Chapter 10, Problem 62A

(a)

Interpretation Introduction

Interpretation: To determine the mass of the given substance.

Concept Introduction: In chemistry, the molar mass is the mass of the 1 mole of the substance, and it is also calculated by,

  $\text{Molar}\text{mass=}\frac{\text{mass}}{\text{moles}}$

Answer to Problem 62A

The mass will be 108 g.

Explanation of Solution

Given:

Mole of ${\text{C}}_{\text{5}}{\text{H}}_{\text{12}}$= 1.5 mole

To find,

Mass =?

According to equation,

  $\begin{array}{c}\text{Molar}\text{mass=}\frac{\text{mass}}{\text{moles}}\\ \text{Mass=molar}\text{mass×mass}\\ \text{=72×1}\text{.5}\\ \text{=108}\text{g}\end{array}$

Therefore, mass will be 108 grams.

(b)

Interpretation Introduction

Interpretation: To determine the mass of given substance.

Concept Introduction: In chemistry, the molar mass is the mass of the 1 mole of the substance, and it is also calculated by,

  $\text{Molar}\text{mass=}\frac{\text{mass}}{\text{moles}}$

Answer to Problem 62A

The mass will be 547.2 g.

Explanation of Solution

Given

Mole of ${\text{F}}_{\text{2}}$ = 14.4 mole

To find,

Mass =?

According to the equation,

  $\begin{array}{c}\text{Molar}\text{mass=}\frac{\text{mass}}{\text{moles}}\\ \text{Mass=molar}\text{mass×mass}\\ \text{=38×14}\text{.4}\\ \text{=547}\text{.2g}\end{array}$

The mass will be 547.2 g.

(c)

Interpretation Introduction

Interpretation: To determine the mass of each substance

Concept Introduction: In chemistry, the molar mass is the mass of the 1 mole of the substance, and it is also calculated by,

  $\text{Molar}\text{mass=}\frac{\text{mass}}{\text{moles}}$

Answer to Problem 62A

The mass will be 71.76 g.

Explanation of Solution

Given:

Mole of $\text{Ca}{\left(\text{CN}\right)}_{\text{2}}$= 0.78 mole

To find,

Mass =?

According to the equation,

  $\begin{array}{c}\text{Molar}\text{mass=}\frac{\text{mass}}{\text{moles}}\\ \text{Mass=molar}\text{mass×mass}\\ \text{=92×0}\text{.78}\\ \text{=71}\text{.76g}\end{array}$

The mass will be 71.76 gram.

(d)

Interpretation Introduction

Interpretation: To determine the mass of the given substance.

Concept Introduction: In chemistry, the molar mass is the mass of the 1 mole of the substance, and it is also calculated by,

  $\text{Molar}\text{mass=}\frac{\text{mass}}{\text{moles}}$

Answer to Problem 62A

The mass will be 238 g.

Explanation of Solution

Given:

Mole of ${\text{H}}_{\text{2}}{\text{O}}_{\text{2}}$ = 7 mole

To find,

Mass =?

According to equation,

  $\begin{array}{c}\text{Molar}\text{mass=}\frac{\text{mass}}{\text{moles}}\\ \text{Mass=molar}\text{mass×mass}\\ \text{=34×7}\\ \text{=238g}\end{array}$

The mass will be 238 grams.

(e)

Interpretation Introduction

Interpretation: To determine the mass of the given substance.

Concept Introduction: In chemistry, the molar mass is the mass of the 1 mole of the substance, and it is also calculated by,

  $\text{Molar}\text{mass=}\frac{\text{mass}}{\text{moles}}$

Answer to Problem 62A

The mass will be 224 grams.

Explanation of Solution

Given:

Mole of NaOH = 5.6 mole

To find,

Mass =?

According to equation,

  $\begin{array}{c}\text{Molar}\text{mass=}\frac{\text{mass}}{\text{moles}}\\ \text{Mass=molar}\text{mass×mass}\\ \text{=40×5}\text{.6}\\ \text{=224g}\end{array}$

The mass will be 224 grams.

(f)

Interpretation Introduction

Interpretation: To determine the mass of the given substance.

Concept Introduction: In chemistry, the molar mass is the mass of the 1 mole of the substance, and it is also calculated by,

  $\text{Molar}\text{mass=}\frac{\text{mass}}{\text{moles}}$

Answer to Problem 62A

The mass will be $\text{179}{\text{.76×10}}^{\text{-2}}$ grams.

Explanation of Solution

Given:

Mole of Ni = $\text{3}\text{.21}\times {\text{10}}^{\text{-2}}\text{mole}$

To find,

Mass =?

According to equation,

  $\begin{array}{c}\text{Molar}\text{mass=}\frac{\text{mass}}{\text{moles}}\\ \text{Mass=molar}\text{mass×mass}\\ \text{=56×3}\text{.21}\times {\text{10}}^{-2}\\ \text{=179}\text{.76}\times {\text{10}}^{-2}\text{g}\end{array}$

The mass will be $\text{179}{\text{.76×10}}^{\text{-2}}$ grams.