Concept explainers
To find the number of ways of selection of three numbers from 3,4,6,8 and 9 so that at least one of the numbers is greater than 6 is 9.
Answer to Problem 33E
The number of ways of selection of three numbers from 3,4,6,8 and 9 so that at least one of the numbers is greater than 6 is 9.
Explanation of Solution
Given information:
The numbers are 3,4,6,8 and 9.
Calculation:
Total number of numbers is 5.
Total number of numbers which is greater than 6 is 2 (8 and 9).
Therefore,
The three-digit number which include at least one number which is greater than 6 are as follows:
Hence,
The number of ways of selection of three numbers from 3,4,6,8 and 9 so that at least one of the numbers is greater than 6 is 9.
Chapter 11 Solutions
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
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