Organic Chemistry, Binder Ready Version
Organic Chemistry, Binder Ready Version
2nd Edition
ISBN: 9781118454312
Author: David R. Klein
Publisher: WILEY
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Chapter 1.9, Problem 22PTS
Interpretation Introduction

Interpretation:

The hybridization state of each carbon in the given compounds is needed to be determined.

Concept introduction:

The atomic orbitals mix together to form a hybrid orbital which is suitable for forming bonds between the atoms to form a compound.  This mixing of hybrid orbitals is known as hybridization.  The hybridization determines the geometry of the particular atom in the compound.  Shortly to say

sp3hybridized =Four sigma (single) bonds

sp2hybridized =Three sigma (single) and one pi bonds (double)

sp hybridized =Two sigma (single) and two pi bonds (double)

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6. Consider the following exothermic reaction below. 2Cu2+(aq) +41 (aq)2Cul(s) + 12(aq) a. If Cul is added, there will be a shift left/shift right/no shift (circle one). b. If Cu2+ is added, there will be a shift left/shift right/no shift (circle one). c. If a solution of AgNO3 is added, there will be a shift left/shift right/no shift (circle one). d. If the solvent hexane (C6H14) is added, there will be a shift left/shift right/no shift (circle one). Hint: one of the reaction species is more soluble in hexane than in water. e. If the reaction is cooled, there will be a shift left/shift right/no shift (circle one). f. Which of the changes above will change the equilibrium constant, K?
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