Concept explainers
To find: if the given statement is true or false.

Answer to Problem 48E
False
Explanation of Solution
Given:
Statement: “To divide a line segment into 16 parts, midpoint formula needs to be applied 16 times.”
Concept Used:
Midpoint Formula: Midpoint of the line segment joining the two points
Midpoint formula is used to divide a line segment joining two points in two equal parts.
So, to divide line in two equal parts, midpoint formula is applied once. Now apply midpoint formula to each of the two equal parts obtained above to obtain 4 equal parts. That is, using midpoint formula three times
Now again apply midpoint formula to each of the four equal parts obtained above to obtain 8 equal parts. That is, using midpoint formula total seven times
Now again apply midpoint formula to each of the 8 equal parts obtained above to obtain 16 equal parts. That is, using midpoint formula total 15 times
Conclusion:
Given statement that to divide a line segment into 16 parts, midpoint formula needs to be applied 16 times is false because it needs to be applied 15 times only.
Chapter 1 Solutions
EBK PRECALCULUS W/LIMITS
- Find the derivative of the function. 5 1 6 p(x) = -24x 5 +15xarrow_forward∞ 2n (4n)! Let R be the radius of convergence of the series -x2n. Then the value of (3" (2n)!)² n=1 sin(2R+4/R) is -0.892 0.075 0.732 -0.812 -0.519 -0.107 -0.564 0.588arrow_forwardFind the cost function if the marginal cost function is given by C'(x) = x C(x) = 2/5 + 5 and 32 units cost $261.arrow_forward
- Find the cost function if the marginal cost function is C'(x) = 3x-4 and the fixed cost is $9. C(x) = ☐arrow_forwardFor the power series ∞ (−1)" (2n+1)(x+4)” calculate Z, defined as follows: n=0 (5 - 1)√n if the interval of convergence is (a, b), then Z = sin a + sin b if the interval of convergence is (a, b), then Z = cos asin b if the interval of convergence is (a, b], then Z = sin a + cos b if the interval of convergence is [a, b], then Z = cos a + cos b Then the value of Z is -0.502 0.117 -0.144 -0.405 0.604 0.721 -0.950 -0.588arrow_forwardH-/ test the Series 1.12 7√2 by ratio best 2n 2-12- nz by vitio test enarrow_forward
- Hale / test the Series 1.12 7√2 2n by ratio best 2-12- nz by vico tio test en - プ n2 rook 31() by mood fest 4- E (^)" by root test Inn 5-E 3' b. E n n³ 2n by ratio test ٤ by Comera beon Test (n+2)!arrow_forwardEvaluate the double integral ' √ √ (−2xy² + 3ry) dA R where R = {(x,y)| 1 ≤ x ≤ 3, 2 ≤ y ≤ 4} Double Integral Plot of integrand and Region R N 120 100 80- 60- 40 20 -20 -40 2 T 3 4 5123456 This plot is an example of the function over region R. The region and function identified in your problem will be slightly different. Answer = Round your answer to four decimal places.arrow_forwardFind Te²+ dydz 0 Write your answer in exact form.arrow_forward
- xy² Find -dA, R = [0,3] × [−4,4] x²+1 Round your answer to four decimal places.arrow_forwardFind the values of p for which the series is convergent. P-?- ✓ 00 Σ nº (1 + n10)p n = 1 Need Help? Read It Watch It SUBMIT ANSWER [-/4 Points] DETAILS MY NOTES SESSCALCET2 8.3.513.XP. Consider the following series. 00 Σ n = 1 1 6 n° (a) Use the sum of the first 10 terms to estimate the sum of the given series. (Round the answer to six decimal places.) $10 = (b) Improve this estimate using the following inequalities with n = 10. (Round your answers to six decimal places.) Sn + + Los f(x) dx ≤s ≤ S₁ + Jn + 1 + Lo f(x) dx ≤s ≤ (c) Using the Remainder Estimate for the Integral Test, find a value of n that will ensure that the error in the approximation s≈s is less than 0.0000001. On > 11 n> -18 On > 18 On > 0 On > 6 Need Help? Read It Watch Itarrow_forward√5 Find Lª³ L² y-are y- arctan (+) dy dydx. Hint: Use integration by parts. SolidUnderSurface z=y*arctan(1/x) Z1 2 y 1 1 Round your answer to 4 decimal places.arrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning





