a) C 5 H 12 Interpretation: The skeletal structures of all compounds possible with molecular formula C 5 H 12 is to be proposed. Concept introduction: In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH 3 ; a two-way intersection is a carbon atom with two hydrogen atoms, CH 2 ; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown. To determine: The skeletal structures of all compounds possible with molecular formula C 5 H 12 .

Question

5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3

Answer 1

Question

Chapter 1.12, Problem 16P

Interpretation Introduction

a) C₅H₁₂

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₅H₁₂ is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₅H₁₂.

Interpretation Introduction

b) C₂H₇N

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₂H₇N is to be proposed.
Concept interpretation:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₂H₇N.

Interpretation Introduction

c) C₃H₆O

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₃H₆O is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₃H₆O.

Interpretation Introduction

d) C₄H₉Cl

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₄H₉Cl is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₄H₉Cl.

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5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3

Show work. don't give Ai generated solution. How many carbons and hydrogens are in the structure?

13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. cleavage Bond A •CH3 + 26.← Cleavage 2°C. + Bond C +3°C• CH3 2C Cleavage E 2°C. 26. weakest bond Intact molecule Strongest 3°C 20. Gund Largest argest a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. C Weakest bond A Produces Most Bond Strongest Bond Strongest Gund produces least stable radicals Weakest Stable radical b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 13°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. • CH3 methyl radical Formed in Gund A Cleavage c.…

Answer 2

Question

Chapter 1.12, Problem 16P

Interpretation Introduction

a) C₅H₁₂

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₅H₁₂ is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₅H₁₂.

Interpretation Introduction

b) C₂H₇N

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₂H₇N is to be proposed.
Concept interpretation:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₂H₇N.

Interpretation Introduction

c) C₃H₆O

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₃H₆O is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₃H₆O.

Interpretation Introduction

d) C₄H₉Cl

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₄H₉Cl is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₄H₉Cl.

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Answer 3

Question

Chapter 1.12, Problem 16P

Interpretation Introduction

a) C₅H₁₂

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₅H₁₂ is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₅H₁₂.

Interpretation Introduction

b) C₂H₇N

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₂H₇N is to be proposed.
Concept interpretation:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₂H₇N.

Interpretation Introduction

c) C₃H₆O

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₃H₆O is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₃H₆O.

Interpretation Introduction

d) C₄H₉Cl

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₄H₉Cl is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₄H₉Cl.

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Answer 4

Question

Chapter 1.12, Problem 16P

Interpretation Introduction

a) C₅H₁₂

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₅H₁₂ is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₅H₁₂.

Interpretation Introduction

b) C₂H₇N

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₂H₇N is to be proposed.
Concept interpretation:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₂H₇N.

Interpretation Introduction

c) C₃H₆O

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₃H₆O is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₃H₆O.

Interpretation Introduction

d) C₄H₉Cl

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₄H₉Cl is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₄H₉Cl.

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Answer 5

Chapter 1.12, Problem 16P

Interpretation Introduction

a) C₅H₁₂

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₅H₁₂ is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₅H₁₂.

Interpretation Introduction

b) C₂H₇N

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₂H₇N is to be proposed.
Concept interpretation:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₂H₇N.

Interpretation Introduction

c) C₃H₆O

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₃H₆O is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₃H₆O.

Interpretation Introduction

d) C₄H₉Cl

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₄H₉Cl is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₄H₉Cl.

Answer 6

Chapter 1.12, Problem 16P

Interpretation Introduction

a) C₅H₁₂

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₅H₁₂ is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₅H₁₂.

Answer 7

Chapter 1.12, Problem 16P

Interpretation Introduction

a) C₅H₁₂

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₅H₁₂ is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₅H₁₂.

Answer 8

Interpretation Introduction

b) C₂H₇N

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₂H₇N is to be proposed.
Concept interpretation:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₂H₇N.

Answer 9

Interpretation Introduction

b) C₂H₇N

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₂H₇N is to be proposed.
Concept interpretation:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₂H₇N.

Answer 10

Interpretation Introduction

c) C₃H₆O

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₃H₆O is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₃H₆O.

Answer 11

Interpretation Introduction

c) C₃H₆O

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₃H₆O is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₃H₆O.

Answer 12

Interpretation Introduction

d) C₄H₉Cl

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₄H₉Cl is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₄H₉Cl.

Answer 13

Interpretation Introduction

d) C₄H₉Cl

Interpretation:
The skeletal structures of all compounds possible with molecular formula C₄H₉Cl is to be proposed.
Concept introduction:
In skeletal structures the carbon atoms are not usually shown. Instead a carbon is assumed to be at each intersection of two lines and at the end of each line. The hydrogen atoms bonded to carbons are also not shown. The correct number of hydrogen atoms for each carbon atom is assigned keeping in mind that carbon has a valence of 4. The end of a line represents a carbon atom with three hydrogen atoms, CH₃; a two-way intersection is a carbon atom with two hydrogen atoms, CH₂; a three way intersection is a carbon with one hydrogen, CH; a four way intersection is a carbon with no attached hydrogen. Atoms other than carbon and hydrogen are shown.
To determine:
The skeletal structures of all compounds possible with molecular formula C₄H₉Cl.

Answer 14

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Answer 19

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Answer 25

Ch. 1.3 - Give the ground-state electron configuration for...Ch. 1.3 - How many electrons does each of the following...Ch. 1.4 - Prob. 3P Ch. 1.4 - Convert the following representation of ethane,...Ch. 1.4 - What are likely formulas for the following...Ch. 1.4 - Prob. 6P Ch. 1.4 - Prob. 7P Ch. 1.7 - Draw a line-bond structure for propane, CH3CH2CH3....Ch. 1.7 - Convert the following molecular model of hexane, a...Ch. 1.8 - Draw a line-bond structure for propene, CH3CH=CH2....

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