry (6th Edition)AlgebraISBN:9780134463216Author:Robert F. BlitzerPublisher:PEARSON
Contemporary Abstract AlgebraAlgebraISBN:9781305657960Author:Joseph GallianPublisher:Cengage Learning
Linear Algebra: A Modern IntroductionAlgebraISBN:9781285463247Author:David PoolePublisher:Cengage Learning
Algebra And Trigonometry (11th Edition)AlgebraISBN:9780135163078Author:Michael SullivanPublisher:PEARSON
Introduction to Linear Algebra, Fifth EditionAlgebraISBN:9780980232776Author:Gilbert StrangPublisher:Wellesley-Cambridge Press
College Algebra (Collegiate Math)AlgebraISBN:9780077836344Author:Julie Miller, Donna GerkenPublisher:McGraw-Hill Education
Algebra and Trigonometry (6th Edition)
Algebra
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:PEARSON
Contemporary Abstract Algebra
Algebra
ISBN:9781305657960
Author:Joseph Gallian
Publisher:Cengage Learning
Linear Algebra: A Modern Introduction
Algebra
ISBN:9781285463247
Author:David Poole
Publisher:Cengage Learning
Algebra And Trigonometry (11th Edition)
Algebra
ISBN:9780135163078
Author:Michael Sullivan
Publisher:PEARSON
Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:9780980232776
Author:Gilbert Strang
Publisher:Wellesley-Cambridge Press
College Algebra (Collegiate Math)
Algebra
ISBN:9780077836344
Author:Julie Miller, Donna Gerken
Publisher:McGraw-Hill Education
Mod-01 Lec-01 Discrete probability distributions (Part 1); Author: nptelhrd;https://www.youtube.com/watch?v=6x1pL9Yov1k;License: Standard YouTube License, CC-BY
Discrete Probability Distributions; Author: Learn Something;https://www.youtube.com/watch?v=m9U4UelWLFs;License: Standard YouTube License, CC-BY
Probability Distribution Functions (PMF, PDF, CDF); Author: zedstatistics;https://www.youtube.com/watch?v=YXLVjCKVP7U;License: Standard YouTube License, CC-BY
Discrete Distributions: Binomial, Poisson and Hypergeometric | Statistics for Data Science; Author: Dr. Bharatendra Rai;https://www.youtube.com/watch?v=lHhyy4JMigg;License: Standard Youtube License