Genetic Analysis: An Integrated Approach (2nd Edition)
Genetic Analysis: An Integrated Approach (2nd Edition)
2nd Edition
ISBN: 9780321948908
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 10, Problem 32P
Summary Introduction

To analyze:

Based on the result of western blot given below:

Genetic Analysis: An Integrated Approach (2nd Edition), Chapter 10, Problem 32P

  1. Identify the protein change resulting in two bands observed in the western blot for organisms having Dd2 genotype.

  2. The absence of detectable protein for organisms with the d1d1 genotype.

  3. The reason behind presence of just one detectable protein band for organisms having d1d2 and d2d2 genotypes.

  4. Based on evaluation of western blot analysis, project the nature of the mutations generating d1 and d2. In other words, changes at the DNA level led to production of these mutations.

Introduction:

Genes encode the functional protein and enzymes; these protein and enzymes perform specific functions to express specific phenotypes. The experimental approach, western blotting, is used to observe the protein level expression pattern of a gene. An individual has two alleles for one gene whereas when multiple alleles for one gene are present in a population, the population is termed as polymorphic population. Dominant allele (D) encodes the functional enzyme but recessive allele (d) does not encode a functional protein. The band pattern for a heterozygous individual is observed in lane 2. The dominant allele suppresses the effect of a recessive allele.

D

Another recessive allele (d2) encodes the protein that inhabits the expression of the dominant allele (D). The band pattern of recessive allele (d2) is observed in western blotting.

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For short answer questions, write your answers on the line provided. To the right is the mRNA codon table to use as needed throughout the exam. First letter U บบบ U CA UUCPhe UUA UCU Phe UCC UUG Leu CUU UAU. G U UAC TV UGCys UAA Stop UGA Stop A UAG Stop UGG Trp Ser UCA UCG CCU] 0 CUC CUA CCC CAC CAU His CGU CGC Leu Pro CCA CAA Gin CGA Arg CUG CCG CAG CGG AUU ACU AAU T AUC lle A 1 ACC Thr AUA ACA AUG Mot ACG AGG Arg GUU GCU GUC GCC G Val Ala GAC Asp GGU GGC GUA GUG GCA GCG GAA GGA Gly Glu GAGJ GGG AACASH AGU Ser AAA1 AAG Lys GAU AGA CAL CALUCAO CAO G Third letter 1. (+7) Use the table below to answer the questions; use the codon table above to assist you. The promoter sequence of DNA is on the LEFT. You do not need to fill in the entire table. Assume we are in the middle of a gene sequence (no need to find a start codon). DNA 1 DNA 2 mRNA tRNA Polypeptide C Val G C. T A C a. On which strand of DNA is the template strand (DNA 1 or 2)?_ b. On which side of the mRNA is the 5' end (left or…
3. (6 pts) Fill in the boxes according to the directions on the right. Structure R-C R-COOH OH R-OH i R-CO-R' R R-PO4 R-CH3 C. 0 R' R-O-P-OH 1 OH H R-C-H R-N' I- H H R-NH₂ \H Name Properties
4. (6 pts) Use the molecule below to answer these questions and identify the side chains and ends. Please use tidy boxes to indicate parts and write the letter labels within that box. a. How many monomer subunits are shown? b. Box a Polar but non-ionizable side chain and label P c. Box a Basic Polar side chain and label BP d. Box the carboxyl group at the end of the polypeptide and label with letter C (C-terminus) H H OHHO H H 0 HHO H-N-CC-N-C-C N-C-C-N-GC-OH I H-C-H CH2 CH2 CH2 H3C-C+H CH2 CH2 OH CH CH₂ C=O OH CH2 NH2
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