Chapter 10, Problem 85A

Interpretation Introduction

Interpretation: To determine the grams of oxygen in 90 grams of ${\text{Cl}}_{\text{2}}\text{O}$ .

Concept Introduction: All element's atoms have a distinct mass, and each compound's molecules have a distinct mass that corresponds to its chemical formula.

Answer to Problem 85A

The gram of oxygen in 90 g of the ${\text{Cl}}_{\text{2}}\text{O}$ will be 16.6 g.

Explanation of Solution

The given compound is ${\text{Cl}}_{\text{2}}\text{O}$. By adding the mass of chlorine and oxygen, its molar mass will be :

Mass of chlorine = 35.5 g/mol.

Mass of oxygen = 16 g/mol.

  $\begin{array}{c}\text{Mass of}{\text{Cl}}_{\text{2}}\text{O}\text{=}\left(\text{35}\text{.5×}\text{2}\right)\text{+16}\\ \text{=87}\text{g/mol}\end{array}$

It is given that,

87 of ${\text{Cl}}_{\text{2}}\text{O}$ = 16 g/mol oxygen

So, the amount of oxygen in 90 grams of ${\text{Cl}}_{\text{2}}\text{O}$ can be calculated as:

  $\begin{array}{c}\text{90}\text{gram}\text{of}{\text{Cl}}_{\text{2}}\text{O}\text{=}\frac{\text{90}\text{×16}}{\text{87}}\\ \text{=16}\text{.6}\text{gram}\end{array}$

Therefore, the gram of oxygen in 90 g of ${\text{Cl}}_{\text{2}}\text{O}$ will be 16.6 gram