Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN: 9780547587776
Author: HOLT MCDOUGAL
Publisher: HOLT MCDOUGAL
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 11, Problem 5CR
To determine
To make a box-and-whisker plot.
Expert Solution & Answer
Answer to Problem 5CR
The box-and-whisker plot is:
Explanation of Solution
Given information:
The ages of people (in years) are:
Calculation:
At first, arrange all data in ascending order,
Lower extreme
Lower quartile
Median
Upper quartile
Upper extreme
Hence,
The box-and-whisker plot is:
Chapter 11 Solutions
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Ch. 11.1 - Prob. 1CCh. 11.1 - Prob. 1ECh. 11.1 - Prob. 2ECh. 11.1 - Prob. 3ECh. 11.1 - Prob. 4ECh. 11.1 - Prob. 5ECh. 11.1 - Prob. 6ECh. 11.1 - Prob. 7ECh. 11.1 - Prob. 8ECh. 11.1 - Prob. 9E
Ch. 11.1 - Prob. 10ECh. 11.1 - Prob. 11ECh. 11.1 - Prob. 12ECh. 11.1 - Prob. 13ECh. 11.1 - Prob. 14ECh. 11.1 - Prob. 15ECh. 11.1 - Prob. 16ECh. 11.1 - Prob. 17ECh. 11.1 - Prob. 18ECh. 11.1 - Prob. 19ECh. 11.1 - Prob. 20ECh. 11.1 - Prob. 21ECh. 11.1 - Prob. 22ECh. 11.1 - Prob. 23ECh. 11.1 - Prob. 24ECh. 11.1 - Prob. 25ECh. 11.1 - Prob. 26ECh. 11.1 - Prob. 27ECh. 11.1 - Prob. 28ECh. 11.1 - Prob. 29ECh. 11.1 - Prob. 30ECh. 11.2 - Prob. 1CCh. 11.2 - Prob. 1ECh. 11.2 - Prob. 2ECh. 11.2 - Prob. 3ECh. 11.2 - Prob. 4ECh. 11.2 - Prob. 5ECh. 11.2 - Prob. 6ECh. 11.2 - Prob. 7ECh. 11.2 - Prob. 8ECh. 11.2 - Prob. 9ECh. 11.2 - Prob. 10ECh. 11.2 - Prob. 11ECh. 11.2 - Prob. 12ECh. 11.2 - Prob. 13ECh. 11.2 - Prob. 14ECh. 11.2 - Prob. 15ECh. 11.2 - Prob. 16ECh. 11.2 - Prob. 17ECh. 11.2 - Prob. 18ECh. 11.2 - Prob. 19ECh. 11.2 - Prob. 20ECh. 11.2 - Prob. 21ECh. 11.2 - Prob. 22ECh. 11.2 - Prob. 23ECh. 11.3 - Prob. 1CCh. 11.3 - Prob. 2CCh. 11.3 - Prob. 1ECh. 11.3 - Prob. 2ECh. 11.3 - Prob. 3ECh. 11.3 - Prob. 4ECh. 11.3 - Prob. 5ECh. 11.3 - Prob. 6ECh. 11.3 - Prob. 7ECh. 11.3 - Prob. 8ECh. 11.3 - Prob. 9ECh. 11.3 - Prob. 10ECh. 11.3 - Prob. 11ECh. 11.3 - Prob. 12ECh. 11.3 - Prob. 13ECh. 11.3 - Prob. 14ECh. 11.3 - Prob. 15ECh. 11.3 - Prob. 16ECh. 11.3 - Prob. 17ECh. 11.3 - Prob. 18ECh. 11.3 - Prob. 19ECh. 11.3 - Prob. 20ECh. 11.3 - Prob. 21ECh. 11.3 - Prob. 22ECh. 11.3 - Prob. 23ECh. 11.3 - Prob. 24ECh. 11.3 - Prob. 25ECh. 11.3 - Prob. 26ECh. 11.4 - Prob. 1CCh. 11.4 - Prob. 1ECh. 11.4 - Prob. 2ECh. 11.4 - Prob. 3ECh. 11.4 - Prob. 4ECh. 11.4 - Prob. 5ECh. 11.4 - Prob. 6ECh. 11.4 - Prob. 7ECh. 11.4 - Prob. 8ECh. 11.4 - Prob. 9ECh. 11.4 - Prob. 10ECh. 11.4 - Prob. 11ECh. 11.4 - Prob. 12ECh. 11.4 - Prob. 13ECh. 11.4 - Prob. 14ECh. 11.4 - Prob. 15ECh. 11.4 - Prob. 16ECh. 11.4 - Prob. 17ECh. 11.4 - Prob. 18ECh. 11.4 - Prob. 19ECh. 11.4 - Prob. 20ECh. 11.4 - Prob. 21ECh. 11.4 - Prob. 22ECh. 11.4 - Prob. 23ECh. 11.4 - Prob. 24ECh. 11.4 - Prob. 25ECh. 11.4 - Prob. 26ECh. 11.4 - Prob. 27ECh. 11.5 - Prob. 1CCh. 11.5 - Prob. 1ECh. 11.5 - Prob. 2ECh. 11.5 - Prob. 3ECh. 11.5 - Prob. 4ECh. 11.5 - Prob. 