Bundle: Chemistry, Loose-leaf Version, 10th + Enhanced Webassign Printed Access Card For Chemistry, Multi-term Courses - 10th Edition - by ZUMDAHL - ISBN 9781337761642

Bundle: Chemistry, Loose-leaf Version, ...
10th Edition
ZUMDAHL
Publisher: Cengage Learning
ISBN: 9781337761642

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Chapter 1, Problem 64EChapter 1, Problem 67EChapter 1, Problem 68EChapter 1, Problem 77EChapter 1, Problem 121CPChapter 2, Problem 1RQChapter 2, Problem 68EChapter 2, Problem 71EChapter 2, Problem 72EExplanation: Atomic number given is 13. From the periodic table we can identify that the element...Chapter 2, Problem 75EExplanation: To determine: The naming of CuI The name of CuI is copper(I) iodide. In naming of...Explanation: To determine: The naming of HC2H3O2 The naming of HC2H3O2 is acetic acid. Rules for...To determine: The formula of of sulfur difluoride The formula of sulfur difluoride is SF2 Sulfur...Explanation: To determine: The formula of sodium oxide. The formula of sodium oxide is Na2O The...Chapter 2, Problem 90EChapter 2, Problem 92EExplanation: To determine: The formula and the name of the binary compound formed from Ca and N. The...Explanation: Given, 1531X Atomic number, Z =15 Mass number, A =31 The atomic number of the element...Explanation: To determine: The explanation for the term “counting by weighing”. The stated concept,...Chapter 3, Problem 61EChapter 3, Problem 62EChapter 3, Problem 63EExplanation: Given The mass of P4O6 is 1.00 g . The molar mass of P4O6 is 219.866 g/mol . Formula...Chapter 3, Problem 69EChapter 3, Problem 70EChapter 3, Problem 73EChapter 3, Problem 75EChapter 3, Problem 78EChapter 3, Problem 81EChapter 3, Problem 102EChapter 3, Problem 103EChapter 3, Problem 115EChapter 3, Problem 125EChapter 3, Problem 127EChapter 3, Problem 132EChapter 3, Problem 152AEChapter 3, Problem 160AEChapter 3, Problem 162CWPChapter 3, Problem 192IPChapter 4, Problem 1RQChapter 4, Problem 7RQExplanation: NaBr(s)→Na(aq)++Braq- Figure 1 Let us consider the above molecular-level pictures of...Explanation: Record the given data Moles of Sodium phosphate= 0.200 moles Volume of the solution=...Chapter 4, Problem 85EChapter 4, Problem 88EChapter 4, Problem 91EChapter 4, Problem 92EChapter 4, Problem 93EChapter 4, Problem 94EChapter 4, Problem 107AEChapter 4, Problem 137CPExplanation Record the given data Mass of the sample mixture = 0.205 g Mass of the precipitate =...Chapter 4, Problem 154CPChapter 4, Problem 155CPChapter 4, Problem 161MPA barometer consists of Mercury column that is tipped inverted and positioned in a dish containing...Chapter 5, Problem 45EExplanation: The relation between pressures measured in the manometers containing mercury and...Explanation According to ideal gas equation, PV=nRT By rearranging the above equation, PVnT=R Since...Chapter 5, Problem 94EExplanation: To find: the mole fractions of CH4 and O2 in the given mixture if the partial pressure...Explanation To find: the number of moles of dimethyl hydrazine from its given mass. The number of...Explanation To determine: The partial pressure of carbon monoxide Partial pressure of carbon...Explanation To determine: The mixing ratio of benzene Mixing ratio of benzene = 9.47 × 10-3ppmv For...Chapter 5, Problem 143AEExplanation To find: the empirical formula of the compound Convert the mass percent to gram 58.51%...Chapter 5, Problem 147AEExplanation To find: the balanced chemical equation of the given reaction of combustion of...Chapter 5, Problem 160CPChapter 5, Problem 161CPExplanation To determine: Mass of hot air when the average molar mass of air 29.0g/mol Mass of hot...To determine: The mass percent of elements in the unknown compound from the given data Mass % of...Chapter 5, Problem 172IPChapter 6, Problem 1RQChapter 6, Problem 24QChapter 6, Problem 38EChapter 6, Problem 54EChapter 6, Problem 56EChapter 6, Problem 79EChapter 6, Problem 85EChapter 6, Problem 86EExplanation: The balanced equation is: a) N2(g)→N2(l) In (a) the volume of products is decreases...Chapter 6, Problem 114AEChapter 6, Problem 121AEChapter 6, Problem 136CPChapter 6, Problem 137CPChapter 6, Problem 143IPChapter 6, Problem 145MPChapter 7, Problem 1RQChapter 7, Problem 28QChapter 7, Problem 49EChapter 7, Problem 51EChapter 7, Problem 63EChapter 7, Problem 64EChapter 7, Problem 68EChapter 7, Problem 69EChapter 7, Problem 75EChapter 7, Problem 80EChapter 7, Problem 85EChapter 7, Problem 87EChapter 7, Problem 88EChapter 7, Problem 99EChapter 7, Problem 100EChapter 7, Problem 101EChapter 7, Problem 103EChapter 7, Problem 152AEChapter 7, Problem 179CPChapter 7, Problem 181CPChapter 8, Problem 1RQExplanation: Refer to figure 3-4. The electro negativity of carbon (C) , nitrogen (N) , and oxygen...Explanation: Refer to figure 3-4 The electro negativity of Sodium (Na) Potassium (K) and Rubidium...Chapter 8, Problem 50EChapter 8, Problem 51EChapter 8, Problem 53EExplanation: In a periodic table the size of ions depends on the nuclear attraction on the valence...Chapter 8, Problem 58EChapter 8, Problem 66EChapter 8, Problem 81EChapter 8, Problem 85EChapter 8, Problem 88EChapter 8, Problem 93EChapter 8, Problem 105EChapter 8, Problem 106EChapter 8, Problem 135AEChapter 8, Problem 162CPChapter 8, Problem 163CPChapter 9, Problem 1RQChapter 9, Problem 27EChapter 9, Problem 28EChapter 9, Problem 30EChapter 9, Problem 33EChapter 9, Problem 34EChapter 9, Problem 43EChapter 9, Problem 56EChapter 9, Problem 57EChapter 9, Problem 67AEChapter 9, Problem 95CPChapter 10, Problem 1RQChapter 10, Problem 43EExplanation: CCl4 , CBr4, CF4 Identify the compound which has highest boiling point and justify it....Chapter 10, Problem 55EChapter 10, Problem 57EChapter 10, Problem 58EChapter 10, Problem 59EChapter 10, Problem 60EChapter 10, Problem 61EChapter 10, Problem 62EChapter 10, Problem 64EChapter 10, Problem 80EChapter 10, Problem 82EChapter 10, Problem 90EChapter 10, Problem 141CPChapter 10, Problem 156CPChapter 10, Problem 158IPExplanation: To explain molarity Molarity can be defined as moles of solute to litres of solution....Chapter 11, Problem 18SRChapter 11, Problem 39EExplanation: Record the given data Gram equivalent of HCl = 0.25 Molarity of HCl = 0.25 M To...Explanation: KrF2 8+2(7)=22e- KrF2 is dissolves in CCl4 . KrF2 is non-polar molecule that makes it...Chapter 11, Problem 69EChapter 11, Problem 85EExplanation: Record the given data, Molality of MgCl2= 0.050 m Molality of FeCl3= 0.050 m To...Explanation: Record the given data, Molality of MgCl2= 0.050 m Molality of FeCl3= 0.050 m To...Explanation: To find the Acetone and water polarity CH3COCH3 and H2O The electrostatic possible...Explanation: Record the given data, Freezing point of an aqueous solution =- 2.79°C To calculate...Chapter 11, Problem 117AEChapter 11, Problem 128CPChapter 11, Problem 138CPChapter 11, Problem 142IPChapter 12, Problem 1RQChapter 12, Problem 29EChapter 12, Problem 32EChapter 12, Problem 35EChapter 12, Problem 37EChapter 12, Problem 38EChapter 12, Problem 60EChapter 12, Problem 88AEChapter 12, Problem 90AEChapter 12, Problem 91AEChapter 12, Problem 97AEChapter 12, Problem 101AEChapter 12, Problem 113CPChapter 12, Problem 122CPChapter 13, Problem 1RQChapter 13, Problem 5ALQChapter 13, Problem 27EChapter 13, Problem 38EChapter 13, Problem 45EChapter 13, Problem 48EChapter 13, Problem 60EChapter 13, Problem 62EChapter 13, Problem 63EChapter 13, Problem 82AEChapter 13, Problem 83AEChapter 13, Problem 88AEChapter 13, Problem 114CPChapter 13, Problem 116CPChapter 14, Problem 1RQChapter 14, Problem 53EChapter 14, Problem 65EChapter 14, Problem 66EChapter 14, Problem 70EChapter 14, Problem 74EChapter 14, Problem 75EChapter 14, Problem 98EChapter 14, Problem 101EChapter 14, Problem 107EChapter 14, Problem 108EChapter 14, Problem 109EChapter 14, Problem 119EChapter 14, Problem 120EChapter 14, Problem 123EChapter 14, Problem 125EChapter 14, Problem 126EChapter 14, Problem 153AEChapter 14, Problem 163AEChapter 14, Problem 172CWPChapter 15, Problem 1RQChapter 15, Problem 7RQChapter 15, Problem 49EChapter 15, Problem 63EChapter 15, Problem 64EChapter 15, Problem 65EChapter 15, Problem 66EChapter 15, Problem 67EChapter 15, Problem 68EChapter 15, Problem 69EChapter 15, Problem 70EChapter 15, