To analyze:
Plants of a particular species can either have the dominant wild-type
Using this information, answer the following:
Propose two mutational events that could cause the small DNA fragment that represents the mutant allele.
In northern blot analysis of mRNA, what mRNA differences would you anticipate for your two proposed mutational mechanisms?
Introduction:
The wild type dominant gene produces tall plants, and recessive genes are responsible for production of dwarf plants. The wild type gene gives a fragment of length around
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Genetic Analysis: An Integrated Approach (2nd Edition)
- Familial retinoblastoma, a rare autosomal dominant defect, arose in a large family that had no prior history of the disease. Consider the following pedigree (the darkly colored symbols represent affected individuals): a. Circle the individual(s) in which the mutation most likely occurred. b. Is the person who is the source of the mutation affected by retinoblastoma? Justify your answer. c. Assuming that the mutant allele is fully penetrant, what is the chance that an affected individual will have an affected child?arrow_forwardThere are two genetic disorders that result from mutation in imprinted genes: Prader-Willi syndrome and Angelman syndrome. Prader-Willi syndrome results from deletion of region 15q11-q13, which in healthy individuals is a region imprinted such that only the paternal copy is expressed. In the pedigree above, individual I-1 is heterozygous for a deletion of region 15q11-q13 and does not have Prader-Willi syndrome. Individuals I-2 and II-1 are both homozygous wild type for the region. Which individuals in the pedigree might have Prader-Willi syndrome? (Who could potentially have the syndrome, based on what alleles it is possible for them to inherit and express?) Question 9 options: Only II-2 could have Prader-Willi syndrome III-1 could have Prader-Willi syndrome in the presented pedigree; II-2 could only have had it if she were male Both II-2 and III-1 could have Prader-Willi syndrome II-2 could have…arrow_forwardBelow is shown an annotation indicating the protein coding genes of a Drosophila genomic region. Below this map is shown the structure of an inversion (the vertical lines indicate the breakpoints), three deletions (indicated by the gaps) and three Insertions (indicated by the triangles) 100 S עולם Sara N Deletion Insortion Insertion 2 13829 Inversion 1 Execst PART Deletion? Deletion 3 Insertion 3 You have a mutation in a gene required for the development of the wings. Drosophila homozygous for this mutation have no wings. You cross these Drosophila homozygous for the wingless mutant allele with Drosophila homozygous for the seven mapped DNA changes. Mapped change Phenotype Inversion 1 wingless Deletion 1 wingless Deletion 2 wild type Deletion 3 wild type Insertion 1 wild type Insertion 2 wingless Insertion 3 wild type You conclude that the mutated allele is in which of the below genes? hh unk Irk1 CG46310 cnc Ⓒfzo CG4467 Rad60 EloA wda Pex11c orbarrow_forward
- Transgenic tobacco plants were obtained in which the vector Ti plasmid was designed to insert the gene of interest plus an adjacent kanamycin-resistance gene. The inheritance of chromosomal insertion was followed by testing progeny for kanamycin resistance. Two plants typified the results obtained generally. When plant 1 was backcrossed with wild-type tobacco, 50 percent of the progeny were kanamycin resistant and 50 percent were sensitive. When plant 2 was backcrossed with the wild type, 75 percent of the progeny were kanamycin resistant and 25 percent were sensitive. What must have been the difference between the two transgenic plants? What would you predict about the situation regarding the gene of interest?arrow_forwardDuchenne Muscular Dystrophy (DMD) is a disorder that primarily affects the function of skeletal muscles used for movement and cardiac muscles used for heart beating. Dystrophin is a protein encoded by a single gene, DMD, that is expressed in skeletal and cardiac muscle. Some forms of muscular dystrophy may be caused by different mutations in the DNA sequence of the DMD gene. Because the DMD locus is on the X chromosome, males are affected at higher rates. Two brothers, one of whom has DMD and one of whom does not, worked with their genetic counselor (Links to an external site.) to have their DMD gene sequenced to identify genetic variation that may explain why one brother was affected and the other not. Because DMD is a very long gene, a fictionalized, simplified model of the results is presented here (Figure 1). The actual DMD mRNA is about 16,000 base-pairs!------Consider single nucleotide polymorphism (SNP) #1 (Figure 1). Is this mutation likely to cause Duchenne muscular…arrow_forwardIn the chapter-opening photograph of kernels on an earof corn, what is the genetic basis of the following (Hint:Refer to Figure 15-4 for some clues):a. the fully pigmented kernel?b. the unpigmented kernels? Note that they can arise intwo different ways.arrow_forward
