The fire releases 2.80 x 107 Joules of heat energy for each liter of oil burned. The water starts out at 24.5 °C, raising the water's temperature up to 100 °C, and then raises the temperature of the resulting steam up to 325 °C. How many liters of water will be needed to absorb the heat from the fire in this way, for each 1.0 liter of crude oil burned? 4186 J/(kg°C) = heat of water 2020 J/(kg°C) = heat of steam 2,256,000 (i.e. 2.256 x 106) J/kg = latent heat of vaporization for water (at the boiling point of 100 °C).
The fire releases 2.80 x 107 Joules of heat energy for each liter of oil burned. The water starts out at 24.5 °C, raising the water's temperature up to 100 °C, and then raises the temperature of the resulting steam up to 325 °C. How many liters of water will be needed to absorb the heat from the fire in this way, for each 1.0 liter of crude oil burned? 4186 J/(kg°C) = heat of water 2020 J/(kg°C) = heat of steam 2,256,000 (i.e. 2.256 x 106) J/kg = latent heat of vaporization for water (at the boiling point of 100 °C).
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The fire releases 2.80 x 107 Joules of heat energy for each liter of oil burned. The water starts out at 24.5 °C, raising the water's temperature up to 100 °C, and then raises the temperature of the resulting steam up to 325 °C. How many liters of water will be needed to absorb the heat from the fire in this way, for each 1.0 liter of crude oil burned?
4186 J/(kg°C) = heat of water
2020 J/(kg°C) = heat of steam
2,256,000 (i.e. 2.256 x 106) J/kg = latent heat of vaporization for water (at the boiling point of 100 °C).
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