Genetics: From Genes to Genomes, 5th edition
Genetics: From Genes to Genomes, 5th edition
5th Edition
ISBN: 9780073525310
Author: Leland H. Hartwell, Michael L. Goldberg, Janice A. Fischer, Leroy Hood, Charles F. Aquadro
Publisher: McGraw-Hill Education
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Chapter 10, Problem 23P
Summary Introduction

a.

To determine:

The genotype for all DNA markers in both parents.

Introduction:

DNA (deoxyribonucleic acid) marker refers to an identifiable physical location on a chromosome with DNA sequence variants whose inheritance can be monitored.

Summary Introduction

b.

To determine:

The microarray data showing that one SNP locus has three alleles in the family.

Introduction:

Alleles are known as the alternative forms of a gene. The basic and physical unit of hereditary is referred to as a gene.

Summary Introduction

c.

To determine:

The way to recognize that the loci on chromosome 4 are about 10 Mb apart.

Introduction:

The self-replicating DNA (deoxyribonucleic acid) or protein complexes in the nucleus that contain genes are known as chromosomes.

Summary Introduction

d.

To determine:

The percentage of length of chromosome 4 that is present in the region between DNA markers 1 and 8.

Introduction:

The length of chromosome 4 is 191 Mb (Mega-basepairs). Each SNP has 10 Mb distance on chromosome-4.

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A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation?   The cell membranes are more resistant than normal.   An isotonic solution had been added instead of water.   A solution of 0.1 M NaCl had been added instead of water.   Not enough water had been added to the red blood cell pellet.   The man had sickle-cell anaemia.
A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation?   The cell membranes are more resistant than normal.   An isotonic solution had been added instead of water.   A solution of 0.1 M NaCl had been added instead of water.   Not enough water had been added to the red blood cell pellet.   The man had sickle-cell anaemia.
With reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobin

Chapter 10 Solutions

Genetics: From Genes to Genomes, 5th edition

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