5ECh. 11.5 - Prob. 6ECh. 11.5 - Prob. 7ECh. 11.5 - Prob. 8ECh. 11.5 - Prob. 9ECh. 11.5 - Prob. 10ECh. 11.5 - Prob. 11ECh. 11.5 - Prob. 12ECh. 11.5 - Prob. 13ECh. 11.5 - Prob. 14ECh. 11.5 - Prob. 15ECh. 11.5 - Prob. 16ECh. 11.5 - Prob. 17ECh. 11.5 - Prob. 18ECh. 11.5 - Prob. 19ECh. 11.5 - Prob. 20ECh. 11.5 - Prob. 21ECh. 11.5 - Prob. 22ECh. 11.5 - Prob. 23ECh. 11.5 - Prob. 24ECh. 11.5 - Prob. 25ECh. 11.5 - Prob. 26ECh. 11.6 - Prob. 1CCh. 11.6 - Prob. 2CCh. 11.6 - Prob. 3CCh. 11.6 - Prob. 4CCh. 11.6 - Prob. 5CCh. 11.6 - Prob. 6CCh. 11.6 - Prob. 7CCh. 11.6 - Prob. 8CCh. 11.6 - Prob. 1ECh. 11.6 - Prob. 2ECh. 11.6 - Prob. 3ECh. 11.6 - Prob. 4ECh. 11.6 - Prob. 5ECh. 11.6 - Prob. 6ECh. 11.6 - Prob. 7ECh. 11.6 - Prob. 8ECh. 11.6 - Prob. 9ECh. 11.6 - Prob. 10ECh. 11.6 - Prob. 11ECh. 11.6 - Prob. 12ECh. 11.6 - Prob. 13ECh. 11.6 - Prob. 14ECh. 11.6 - Prob. 15ECh. 11.6 - Prob. 16ECh. 11.6 - Prob. 17ECh. 11.6 - Prob. 18ECh. 11.6 - Prob. 19ECh. 11.6 - Prob. 20ECh. 11.6 - Prob. 21ECh. 11.6 - Prob. 22ECh. 11.6 - Prob. 23ECh. 11.6 - Prob. 24ECh. 11.6 - Prob. 25ECh. 11.6 - Prob. 26ECh. 11.6 - Prob. 27ECh. 11.6 - Prob. 28ECh. 11.6 - Prob. 29ECh. 11.6 - Prob. 30ECh. 11.6 - Prob. 31ECh. 11.6 - Prob. 32ECh. 11.6 - Prob. 33ECh. 11.6 - Prob. 34ECh. 11.6 - Prob. 35ECh. 11.6 - Prob. 36ECh. 11.6 - Prob. 37ECh. 11.6 - Prob. 38ECh. 11.6 - Prob. 39ECh. 11.6 - Prob. 40ECh. 11.6 - Prob. 41ECh. 11.6 - Prob. 42ECh. 11.6 - Prob. 43ECh. 11.6 - Prob. 44ECh. 11.6 - Prob. 45ECh. 11.6 - Prob. 46ECh. 11.6 - Prob. 47ECh. 11.6 - Prob. 48ECh. 11.6 - Prob. 49ECh. 11.6 - Prob. 50ECh. 11.7 - Prob. 1CCh. 11.7 - Prob. 2CCh. 11.7 - Prob. 3CCh. 11.7 - Prob. 4CCh. 11.7 - Prob. 5CCh. 11.7 - Prob. 6CCh. 11.7 - Prob. 7CCh. 11.7 - Prob. 1ECh. 11.7 - Prob. 2ECh. 11.7 - Prob. 3ECh. 11.7 - Prob. 4ECh. 11.7 - Prob. 5ECh. 11.7 - Prob. 6ECh. 11.7 - Prob. 7ECh. 11.7 - Prob. 8ECh. 11.7 - Prob. 9ECh. 11.7 - Prob. 10ECh. 11.7 - Prob. 11ECh. 11.7 - Prob. 12ECh. 11.7 - Prob. 13ECh. 11.7 - Prob. 14ECh. 11.7 - Prob. 15ECh. 11.7 - Prob. 16ECh. 11.7 - Prob. 17ECh. 11.7 - Prob. 18ECh. 11.7 - Prob. 19ECh. 11.7 - Prob. 20ECh. 11.7 - Prob. 21ECh. 11.7 - Prob. 22ECh. 11.7 - Prob. 23ECh. 11.7 - Prob. 24ECh. 11.7 - Prob. 25ECh. 11.7 - Prob. 26ECh. 11.7 - Prob. 27ECh. 11.7 - Prob. 28ECh. 11.7 - Prob. 29ECh. 11.7 - Prob. 30ECh. 11.7 - Prob. 31ECh. 11.7 - Prob. 32ECh. 11.7 - Prob. 33ECh. 11.7 - Prob. 34ECh. 11.7 - Prob. 35ECh. 11.7 - Prob. 36ECh. 11.7 - Prob. 37ECh. 11.7 - Prob. 38ECh. 11.7 - Prob. 39ECh. 11.7 - Prob. 40ECh. 11.7 - Prob. 41ECh. 11.8 - Prob. 1CCh. 11.8 - Prob. 2CCh. 11.8 - Prob. 1ECh. 11.8 - Prob. 2ECh. 11.8 - Prob. 3ECh. 11.8 - Prob. 4ECh. 11.8 - Prob. 5ECh. 11.8 - Prob. 6ECh. 11.8 - Prob. 7ECh. 11.8 - Prob. 8ECh. 11.8 - Prob. 9ECh. 11.8 - Prob. 10ECh. 11.8 - Prob. 11ECh. 11.8 - Prob. 12ECh. 11.8 - Prob. 13ECh. 11.8 - Prob. 14ECh. 11.8 - Prob. 15ECh. 11.8 - Prob. 16ECh. 11.8 - Prob. 17ECh. 11.8 - Prob. 18ECh. 11.8 - Prob. 