Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN: 9780547587776
Author: HOLT MCDOUGAL
Publisher: HOLT MCDOUGAL
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Chapter 11.9, Problem 13E

a.

To determine

To find the probability of choosing 2 blue socks.

a.

Expert Solution
Check Mark

Answer to Problem 13E

The probability of choosing 2 blue socks is 251 .

Explanation of Solution

Given information:

A drawer contains 4 blue socks, 6 gray socks, and 8 black socks.

Calculation:

Let P be the probability of choosing 2 blue socks.

Total number of blue socks is 4.

Total number of socks =4+6+8=18

Therefore,

Probability of choosing blue socks in first selection is 418 .

Probability of choosing blue socks in second selection is 317 .

Probability of choosing 2 blue socks is 418×317=251

Hence,

The probability of choosing 2 blue socks is 251 .

b.

To determine

To find the probability of choosing 2 blue socks.

b.

Expert Solution
Check Mark

Answer to Problem 13E

The probability of choosing 2 gray socks is 551 .

Explanation of Solution

Given information:

A drawer contains 4 blue socks, 6 gray socks, and 8 black socks.

Calculation:

Let P be the probability of choosing 2 blue socks.

Total number of gray socks is 6.

Total number of socks =4+6+8=18

Therefore,

Probability of choosing gray socks in first selection is 618 .

Probability of choosing gray socks in second selection is 517 .

Probability of choosing 2 blue socks is 618×517=551

Hence,

The probability of choosing 2 gray socks is 551 .

c.

To determine

To find the probability of choosing 2 black socks.

c.

Expert Solution
Check Mark

Answer to Problem 13E

The probability of choosing 2 black socks is 251 .

Explanation of Solution

Given information:

A drawer contains 4 blue socks, 6 gray socks, and 8 black socks.

Calculation:

Let P be the probability of choosing 2 black socks.

Total number of black socks is 8.

Total number of socks =4+6+8=18

Therefore,

Probability of choosing black socks in first selection is

  818 .

Probability of choosing black socks in second selection is 717 .

Probability of choosing 2 black socks is

  818×717=28153

Hence,

The probability of choosing 2 black socks is 28153 .

d.

To determine

To find the probability of choosing same color socks.

d.

Expert Solution
Check Mark

Answer to Problem 13E

The probability of choosing same color socksis

  49153 .

Explanation of Solution

Given information:

A drawer contains 4 blue socks, 6 gray socks, and 8 black socks.

Calculation:

Let P be the probability of choosing same color socks.

The probability of choosing 2 blue socks is 251 .

The probability of choosing 2 gray socks is

  551 .

The probability of choosing 2 black socks is 28153 .

Hence,

The probability of choosing same color socks is 251+551+28153=6+15+28153=49153 .

