Chapter 10, Problem 67A

(a)

Interpretation Introduction

Interpretation: To determine the volume of the gases at STP.

Concept Introduction: Ideal gas equation give the relation between temperature, pressure, and volume. The ideal gas equation is shown as, $\text{PV}=\text{nRT}$

Answer to Problem 67A

The volume will be $\text{166}\text{.8L}$

Explanation of Solution

At STP,

Temperature (T) = 273 K

Pressure (P) = 1 atm

Given: Number of Mole = 7.64 moles

According to the ideal gas equation,

  $\text{PV=nRT}\mathrm{.....}\text{(i)}$

Put the given value in equation (i).

  $\begin{array}{c}\text{PV=nRT}\\ \text{V=}\frac{\text{7}\text{.64}\text{moles×0}\text{.08×273}}{\text{1}}\\ \text{=166}\text{.8L}\end{array}$

Therefore, the volume will be $\text{166}\text{.8L}$

(b)

Interpretation Introduction

Interpretation: To determine the volume of the gases at STP.

Concept Introduction: Ideal gas equation give the relation between temperature, pressure, and volume. The ideal gas equation is shown as, $\text{PV=nRT}$

Answer to Problem 67A

The volume will be 29.26L:

Explanation of Solution

At STP,

Temperature (T) = 273 K

Pressure (P) = 1 atm

Given: Number of Mole = 1.34 moles

According to the ideal gas equation,

  $\text{PV=nRT}\mathrm{.....}\text{(i)}$

Put the given value in equation (i).

  $\begin{array}{c}\text{PV=nRT}\\ \text{V=}\frac{1.34\text{moles×0}\text{.08×273}}{\text{1}}\\ \text{=29}\text{.26L}\end{array}$

Therefore, the volume will be 29.26L.

(c)

Interpretation Introduction

Interpretation: To determine the volume of the gases at STP.

Concept Introduction: Ideal gas equation give the relation between temperature, pressure, and volume. The ideal gas equation is shown as, $\text{PV=nRT}$

Answer to Problem 67A

The volume will be 9.21L:

Explanation of Solution

At STP,

Temperature (T) = 273 K

Pressure (P) = 1 atm

Given: Number of Mole = 0.422 moles

To find,

Volume =?

According to the ideal gas equation,

  $\text{PV=nRT}\mathrm{.....}\text{(i)}$

Put the given value in the equation (i).

  $\begin{array}{c}\text{PV=nRT}\\ \text{V=}\frac{0.422\text{moles×0}\text{.08×273}}{\text{1}}\\ \text{=9}\text{.21L}\end{array}$

Therefore, the volume will be 9.21L.

(d)

Interpretation Introduction

Interpretation: To determine the volume of the gases at STP.

Concept Introduction: Ideal gas equation give the relation between temperature, pressure, and volume. The ideal gas equation is shown as, $\text{PV=nRT}$

Answer to Problem 67A

The volume will be 53.9L:

Explanation of Solution

At STP,

Temperature (T) = 273 K

Pressure (P) = 1 atm

Given: Number of Mole = $\text{2}{\text{.47×10}}^{\text{-3}}\text{moles}$

According to the ideal gas equation,

  $\text{PV=nRT}\mathrm{.....}\text{(i)}$

Put the given value in equation (i).

  $\begin{array}{c}\text{PV=nRT}\\ \text{V=}\frac{2.47\times {10}^{-3}\text{moles×0}\text{.08×273}}{\text{1}}\\ \text{=53}\text{.9}\text{L}\end{array}$

Therefore, the volume will be 53.9L.