19ECh. 11.8 - Prob. 20ECh. 11.8 - Prob. 21ECh. 11.8 - Prob. 22ECh. 11.8 - Prob. 23ECh. 11.8 - Prob. 24ECh. 11.8 - Prob. 25ECh. 11.8 - Prob. 26ECh. 11.8 - Prob. 27ECh. 11.8 - Prob. 28ECh. 11.8 - Prob. 29ECh. 11.8 - Prob. 30ECh. 11.8 - Prob. 31ECh. 11.8 - Prob. 32ECh. 11.8 - Prob. 33ECh. 11.8 - Prob. 34ECh. 11.8 - Prob. 35ECh. 11.8 - Prob. 36ECh. 11.8 - Prob. 37ECh. 11.8 - Prob. 38ECh. 11.8 - Prob. 39ECh. 11.8 - Prob. 40ECh. 11.9 - Prob. 1CCh. 11.9 - Prob. 2CCh. 11.9 - Prob. 3CCh. 11.9 - Prob. 4CCh. 11.9 - Prob. 1ECh. 11.9 - Prob. 2ECh. 11.9 - Prob. 3ECh. 11.9 - Prob. 4ECh. 11.9 - Prob. 5ECh. 11.9 - Prob. 6ECh. 11.9 - Prob. 7ECh. 11.9 - Prob. 8ECh. 11.9 - Prob. 9ECh. 11.9 - Prob. 10ECh. 11.9 - Prob. 11ECh. 11.9 - Prob. 12ECh. 11.9 - Prob. 13ECh. 11.9 - Prob. 14ECh. 11.9 - Prob. 15ECh. 11.9 - Prob. 16ECh. 11.9 - Prob. 17ECh. 11.9 - Prob. 18ECh. 11.9 - Prob. 20ECh. 11.9 - Prob. 21ECh. 11.9 - Prob. 22ECh. 11.9 - Prob. 23ECh. 11.9 - Prob. 24ECh. 11.9 - Prob. 25ECh. 11.9 - Prob. 26ECh. 11 - Prob. 1PSQCh. 11 - Prob. 2PSQCh. 11 - Prob. 3PSQCh. 11 - Prob. 4PSQCh. 11 - Prob. 5PSQCh. 11 - Prob. 6PSQCh. 11 - Prob. 7PSQCh. 11 - Prob. 8PSQCh. 11 - Prob. 9PSQCh. 11 - Prob. 10PSQCh. 11 - Prob. 11PSQCh. 11 - Prob. 1MCQCh. 11 - Prob. 2MCQCh. 11 - Prob. 3MCQCh. 11 - Prob. 4MCQCh. 11 - Prob. 5MCQCh. 11 - Prob. 6MCQCh. 11 - Prob. 7MCQCh. 11 - Prob. 1CRCh. 11 - Prob. 2CRCh. 11 - Prob. 3CRCh. 11 - Prob. 4CRCh. 11 - Prob. 5CRCh. 11 - Prob. 6CRCh. 11 - Prob. 7CRCh. 11 - Prob. 8CRCh. 11 - Prob. 9CRCh. 11 - Prob. 10CRCh. 11 - Prob. 11CRCh. 11 - Prob. 12CRCh. 11 - Prob. 13CRCh. 11 - Prob. 14CRCh. 11 - Prob. 15CRCh. 11 - Prob. 1CTCh. 11 - Prob. 2CTCh. 11 - Prob. 3CTCh. 11 - Prob. 4CTCh. 11 - Prob. 5CTCh. 11 - Prob. 6CTCh. 11 - Prob. 7CTCh. 11 - Prob. 8CTCh. 11 - Prob. 9CTCh. 11 - Prob. 10CTCh. 11 - Prob. 11CTCh. 11 - Prob. 12CTCh. 11 - Prob. 13CTCh. 11 - Prob. 14CTCh. 11 - Prob. 15CTCh. 11 - Prob. 16CTCh. 11 - Prob. 17CTCh. 11 - Prob. 18CTCh. 11 - Prob. 19CTCh. 11 - Prob. 1CSTCh. 11 - Prob. 2CSTCh. 11 - Prob. 3CSTCh. 11 - Prob. 4CSTCh. 11 - Prob. 5CSTCh. 11 - Prob. 6CSTCh. 11 - Prob. 7CSTCh. 11 - Prob. 8CSTCh. 11 - Prob. 9CSTCh. 11 - Prob. 10CST
Additional Math Textbook Solutions
Find more solutions based on key concepts
The probability of greenapples chosen is to be estimated.
Pre-Algebra Student Edition
Birth Length The mean birth length for U.S. children born at full term (after 40 weeks) is 52.2 centimeters (ab...
Introductory Statistics
Read about basic ideas of statistics in Common Core Standards for grades 3-5, and discuss why students at these...
A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)
Derivatives Evaluate the derivatives of the following functions. 19. f(x) = cos1 (1/x)
Calculus: Early Transcendentals (2nd Edition)
1. combination of numbers, variables, and operation symbols is called an algebraic______.
Algebra and Trigonometry (6th Edition)
At what points are the functions in Exercise continuous?
University Calculus: Early Transcendentals (4th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.Similar questions
- 3. Write a system of linear equations in slope intercept form that has exactly one solution at the point (3, 4), such that one line has positive slope (but not 1) and the other line has negative slope (but not "1). Also write your system of equations with both equations written in standard form with out any fractions 8- 7 8 5 4 3 -2- + -8-7-6-5-4-3-2-1 1 2 3 -1 2 - ° 4 -5 - -8arrow_forward2. Write a system of linear equations in slope-intercept form has exactly one solution at the point (3, 4), such that both lines have negative slope (but neither one has slope of 1). Also write your system of equations with both equations written in standard form without any fractions. B 0 5 4 3 -2 1 -8-7-6-5-4-3-2 -1 12 3 -1 2 -3 -5 6 -7 -8arrow_forward4. Write a system of linear equations in slope-intercept form that has no solution, such that (3, 4), and (3,8) are solutions to the first equation, and (0, 4) is a solution to the second equation. Also write your system of equations with both equations written in standard form with out any fractions B 0 5 4 3 -2 + -8-7-6-5-4-3-2 -1 |- 1 2 3 -1 2 -3 4 -5 6 -7arrow_forward
- Show how you can solve the system of equations by manipulating the algebra tiles while maintaining the balances. On this side of the page, use the addition (elimination) method. Keep track of what you did at each step by writing down the corresponding equivalent equations, as well as what you did to go from one equation to the next. 1. x + 2y = 5 x-2y=1 2. 2x+y=2 x-2y= 6arrow_forwarde) x24 1) Which of these are equivalent to x³? For each expression that is equivalent to x², prove it by using the definition of exponents. For each that is not equivalent to x³, give an example using a specific value for x that shows that it represents a different number. a) (x5) d) f) 10-2 b) (x²) *|*arrow_forwardNow show how you can solve the system of equations by manipulating the algebra tiles while maintaining the balances, using the substitution method. Keep track of what you did at each step by writing down the corresponding equivalent equations, as well as what you did to go from one equation to the next. Δ 1. x + 2y = 5 x-2y=1 2. 2x + y = 2 x-2y= 6arrow_forward
- 1. Write a system of two linear equations in slope-intercept form that has exactly one solution at the point (3, 4), such that both lines have positive slope (but neither one has slope of 1) Also write your system of equations with both equations written in standard form without any fractions. 8- 7 8 5 4 3 -2- + -8-7-6-5-4-3-2-1 1 2 3 -1 2 - 4 -5 -7 -8arrow_forwardThe original idea for creating this applet comes from Steve Phelps' Graph the Line applet. Directions: 1) Examine the equation shown on the right side of the screen. 