Chapter 11 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 11.1 - Prob. 10ECh. 11.1 - Prob. 11ECh. 11.1 - Prob. 12ECh. 11.1 - Prob. 13ECh. 11.1 - Prob. 14ECh. 11.1 - Prob. 15ECh. 11.1 - Prob. 16ECh. 11.1 - Prob. 17ECh. 11.1 - Prob. 18ECh. 11.1 - Prob. 19ECh. 11.1 - Prob. 20ECh. 11.1 - Prob. 21ECh. 11.1 - Prob. 22ECh. 11.1 - Prob. 23ECh. 11.1 - Prob. 24ECh. 11.1 - Prob. 25ECh. 11.1 - Prob. 26ECh. 11.1 - Prob. 27ECh. 11.1 - Prob. 28ECh. 11.1 - Prob. 29ECh. 11.1 - Prob. 30ECh. 11.2 - Prob. 1CCh. 11.2 - Prob. 1ECh. 11.2 - Prob. 2ECh. 11.2 - Prob. 3ECh. 11.2 - Prob. 4ECh. 11.2 - Prob. 5ECh. 11.2 - Prob. 6ECh. 11.2 - Prob. 7ECh. 11.2 - Prob. 8ECh. 11.2 - Prob. 9ECh. 11.2 - Prob. 10ECh. 11.2 - Prob. 11ECh. 11.2 - Prob. 12ECh. 11.2 - Prob. 13ECh. 11.2 - Prob. 14ECh. 11.2 - Prob. 15ECh. 11.2 - Prob. 16ECh. 11.2 - Prob. 17ECh. 11.2 - Prob. 18ECh. 11.2 - Prob. 19ECh. 11.2 - Prob. 20ECh. 11.2 - Prob. 21ECh. 11.2 - Prob. 22ECh. 11.2 - Prob. 23ECh. 11.3 - Prob. 1CCh. 11.3 - Prob. 2CCh. 11.3 - Prob. 1ECh. 11.3 - Prob. 2ECh. 11.3 - Prob. 3ECh. 11.3 - Prob. 4ECh. 11.3 - Prob. 5ECh. 11.3 - Prob. 6ECh. 11.3 - Prob. 7ECh. 11.3 - Prob. 8ECh. 11.3 - Prob. 9ECh. 11.3 - Prob. 10ECh. 11.3 - Prob. 11ECh. 11.3 - Prob. 12ECh. 11.3 - Prob. 13ECh. 11.3 - Prob. 14ECh. 11.3 - Prob. 15ECh. 11.3 - Prob. 16ECh. 11.3 - Prob. 17ECh. 11.3 - Prob. 18ECh. 11.3 - Prob. 19ECh. 11.3 - Prob. 20ECh. 11.3 - Prob. 21ECh. 11.3 - Prob. 22ECh. 11.3 - Prob. 23ECh. 11.3 - Prob. 24ECh. 11.3 - Prob. 25ECh. 11.3 - Prob. 26ECh. 11.4 - Prob. 1CCh. 11.4 - Prob. 1ECh. 11.4 - Prob. 2ECh. 11.4 - Prob. 3ECh. 11.4 - Prob. 4ECh. 11.4 - Prob. 5ECh. 11.4 - Prob. 6ECh. 11.4 - Prob. 7ECh. 11.4 - Prob. 8ECh. 11.4 - Prob. 9ECh. 11.4 - Prob. 10ECh. 11.4 - Prob. 11ECh. 11.4 - Prob. 12ECh. 11.4 - Prob. 13ECh. 11.4 - Prob. 14ECh. 11.4 - Prob. 15ECh. 11.4 - Prob. 16ECh. 11.4 - Prob. 17ECh. 11.4 - Prob. 18ECh. 11.4 - Prob. 19ECh. 11.4 - Prob. 20ECh. 11.4 - Prob. 21ECh. 11.4 - Prob. 22ECh. 11.4 - Prob. 23ECh. 11.4 - Prob. 24ECh. 11.4 - Prob. 25ECh. 11.4 - Prob. 26ECh. 11.4 - Prob. 27ECh. 11.5 - Prob. 1CCh. 11.5 - Prob. 1ECh. 11.5 - Prob. 2ECh. 11.5 - Prob. 3ECh. 11.5 - Prob. 4ECh. 11.5 - Prob. 5ECh. 11.5 - Prob. 6ECh. 11.5 - Prob. 7ECh. 11.5 - Prob. 8ECh. 11.5 - Prob. 9ECh. 11.5 - Prob. 10ECh. 11.5 - Prob. 11ECh. 11.5 - Prob. 12ECh. 11.5 - Prob. 13ECh. 11.5 - Prob. 14ECh. 11.5 - Prob. 15ECh. 11.5 - Prob. 16ECh. 11.5 - Prob. 17ECh. 11.5 - Prob. 18ECh. 11.5 - Prob. 19ECh. 11.5 - Prob. 20ECh. 11.5 - Prob. 21ECh. 11.5 - Prob. 22ECh. 11.5 - Prob. 23ECh. 11.5 - Prob. 24ECh. 11.5 - Prob. 25ECh. 11.5 - Prob. 26ECh. 11.6 - Prob. 1CCh. 11.6 - Prob. 2CCh. 11.6 - Prob. 3CCh. 11.6 - Prob. 4CCh. 11.6 - Prob. 5CCh. 11.6 - Prob. 6CCh. 11.6 - Prob. 7CCh. 11.6 - Prob. 8CCh. 11.6 - Prob. 1ECh. 11.6 - Prob. 2ECh. 11.6 - Prob. 3ECh. 11.6 - Prob. 4ECh. 11.6 - Prob. 5ECh. 11.6 - Prob. 6ECh. 11.6 - Prob. 7ECh. 11.6 - Prob. 8ECh. 11.6 - Prob. 9ECh. 11.6 - Prob. 10ECh. 11.6 - Prob. 11ECh. 11.6 - Prob. 12ECh. 11.6 - Prob. 13ECh. 11.6 - Prob. 14ECh. 11.6 - Prob. 15ECh. 11.6 - Prob. 16ECh. 11.6 - Prob. 17ECh. 11.6 - Prob. 18ECh. 11.6 - Prob. 19ECh. 11.6 - Prob. 20ECh. 11.6 - Prob. 21ECh. 11.6 - Prob. 22ECh. 11.6 - Prob. 23ECh. 11.6 - Prob. 24ECh. 11.6 - Prob. 25ECh. 11.6 - Prob. 26ECh. 11.6 - Prob. 27ECh. 11.6 - Prob. 28ECh. 11.6 - Prob. 29ECh. 11.6 - Prob. 30ECh. 11.6 - Prob. 31ECh. 11.6 - Prob. 32ECh. 11.6 - Prob. 33ECh. 11.6 - Prob. 34ECh. 11.6 - Prob. 35ECh. 11.6 - Prob. 36ECh. 11.6 - Prob. 37ECh. 11.6 - Prob. 38ECh. 11.6 - Prob. 39ECh. 11.6 - Prob. 40ECh. 11.6 - Prob. 41ECh. 11.6 - Prob. 42ECh. 11.6 - Prob. 43ECh. 11.6 - Prob. 44ECh. 11.6 - Prob. 45ECh. 11.6 - Prob. 46ECh. 11.6 - Prob. 47ECh. 11.6 - Prob. 48ECh. 11.6 - Prob. 49ECh. 11.6 - Prob. 50ECh. 11.7 - Prob. 1CCh. 11.7 - Prob. 2CCh. 11.7 - Prob. 3CCh. 11.7 - Prob. 4CCh. 11.7 - Prob. 5CCh. 11.7 - Prob. 6CCh. 11.7 - Prob. 7CCh. 11.7 - Prob. 1ECh. 11.7 - Prob. 2ECh. 11.7 - Prob. 3ECh. 11.7 - Prob. 4ECh. 11.7 - Prob. 5ECh. 11.7 - Prob. 6ECh. 11.7 - Prob. 7ECh. 11.7 - Prob. 8ECh. 11.7 - Prob. 9ECh. 11.7 - Prob. 10ECh. 11.7 - Prob. 11ECh. 11.7 - Prob. 12ECh. 11.7 - Prob. 13ECh. 11.7 - Prob. 14ECh. 11.7 - Prob. 15ECh. 11.7 - Prob. 16ECh. 11.7 - Prob. 17ECh. 11.7 - Prob. 18ECh. 11.7 - Prob. 19ECh. 11.7 - Prob. 20ECh. 11.7 - Prob. 21ECh. 11.7 - Prob. 22ECh. 11.7 - Prob. 23ECh. 11.7 - Prob. 24ECh. 11.7 - Prob. 25ECh. 11.7 - Prob. 26ECh. 11.7 - Prob. 27ECh. 11.7 - Prob. 28ECh. 11.7 - Prob. 29ECh. 11.7 - Prob. 30ECh. 11.7 - Prob. 31ECh. 11.7 - Prob. 32ECh. 11.7 - Prob. 33ECh. 11.7 - Prob. 34ECh. 11.7 - Prob. 35ECh. 11.7 - Prob. 36ECh. 11.7 - Prob. 37ECh. 11.7 - Prob. 38ECh. 11.7 - Prob. 39ECh. 11.7 - Prob. 40ECh. 11.7 - Prob. 41ECh. 11.8 - Prob. 1CCh. 11.8 - Prob. 2CCh. 11.8 - Prob. 1ECh. 11.8 - Prob. 2ECh. 11.8 - Prob. 3ECh. 11.8 - Prob. 4ECh. 11.8 - Prob. 5ECh. 11.8 - Prob. 6ECh. 11.8 - Prob. 7ECh. 11.8 - Prob. 8ECh. 11.8 - Prob. 9ECh. 11.8 - Prob. 10ECh. 11.8 - Prob. 11ECh. 11.8 - Prob. 12ECh. 11.8 - Prob. 13ECh. 11.8 - Prob. 14ECh. 11.8 - Prob. 15ECh. 11.8 - Prob. 16ECh. 11.8 - Prob. 17ECh. 11.8 - Prob. 18ECh. 11.8 - Prob. 19ECh. 11.8 - Prob. 20ECh. 11.8 - Prob. 21ECh. 11.8 - Prob. 22ECh. 11.8 - Prob. 23ECh. 11.8 - Prob. 24ECh. 11.8 - Prob. 25ECh. 11.8 - Prob. 26ECh. 11.8 - Prob. 27ECh. 11.8 - Prob. 28ECh. 11.8 - Prob. 29ECh. 11.8 - Prob. 30ECh. 11.8 - Prob. 31ECh. 11.8 - Prob. 32ECh. 11.8 - Prob. 33ECh. 11.8 - Prob. 34ECh. 11.8 - Prob. 35ECh. 11.8 - Prob. 36ECh. 11.8 - Prob. 37ECh. 11.8 - Prob. 38ECh. 11.8 - Prob. 39ECh. 11.8 - Prob. 40ECh. 11.9 - Prob. 1CCh. 11.9 - Prob. 2CCh. 11.9 - Prob. 3CCh. 11.9 - Prob. 4CCh. 11.9 - Prob. 1ECh. 11.9 - Prob. 2ECh. 11.9 - Prob. 3ECh. 11.9 - Prob. 4ECh. 11.9 - Prob. 5ECh. 11.9 - Prob. 6ECh. 11.9 - Prob. 7ECh. 11.9 - Prob. 8ECh. 11.9 - Prob. 9ECh. 11.9 - Prob. 10ECh. 11.9 - Prob. 11ECh. 11.9 - Prob. 12ECh. 11.9 - Prob. 13ECh. 11.9 - Prob. 14ECh. 11.9 - Prob. 15ECh. 11.9 - Prob. 16ECh. 11.9 - Prob. 17ECh. 11.9 - Prob. 18ECh. 11.9 - Prob. 20ECh. 11.9 - Prob. 21ECh. 11.9 - Prob. 22ECh. 11.9 - Prob. 23ECh. 11.9 - Prob. 24ECh. 11.9 - Prob. 25ECh. 11.9 - Prob. 26ECh. 11 - Prob. 1PSQCh. 11 - Prob. 2PSQCh. 11 - Prob. 3PSQCh. 11 - Prob. 4PSQCh. 11 - Prob. 5PSQCh. 11 - Prob. 6PSQCh. 11 - Prob. 7PSQCh. 11 - Prob. 8PSQCh. 11 - Prob. 9PSQCh. 11 - Prob. 10PSQCh. 11 - Prob. 11PSQCh. 11 - Prob. 1MCQCh. 11 - Prob. 2MCQCh. 11 - Prob. 3MCQCh. 11 - Prob. 4MCQCh. 11 - Prob. 5MCQCh. 11 - Prob. 6MCQCh. 11 - Prob. 7MCQCh. 11 - Prob. 1CRCh. 11 - Prob. 2CRCh. 11 - Prob. 3CRCh. 11 - Prob. 4CRCh. 11 - Prob. 5CRCh. 11 - Prob. 6CRCh. 11 - Prob. 7CRCh. 11 - Prob. 8CRCh. 11 - Prob. 9CRCh. 11 - Prob. 10CRCh. 11 - Prob. 11CRCh. 11 - Prob. 12CRCh. 11 - Prob. 13CRCh. 11 - Prob. 14CRCh. 11 - Prob. 15CRCh. 11 - Prob. 1CTCh. 11 - Prob. 2CTCh. 11 - Prob. 3CTCh. 11 - Prob. 4CTCh. 11 - Prob. 5CTCh. 11 - Prob. 6CTCh. 11 - Prob. 7CTCh. 11 - Prob. 8CTCh. 11 - Prob. 9CTCh. 11 - Prob. 10CTCh. 11 - Prob. 11CTCh. 11 - Prob. 12CTCh. 11 - Prob. 13CTCh. 11 - Prob. 14CTCh. 11 - Prob. 15CTCh. 11 - Prob. 16CTCh. 11 - Prob. 17CTCh. 11 - Prob. 18CTCh. 11 - Prob. 19CTCh. 11 - Prob. 1CSTCh. 11 - Prob. 2CSTCh. 11 - Prob. 3CSTCh. 11 - Prob. 4CSTCh. 11 - Prob. 5CSTCh. 11 - Prob. 6CSTCh. 11 - Prob. 7CSTCh. 11 - Prob. 8CSTCh. 11 - Prob. 9CSTCh. 11 - Prob. 10CST
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