Genetics: From Genes to Genomes, 5th edition
5th Edition
ISBN: 9780073525310
Author: Leland H. Hartwell, Michael L. Goldberg, Janice A. Fischer, Leroy Hood, Charles F. Aquadro
Publisher: McGraw-Hill Education
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Chapter 10, Problem 4P
A recent estimate of the rate of base substitutions at SNP loci is about 1 × 10−8 per
| a. | Based on this estimate, about how many de novo mutations (that is, mutations not found in the genomes of your parents) are present in your own genome? |
| b. | Where and when did these de novo mutations in your genome most likely occur? |
| c. | It has been calculated that each sperm made in a 25-year-old man is the result on average of about 300 rounds of cell division, starting with the first mitotic division of the male zygote. In contrast, each mature oocyte found in a 5-month-old female human fetus is the result of about 25 rounds of division, starting with the first mitotic division of the female zygote. What bearing do these calculations have on the estimate of the rate of base substitutions in humans, and on your answer to part (b)? |
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Chapter 10 Solutions
Genetics: From Genes to Genomes, 5th edition
Ch. 10 - Choose the phrase from the right column that best...Ch. 10 - Would you characterize the pattern of inheritance...Ch. 10 - Would you be more likely to find single nucleotide...Ch. 10 - A recent estimate of the rate of base...Ch. 10 - If you examine Fig. 10.5 on p. 344 closely, you...Ch. 10 - Approximately 50 million SNPs have thus far been...Ch. 10 - Mutations at simple sequence repeat SSR loci occur...Ch. 10 - Humans and gorillas last shared a common ancestor...Ch. 10 - Using PCR, you want to amplify an approximately 1...Ch. 10 - Prob. 10P
Ch. 10 - Prob. 11PCh. 10 - Prob. 12PCh. 10 - shows three different sequences of the same...Ch. 10 - The trinucleotide repeat region of the Huntington...Ch. 10 - Prob. 15PCh. 10 - Prob. 16PCh. 10 - a. It is possible to perform DNA fingerprinting...Ch. 10 - On July 17, 1918, Tsar Nicholas II; his wife the...Ch. 10 - The figure below shows DNA fingerprint analysis of...Ch. 10 - Microarrays were used to determine the genotypes...Ch. 10 - A partial sequence of the wild-type HbA allele is...Ch. 10 - Prob. 22PCh. 10 - Prob. 23PCh. 10 - The microarray shown at the top of this page...Ch. 10 - The figure below shows the pedigree of a family in...Ch. 10 - Prob. 26PCh. 10 - Now consider a mating between consanguineous...Ch. 10 - The pedigree shown in Fig. 10.22 on p.360 was...Ch. 10 - You have identified a SNP marker that in one large...Ch. 10 - The pedigrees indicated here were obtained with...Ch. 10 - Approximately 3 of the population carries a mutant...Ch. 10 - The drug ivacaftor has recently been developed to...Ch. 10 - In the high-throughput DNA sequencing protocol...Ch. 10 - A researcher sequences the whole exome of a...Ch. 10 - As explained in the text, the cause of many...Ch. 10 - Figure 10.26 on p. 366 portrayed the analysis of...Ch. 10 - Prob. 37PCh. 10 - Table 10.2 p. 367 and Fig. 10.27 p. 367 together...Ch. 10 - The human RefSeq of the entire first exon of a...
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- examples of synamtomorphy.arrow_forwardE. Bar Graph Use the same technique to upload the completed image. We will use a different type of graph to derive additional information from the CO2 data (Fig A1.6.2) 1. Calculate the average rate of increase in COz concentration per year for the time intervals 1959-1969, 1969- 1979, etc. and write the results in the spaces provided. The value for 1959-1969 is provided for you as an example. 2. Plot the results as a bar graph. The 1959-1969 is plotted for you. 3. Choose the graph that looks the most like yours A) E BAR GRAPH We will use a different type of graph to derive additional information from the CU, data (rig. nive). Average Yearly Rate of Observatory, Hawall interval Rate of increase per year 1959-1969 0.9 1969-1979 1979-1989 1989-1999 1999-2009 Figure A1.6.2 1999-2009 *- mrame -11- -n4 P2 جية 1989-1999 1979-1989 1969-1979 1959-1969 This bar drawn for you as an example 1.0 CO, Average Increase/Year (ppmv) B) E BAR GRAPH We will use a different type of graph to derive…arrow_forwardUse the relationships you just described to compute the values needed to fill in the blanks in the table in Fig A1.4.1 depth (a) 1.0 cml 0.7 cml cm| base dimensions (b, c)| 1.0 cm| 1.0 cm| 1.0 cm 1.0 cm| 1.0 cm| 1.0 cm volume (V) 1.0_cm' cm'| cm'| density (p) 1.0 g/cm'| 1.0 g/cm 1.0 g/cm' mass (m)| 0.3 g Column 1: depth at 1.0 cm volume mass Column 2: depth at 0.7 cm volume mass Column 3: unknown depth depth volumearrow_forward
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- Draw a gram negative bacterial cell below. Your cell should have the following parts, labeled: A bacillus shape Fimbriae Amphitrichous flagella 2 membranes (outer and inner) The outer membrane should have lipopolysaccharide (LPS) with lipid A and O antigens Periplasmic space The thin peptidoglycan cell wall between the 2 membranes A nucleoid Ribosomes Inclusionsarrow_forwardBacterial species Cell wall type Example: S. mitis Gram positive S. epidermidis H. pylori M. bovis S. marcescens Shape and arrangement Coccus, streptococcus Drawing 0000000arrow_forwardDraw a gram positive bacterial cell below. Your cell should have the following parts, labeled: A coccus shape A capsule The gram positive cell wall should have the peptidoglycan labeled, as well as its component parts (NAM, NAG, and teichoic acid) A cell membrane Fimbriae A nucleoid Ribosomes Inclusionsarrow_forward
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