- The fruit fly Drosophila melanogaster has about 2 x 10^8 base pairs of DNA per haploid genome, of which about 75% in nonrepeated DNA. The DNA is distributed among four pairs of homologous chromosomes, which have a total of about 5,000 visible bands when in polytene forms in the salivary gland. The number of genes initially estimated from mutational studies was also about 5,000 but recent DNA sequencing studies suggest that the gene number may be somewhat higher. a. Why was it tempting to speculate that each band corresponds to a single gene? What does this suggest about the number of different proteins Drosophila can make? Does that seem like a reasonable number to you? b. Assuming all the nonrepeated DNA is uniformly distributed in the chromosomes, how much nonrepeated DNA (in base pairs) is there in average band?arrow_forwardThe D1S80 locus is located on human chromosome 1 and is characterized by a repeating 16 base pair (bp) sequence. Alleles for this locus vary depending on the number of repeats present, thus affecting the size of the locus. The D1S80 locus also contains two conserved sequences, a 32bp sequence at one end and a 113bp sequence at the other end. If the DNA of an individual is targeted for D1S80 amplification, and one of the resulting amplicons is approximately 785bp in size, how many repeats would be present in this D1S80 allele? The amplicon of interest is indicated by a red arrow in the diagram below.arrow_forwardThe DNA of every individual in the pedigree shown below has been sequenced at the causative locus. All the non-shaded individuals are wild type apart from III.1. III.1 has been proven to have the causative mutation for this autosomal dominant condition, but they exhibit no symptoms. Based on this small pedigree, what is the level of penetrance for the condition? Please give your answer as a WHOLE percentage, give the number only, no percentage symbol. Answer: The level of penetrance for the condition shown in the pedigree below is Blank 1 percent. 1:1 1:2 Il:1 I1:2 I1:3 Il:4 I1:5 I1:6 II:1 I:2 III:3 III:4 III:3 III:6 III:7 III:8 III:9 III:10 III:11 III12 II:13 III:14 IV:1 | IV:2 IV:3 IV:4 IV:5 IV:6 IV:7 IV:8 IV:9 IV:10 IV:11 IV:12 IV:13 IV:14 IV:15 IV:16 IV:17 IV:18 IV:19 V:1 V:2 V:3 V:4 V:5 V:6 V:7 V:8 V:9 V:10 V:11 V:12arrow_forward
- QUESTION 11 The location of five deletions have been mapped to a Drosophila chromosome, as shown in the following deletion map. Recessive mutations a, b, c, d and e are known to be located in the same region as the deletions but the order of the mutations on the chromosome is not known. Drosophila Chromosome Deletion 1 Deletion 2 Deletion 3 Deletion 4 Deletion 5 When flies homozygous for the recessive mutation are crossed with flies heterozygous for the deletions, the following results are obtained in which "m" represents recovery of flies with a mutant phenotype and "+" represents recovery of only flies with a wildtype phenotype. Use the data from the table below to determine the order of the genes (a-e) on the chromosome. Mutants Deletions a b C d e 1 + + + + m 2 + m + m 3 m m m m 4 + + m + + 5 m + m m + What is the gene order for these five genes? Please do not separate the letters representing the mutations with spaces or punctuation (e.g. LMNOP)arrow_forwardThe DNA of every individual in the pedigree shown in image B (below) has been sequenced at the causative locus, all the non- shaded individuals are wild type apart from III.1 and III.6. III.1 and III.6 have both been proven to have the causative allele for the condition but they do not exhibit any of the phenotypic signs or symptoms. Based on this pedigree, what is the level of penetrance for the condition? Please give your answer as a percentage to one decimal place, give the number only, no percentage symbol. ANSWER: Given the information above I calculate the level of penetrance seen in image B to be Blank 1 percent. A KEY Homozygous Homozygous Heterozygous Heterozygous Wild Type Male Female Male Female Male Note: Completely red symbol denotes an individual exhibiting the phenotype of interest CI || III IV V 1/4 1/2 1/2 1/2 1/2 Wild Type Female 1/4 1/2 Affected Known carrier Affected female Normal female Affected male Normal male D ●●●arrow_forwardThe DNA of every individual in the pedigree shown in image B (below) has been sequenced at the causative locus, all the non-shaded individuals are wild type apart from III.1 and III.6. III.1 and III.6 have both been proven to have the causative allele for the condition but they do not exhibit any of the phenotypic signs or symptoms. Based on this pedigree, what is the level of penetrance for the condition? Please give your answer as a percentage to one decimal place, give the number only, no percentage symbol. Given the information above I calculate the level of penetrance seen in image B to be "Blank" 1 percent.arrow_forward
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning