Analysis of the a-ketoglutarate formed showed that none of the radioactive label had been lost. Decarboxylation of a-ketoglutarate then yielded succinate devoid of radioactivity. All the label was in the released CO₂. Use an asterisk (*) to indicate the location of "C in the intermediates and products of the pathway that converts [C]oxaloacetate into succinate. Coo Coo CH₂ CH₂ Tooc-c-OH ooc-CH CH₂ CH₂ HC OH 14Coo coo -Coo [14C]oxaloacetate Citrate Isocitrate 0000 Coo coo CH₂ CH₂ S-COA Succinate Succinyl CoA ☐ ☐ CH₂ a-Ketoglutarate Why do all the labeled carbons emerge as carbon dioxide? Citrate is a symmetric molecule, and each -CH, COO group reacts identically. Both of citrate's -CH, COO groups are decarboxylated on the pathway to succinate. Citrate is a chiral molecule, and each-CH,COO- group reacts differently. An enzyme in this pathway holds its substrate in a specific orientation. Anwer Bank
Analysis of the a-ketoglutarate formed showed that none of the radioactive label had been lost. Decarboxylation of a-ketoglutarate then yielded succinate devoid of radioactivity. All the label was in the released CO₂. Use an asterisk (*) to indicate the location of "C in the intermediates and products of the pathway that converts [C]oxaloacetate into succinate. Coo Coo CH₂ CH₂ Tooc-c-OH ooc-CH CH₂ CH₂ HC OH 14Coo coo -Coo [14C]oxaloacetate Citrate Isocitrate 0000 Coo coo CH₂ CH₂ S-COA Succinate Succinyl CoA ☐ ☐ CH₂ a-Ketoglutarate Why do all the labeled carbons emerge as carbon dioxide? Citrate is a symmetric molecule, and each -CH, COO group reacts identically. Both of citrate's -CH, COO groups are decarboxylated on the pathway to succinate. Citrate is a chiral molecule, and each-CH,COO- group reacts differently. An enzyme in this pathway holds its substrate in a specific orientation. Anwer Bank
Chapter10: Reconstitution Of Powdered Drugs
Section: Chapter Questions
Problem 6.4P
Related questions
Question
![Analysis of the a-ketoglutarate formed showed that none of the radioactive label had been lost. Decarboxylation of
a-ketoglutarate then yielded succinate devoid of radioactivity. All the label was in the released CO₂.
Use an asterisk (*) to indicate the location of "C in the intermediates and products of the pathway that converts
[C]oxaloacetate into succinate.
Coo
Coo
CH₂
CH₂
Tooc-c-OH
ooc-CH
CH₂
CH₂
HC OH
14Coo
coo
-Coo
[14C]oxaloacetate
Citrate
Isocitrate
0000
Coo
coo
CH₂
CH₂
S-COA
Succinate
Succinyl CoA
☐ ☐
CH₂
a-Ketoglutarate
Why do all the labeled carbons emerge as carbon dioxide?
Citrate is a symmetric molecule, and each -CH, COO group reacts identically.
Both of citrate's -CH, COO groups are decarboxylated on the pathway to succinate.
Citrate is a chiral molecule, and each-CH,COO- group reacts differently.
An enzyme in this pathway holds its substrate in a specific orientation.
Anwer Bank](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F31f59ff4-c1b6-4bfe-b48e-f376b2b8e1ed%2Fba52935a-02c5-4dbf-9399-a7276ab4f636%2Fpfoua4b_processed.png&w=3840&q=75)
Transcribed Image Text:Analysis of the a-ketoglutarate formed showed that none of the radioactive label had been lost. Decarboxylation of
a-ketoglutarate then yielded succinate devoid of radioactivity. All the label was in the released CO₂.
Use an asterisk (*) to indicate the location of "C in the intermediates and products of the pathway that converts
[C]oxaloacetate into succinate.
Coo
Coo
CH₂
CH₂
Tooc-c-OH
ooc-CH
CH₂
CH₂
HC OH
14Coo
coo
-Coo
[14C]oxaloacetate
Citrate
Isocitrate
0000
Coo
coo
CH₂
CH₂
S-COA
Succinate
Succinyl CoA
☐ ☐
CH₂
a-Ketoglutarate
Why do all the labeled carbons emerge as carbon dioxide?
Citrate is a symmetric molecule, and each -CH, COO group reacts identically.
Both of citrate's -CH, COO groups are decarboxylated on the pathway to succinate.
Citrate is a chiral molecule, and each-CH,COO- group reacts differently.
An enzyme in this pathway holds its substrate in a specific orientation.
Anwer Bank
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