Mutation analysis of GCK gene in patients with diabetes revealed a c.114 TA (shown in bold and underlined) substitution in heterozygote state. In order to check the mutation in healthy individuals, restriction enzyme analysis will be used. a) Which enzyme can we use to differentiate wild type and mutant sequence? Please indicate which allele (wild type or mutant allele) will be cut with the restriction enzyme. Use table 1 shown below. b) Draw the expected agarose gel result of a homozygous wild type, homozygous mutant and heterozygote individual after restriction enzyme analysis. ATGAGGCTCTTTGCCACCAGTCCCAGTTTTATGCATGGCAGCTCTAATGACAGGATGGTCACCCCTGC TGAGGCCACTCCTGGTCACCATGACAACCACAGGCCCTCTCAGTATCACAGTAAGCCCTGGCAGGAG AATCCCCCACTCCACACCTGGCTGGAGCACGAAATGCCGAGCGGCGCCTGAGCCCCAGGGAAGCAG GCTAGGATGTGA Figure 1. GCK gene sequence. Length of the fragment is 213bp. Table1. The restriction enzymes and their recognition sequences. Restriction enzyme Recognition seguence Nar I GG/CGCC Dde I c/TNAG www Hae III NGCGC/n Cc/GG Hpall Alul AG/CT Smal ССС/GGG Mbol /GATC Mae III wwww /GTNAC Bsp 1286 I GnGCn/C ww Hind III A/AGCTT EcoR I G/AATTC wwm n: any nucleotide /: cutting site

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Mutation analysis of GCK gene in patients with diabetes revealed a c.114 T A (shown in bold
and underlined) substitution in heterozygote state. In order to check the mutation in healthy
individuals, restriction enzyme analysis will be used.
a) Which enzyme can we use to differentiate wild type and mutant sequence? Please indicate
which allele (wild type or mutant allele) will be cut with the restriction enzyme. Use table
1 shown below.
b) Draw the expected agarose gel result of a homozygous wild type, homozygous mutant and
heterozygote individual after restriction enzyme analysis.
ATGAGGCTCTTTGCCACCAGTCCCAGTTTTATGCATGGCAGCTCTAATGACAGGATGGTCACCCCTGC
TGAGGCCACTCCTGGTCACCATGACAACCACAGGCCCTCTCAGTATCACAGTAAGCCCTGGCAGGAG
AATCCCCCACTCCACACCTGGCTGGAGCACGAAATGCCGAGCGGCGCCTGAGCCCCAGGGAAGCAG
GCTAGGATGTGA
Figure 1. GCK gene sequence. Length of the fragment is 213bp.
Table1. The restriction enzymes and their recognition sequences.
Restriction enzyme
Recognition seguence
Nar I
GG/CGCC
Dde I
c/TNAG
wwwww
Hae IlI
NGCGC/n
wwww
Hpall
c/GG
Alul
AG/CT
Smal
ССС/GGG
Mbol
/GATC
Маe II
/GTNAC
ww
Bsp 1286 I
GnGCn/C
Hind III
A/AGCTT
EcoR I
G/AATTC
n: any nucleotide
/: cutting site
Transcribed Image Text:Mutation analysis of GCK gene in patients with diabetes revealed a c.114 T A (shown in bold and underlined) substitution in heterozygote state. In order to check the mutation in healthy individuals, restriction enzyme analysis will be used. a) Which enzyme can we use to differentiate wild type and mutant sequence? Please indicate which allele (wild type or mutant allele) will be cut with the restriction enzyme. Use table 1 shown below. b) Draw the expected agarose gel result of a homozygous wild type, homozygous mutant and heterozygote individual after restriction enzyme analysis. ATGAGGCTCTTTGCCACCAGTCCCAGTTTTATGCATGGCAGCTCTAATGACAGGATGGTCACCCCTGC TGAGGCCACTCCTGGTCACCATGACAACCACAGGCCCTCTCAGTATCACAGTAAGCCCTGGCAGGAG AATCCCCCACTCCACACCTGGCTGGAGCACGAAATGCCGAGCGGCGCCTGAGCCCCAGGGAAGCAG GCTAGGATGTGA Figure 1. GCK gene sequence. Length of the fragment is 213bp. Table1. The restriction enzymes and their recognition sequences. Restriction enzyme Recognition seguence Nar I GG/CGCC Dde I c/TNAG wwwww Hae IlI NGCGC/n wwww Hpall c/GG Alul AG/CT Smal ССС/GGG Mbol /GATC Маe II /GTNAC ww Bsp 1286 I GnGCn/C Hind III A/AGCTT EcoR I G/AATTC n: any nucleotide /: cutting site
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