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Interpretation: The geometry of each carbon atoms in benzene and that of the entire molecule have to be predicted
Concept Introduction: According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule.
The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved.
Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the atom will be determined by counting the steric number followed by the hybridization state of that atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the atom has sp3 hybridization and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the atom has sp2 hybridization and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the atom has sp hybridization and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: The geometry of each carbon atoms in benzene and also that of the entire molecule
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Chapter 1 Solutions
Organic Chemistry, Binder Ready Version
- 1A H 2A Li Be Use the References to access important values if needed for this question. 8A 3A 4A 5A 6A 7A He B C N O F Ne Na Mg 3B 4B 5B 6B 7B 8B-1B 2B Al Si P 1B 2B Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe * Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Ac Rf Ha ****** Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr Analyze the following reaction by looking at the electron configurations given below each box. Put a number and a symbol in each box to show the number and kind of the corresponding atom or ion. Use the smallest integers possible. cation anion + + Shell 1: 2 Shell 2: 8 Shell 3: 1 Shell 1 : 2 Shell 2 : 6 Shell 1 : 2 Shell 2: 8 Shell 1: 2 Shell 2: 8arrow_forwardNonearrow_forwardIV. Show the detailed synthesis strategy for the following compounds. a. CH3CH2CH2CH2Br CH3CH2CCH2CH2CH3arrow_forward
- Do the electrons on the OH participate in resonance with the ring through a p orbital? How many pi electrons are in the ring, 4 (from the two double bonds) or 6 (including the electrons on the O)?arrow_forwardPredict and draw the product of the following organic reaction:arrow_forwardNonearrow_forward
- Redraw the molecule below as a skeletal ("line") structure. Be sure to use wedge and dash bonds if necessary to accurately represent the direction of the bonds to ring substituents. Cl. Br Click and drag to start drawing a structure. : ☐ ☑ Parrow_forwardK m Choose the best reagents to complete the following reaction. L ZI 0 Problem 4 of 11 A 1. NaOH 2. CH3CH2CH2NH2 1. HCI B OH 2. CH3CH2CH2NH2 DII F1 F2 F3 F4 F5 A F6 C CH3CH2CH2NH2 1. SOCl2 D 2. CH3CH2CH2NH2 1. CH3CH2CH2NH2 E 2. SOCl2 Done PrtScn Home End FA FQ 510 * PgUp M Submit PgDn F11arrow_forwardNonearrow_forward
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