Organic Chemistry, Binder Ready Version
2nd Edition
ISBN: 9781118454312
Author: David R. Klein
Publisher: WILEY
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Question
Chapter 1.9, Problem 7LTS
Interpretation Introduction
Interpretation: For the given compound, the hybridization state of each carbon atoms has to be identified.
Concept Introduction:
Hybridization is the process of mixing of atomic orbitals which are almost equal energy. As a result, hybridized orbitals which are same energy are produced. Number of atomic orbitals is equal to number of hybridized orbitals.
σ-bond is formed by head-on overlapping between two atomic orbitals which are mostly by electrons in the s-orbital. π-bond is formed by side-to-side overlap of atomic orbitals which are mostly by electrons in the p-orbital.
In sp3 hybridization, carbon atom has four σ-covalent bonds. It has the bond angle of 109.5º. In sp2 hybridization, carbon atom has three σ-covalent bonds and one π-bond. It has the bond angle of 120º. In sp hybridization, carbon atom has two σ-covalent bonds and two π-bonds. It has the bond angle of 180º.
Hybridization of a particular atom is depending on the number and type of bonds involved by it.
To find: Get the hybridization state of each carbon atoms in the given compound
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Chapter 1 Solutions
Organic Chemistry, Binder Ready Version
Ch. 1.2 - Prob. 1LTSCh. 1.2 - Prob. 1PTSCh. 1.2 - Prob. 2ATSCh. 1.2 - Prob. 3ATSCh. 1.2 - Prob. 4ATSCh. 1.3 - Prob. 2LTSCh. 1.3 - Prob. 5PTSCh. 1.3 - Prob. 6ATSCh. 1.3 - Prob. 7ATSCh. 1.3 - Prob. 8ATS
Ch. 1.3 - Prob. 9ATSCh. 1.3 - Prob. 3LTSCh. 1.3 - Prob. 10PTSCh. 1.3 - Prob. 11ATSCh. 1.3 - Prob. 12ATSCh. 1.4 - Prob. 4LTSCh. 1.4 - Prob. 13PTSCh. 1.4 - Prob. 14ATSCh. 1.5 - Prob. 5LTSCh. 1.5 - Prob. 15PTSCh. 1.5 - Prob. 16ATSCh. 1.6 - Prob. 6LTSCh. 1.6 - Prob. 17PTSCh. 1.6 - Prob. 18ATSCh. 1.9 - Prob. 19CCCh. 1.9 - Prob. 20CCCh. 1.9 - Prob. 21CCCh. 1.9 - Prob. 7LTSCh. 1.9 - Prob. 22PTSCh. 1.9 - Prob. 23ATSCh. 1.9 - Prob. 24CCCh. 1.10 - Prob. 8LTSCh. 1.10 - Prob. 25PTSCh. 1.10 - Prob. 26PTSCh. 1.10 - Prob. 27ATSCh. 1.10 - Prob. 28ATSCh. 1.11 - Prob. 9LTSCh. 1.11 - Prob. 29PTSCh. 1.11 - Prob. 30ATSCh. 1.11 - Prob. 31ATSCh. 1.12 - Prob. 10LTSCh. 1.12 - Prob. 32PTSCh. 1.12 - Prob. 33ATSCh. 1 - Prob. 34PPCh. 1 - Prob. 35PPCh. 1 - Prob. 36PPCh. 1 - Prob. 37PPCh. 1 - Prob. 38PPCh. 1 - Prob. 39PPCh. 1 - Prob. 40PPCh. 1 - Prob. 41PPCh. 1 - Prob. 42PPCh. 1 - Prob. 43PPCh. 1 - Prob. 44PPCh. 1 - Prob. 45PPCh. 1 - Prob. 46PPCh. 1 - Prob. 47PPCh. 1 - Prob. 48PPCh. 1 - Prob. 49PPCh. 1 - Prob. 50PPCh. 1 - Prob. 51PPCh. 1 - Prob. 52PPCh. 1 - Prob. 53PPCh. 1 - Prob. 54PPCh. 1 - Prob. 55PPCh. 1 - Prob. 56PPCh. 1 - Prob. 57PPCh. 1 - Prob. 58PPCh. 1 - Prob. 59PPCh. 1 - Prob. 60PPCh. 1 - Prob. 61PPCh. 1 - Prob. 62PPCh. 1 - Prob. 63IPCh. 1 - Prob. 67IPCh. 1 - Prob. 68IPCh. 1 - Prob. 69IPCh. 1 - Prob. 70CPCh. 1 - Prob. 71CPCh. 1 - Prob. 72CPCh. 1 - Prob. 73CPCh. 1 - Prob. 74CPCh. 1 - Prob. 75CPCh. 1 - Prob. 76CPCh. 1 - Prob. 77CP
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