Chemistry: The Molecular Nature of Matter

7th Edition

ISBN: 9781118516461

Author: Neil D. Jespersen, Alison Hyslop

Publisher: WILEY

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Quantum Mechanical Treatment of the Valence Bond Theory

Quantum mechanical treatment of valence bond theory refers to the relationship established between the quantum mechanical theory and the valence bond theory to describe the chemical bonding in a particular molecule.

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Textbook Question

Chapter 11, Problem 96RQ

Carbon dioxide does not liquefy at atmospheric pressure, but instead forms a solid that sublimes at –78 °C . Nitrogen dioxide forms a liquid that boils at 21°C at atmospheric pressure. How do these data support the statement that CO 2 is a linear molecule whereas NO 2 is nonlinear?

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Chapter 11, Problem 95RQ

Chapter 11, Problem 97RQ

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Ammonium chloride, NH4Cl, is a very soluble salt in water.Is there an N—Cl bond in solid ammonium chloride?

Molecules can be polar because of the unsymmetrical distribution of electrons. The dipole moment, μ Q r μ=Q×r The SI unit of dipole moment is the coulomb-meter (C⋅m), but another common unit is the debye (D). The two are related as 3.336×10^−30 C⋅m=1 D The percent ionic character is a comparison of the measured dipole moment of the bond to the expected dipole moment if electrons are instead transferred: %ionic character=measured dipole/if electrons transferred×100% The dipole moment if electrons are completely transferred is one for which a full unit of charge (1.60×10^−19 C) exists on each end of the bond. The dipole measured for HI is 0.380 D. The bond distance is 161 pm. What is the percent ionic character of the HI bond? Express your answer as a percent to three significant figures. Describe the molecular dipole of OCl2.

The dipole moment of gaseous Ag – Cl is ? = 6.08 D, and the bond distance is r(Ag − Cl) = 228. 1 pm. Calculate the percent ionic character for this bond in the gas phase. In solid form it is however, found the following values for the two silver halides Ag − CL and Ag − F: See image Explain why solid silver chloride is sparingly soluble in water, while solid silver fluoride is moderately soluble B) Explain why solid silver chloride is sparingly soluble in water, while solid silver fluoride is moderately soluble Given extra information: Formal charge: ?? = ??? – (??? + ???); where ??? = valence electrons in free atom, ???= free-pair electrons, ??? = number of bonds to the atom. The elementary charge: ? = 1.6022 × 10−19 C.1 Debye (?)= 3.3356 × 10−30 C × m. The dipole moment has definition: ? = ? × ?, where ? is partialcharge in Coulomb (?), ? is the bond distance (?). Picometer: 1 ?? = 1 × 10−12

Chapter 11 Solutions

Chemistry: The Molecular Nature of Matter

Ch. 11 - Prob. 1PE Ch. 11 - List the following in order of their boiling...Ch. 11 - Propylamine and trimethylamine have the same...Ch. 11 - People living in arid, dry, regions can cool their...Ch. 11 - Use the kinetic molecular theory to explain why...Ch. 11 - Considering Figure 11.24, in which direction...Ch. 11 - Suppose a liquid is in equilibrium with its vapor...Ch. 11 - The Dead Sea is approximately 1300 ft below sea...Ch. 11 - The atmospheric pressure at the summit of Mt....Ch. 11 - Benzene has a boiling point of 80.1C, and a...

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