Chapter 10, Problem 78A

Interpretation Introduction

Interpretation: To determine the pair of compounds having the correct empirical formula.

Concept Introduction: The empirical formula represents the smallest whole number ratio of an atom present in the molecule or compound. The empirical formula of the molecule is obtained by multiplying the number present in the compound by the common number.

Answer to Problem 78A

(a)

Explanation of Solution

The empirical formula of ${\text{C}}_{\text{2}}{\text{H}}_{\text{4}}{\text{O}}_{\text{2}}$ = ${\text{CH}}_{\text{2}}\text{O}$

The empirical formula of ${\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}$ = ${\text{CH}}_{\text{2}}\text{O}$

Hence, ${\text{C}}_{\text{2}}{\text{H}}_{\text{4}}{\text{O}}_{\text{2}}$ and ${\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}$ molecule has the same empirical formula.

Conclusion

There is no other simplest of compounds ${\text{NaCrO}}_{\text{4}}$ and ${\text{Na}}_{\text{2}}{\text{Cr}}_{\text{2}}{\text{O}}_{\text{7}}$