2) Reposition the 2 big points so that the line is the graph of the displayed equation. 3) Click the "Check Answer" checkbox to check. If you're correct, the app will inform you. If you're not, you'll know this as well. If you're not correct, keep trying until you position the gray line correctly. 4) After correctly graphing the line, click the "Generate New Line" button.arrow_forwardProblem 1 & 2 answers 1. One diagonal has 11 squares, then total square in total for two diagonal line is 11 + 11 - 1 = 21 . 2. Each part has 5 squares.(except middle)Multiply by 4: 5 × 4 = 20.Add the middle square: 20 + 1 = 21.arrow_forward
- 2. Now Figure out a different way you could determine how many squares there are in the figure, again without counting them all one-by-one. Briefly describe this other method:arrow_forward1. Without counting all of the squares one by one, determine how many squares there are in the figure shown. Briefly describe your method.arrow_forward54, and 68 e Problem (10 point. in standard form (a + bi): 2+i √√3-2i ksgiving Problem (2 ion to reveal Mr. Erdman's favoriarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Algebra and Trigonometry (6th Edition)AlgebraISBN:9780134463216Author:Robert F. BlitzerPublisher:PEARSON
Contemporary Abstract AlgebraAlgebraISBN:9781305657960Author:Joseph GallianPublisher:Cengage Learning
Linear Algebra: A Modern IntroductionAlgebraISBN:9781285463247Author:David PoolePublisher:Cengage Learning
Algebra And Trigonometry (11th Edition)AlgebraISBN:9780135163078Author:Michael SullivanPublisher:PEARSON
Introduction to Linear Algebra, Fifth EditionAlgebraISBN:9780980232776Author:Gilbert StrangPublisher:Wellesley-Cambridge Press
College Algebra (Collegiate Math)AlgebraISBN:9780077836344Author:Julie Miller, Donna GerkenPublisher:McGraw-Hill Education
Algebra and Trigonometry (6th Edition)
Algebra
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:PEARSON
Contemporary Abstract Algebra
Algebra
ISBN:9781305657960
Author:Joseph Gallian
Publisher:Cengage Learning
Linear Algebra: A Modern Introduction
Algebra
ISBN:9781285463247
Author:David Poole
Publisher:Cengage Learning
Algebra And Trigonometry (11th Edition)
Algebra
ISBN:9780135163078
Author:Michael Sullivan
Publisher:PEARSON
Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:9780980232776
Author:Gilbert Strang
Publisher:Wellesley-Cambridge Press
College Algebra (Collegiate Math)
Algebra
ISBN:9780077836344
Author:Julie Miller, Donna Gerken
Publisher:McGraw-Hill Education
The Shape of Data: Distributions: Crash Course Statistics #7; Author: CrashCourse;https://www.youtube.com/watch?v=bPFNxD3Yg6U;License: Standard YouTube License, CC-BY
Shape, Center, and Spread - Module 20.2 (Part 1); Author: Mrmathblog;https://www.youtube.com/watch?v=COaid7O_Gag;License: Standard YouTube License, CC-BY
Shape, Center and Spread; Author: Emily Murdock;https://www.youtube.com/watch?v=_YyW0DSCzpM;License: Standard Youtube License