Chapter 10, Problem 80A

(a)

Interpretation Introduction

Interpretation: The number of atoms in $\text{1}\text{.00}\text{mol}$ of sucrose is to be calculated.

Concept Introduction: Glucose and fructose, two monosaccharides, make up the molecule known as sucrose. The molecular formula of this non-reducing disaccharide is ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ .

Common names for sucrose include table sugar and cane sugar.

Answer to Problem 80A

The number of atoms in $\text{1}\text{.00}\text{mol}$ of sucrose is $2.71\times {10}^{25}\text{atoms}$ .

Explanation of Solution

The number of atoms of ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ is given as follows:

  $\begin{array}{c}{\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}=12+22+11\\ =45\text{atoms}\end{array}$

The number of atoms in $\text{1}\text{.00}\text{mol}$ of sucrose is given as follows:

  $\begin{array}{c}\text{No}\text{.}\text{}\text{of}\text{}\text{atoms}=1\cancel{\text{mol}{\text{C}}_{12}{\text{H}}_{22}{\text{O}}_{11}}\times \frac{6.02\times {10}^{23}\cancel{\text{molecule}{\text{C}}_{12}{\text{H}}_{22}{\text{O}}_{11}}}{1\cancel{{\text{mol C}}_{12}{\text{H}}_{22}{\text{O}}_{11}}}\times \frac{45\text{atoms}}{1\cancel{\text{molecule}{\text{C}}_{12}{\text{H}}_{22}{\text{O}}_{11}}}\\ =2.71\times {10}^{25}\text{atoms}\end{array}$

(b)

Interpretation Introduction

Interpretation: The number of atoms of $\text{C}$ in $\text{2}\text{.00}\text{mol}$ of sucrose is to be calculated.

Concept Introduction: Glucose and fructose, two monosaccharides, make up the molecule known as sucrose. The molecular formula of this non-reducing disaccharide is ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ .

Common names for sucrose include table sugar and cane sugar.

Answer to Problem 80A

The number of atoms of $\text{C}$ in $\text{2}\text{.00}\text{mol}$ of sucrose is $1.44\times {10}^{23}\text{atoms}$ .

Explanation of Solution

The number of atoms of $\text{C}$ in ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ is given as follows:

  ${\text{C}}_{\text{12}}=12\text{atoms}$

The number of atoms of $\text{C}$ in $\text{2}\text{.00}\text{mol}$ of sucrose is given as follows:

  $\begin{array}{c}\text{No}\text{.}\text{}\text{of}\text{}\text{atoms}=2\cancel{\text{mol}{\text{C}}_{12}{\text{H}}_{22}{\text{O}}_{11}}\times \frac{6.02\times {10}^{23}\cancel{\text{molecule}{\text{C}}_{12}{\text{H}}_{22}{\text{O}}_{11}}}{1\cancel{{\text{mol C}}_{12}{\text{H}}_{22}{\text{O}}_{11}}}\times \frac{12\text{C}\text{atoms}}{1\cancel{\text{molecule}{\text{C}}_{12}{\text{H}}_{22}{\text{O}}_{11}}}\\ =1.44\times {10}^{23}\text{C atoms}\end{array}$

(c)

Interpretation Introduction

Interpretation: The number of atoms of $\text{H}$ in $\text{2}\text{.00}\text{mol}$ of sucrose is to be calculated.

Concept Introduction: Glucose and fructose, two monosaccharides, make up the molecule known as sucrose. The molecular formula of this non-reducing disaccharide is ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ .

Common names for sucrose include table sugar and cane sugar.

Answer to Problem 80A

The number of atoms of $\text{H}$ in $\text{2}\text{.00}\text{mol}$ of sucrose is $2.65\times {10}^{25}\text{atoms}$ .

Explanation of Solution

The number of atoms of $\text{H}$ in ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ is given as follows:

  ${\text{C}}_{22}=22\text{atoms}$

The number of atoms of $\text{H}$ in $\text{2}\text{.00}\text{mol}$ of sucrose is given as follows:

  $\begin{array}{c}\text{No}\text{.}\text{}\text{of}\text{}\text{atoms}=2\cancel{\text{mol}{\text{C}}_{12}{\text{H}}_{22}{\text{O}}_{11}}\times \frac{6.02\times {10}^{23}\cancel{\text{molecule}{\text{C}}_{12}{\text{H}}_{22}{\text{O}}_{11}}}{1\cancel{{\text{mol C}}_{12}{\text{H}}_{22}{\text{O}}_{11}}}\times \frac{22\text{H}\text{atoms}}{1\cancel{\text{molecule}{\text{C}}_{12}{\text{H}}_{22}{\text{O}}_{11}}}\\ =2.65\times {10}^{25}\text{H atoms}\end{array}$

(d)

Interpretation Introduction

Interpretation: The number of atoms of $\text{O}$ in $\text{3}\text{.65}\text{mol}$ of sucrose is to be calculated.

Concept Introduction: Glucose and fructose, two monosaccharides, make up the molecule known as sucrose. The molecular formula of this non-reducing disaccharide is ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ .

Common names for sucrose include table sugar and cane sugar.

Answer to Problem 80A

The number of atoms of $\text{O}$ in $\text{3}\text{.65}\text{mol}$ of sucrose is $2.42\times {10}^{25}\text{atoms}$ .

Explanation of Solution

The number of atoms of $\text{O}$ in ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ is given as follows:

  ${\text{O}}_{11}=11\text{atoms}$

The number of atoms of $\text{O}$ in $\text{3}\text{.65}\text{mol}$ of sucrose is given as follows:

  $\begin{array}{c}\text{No}\text{.}\text{}\text{of}\text{}\text{atoms}=3.65\cancel{\text{mol}{\text{C}}_{12}{\text{H}}_{22}{\text{O}}_{11}}\times \frac{6.02\times {10}^{23}\cancel{\text{molecule}{\text{C}}_{12}{\text{H}}_{22}{\text{O}}_{11}}}{1\cancel{{\text{mol C}}_{12}{\text{H}}_{22}{\text{O}}_{11}}}\times \frac{\text{11H}\text{atoms}}{1\cancel{\text{molecule}{\text{C}}_{12}{\text{H}}_{22}{\text{O}}_{11}}}\\ =2.42\times {10}^{25}\text{O atoms}\end{array}$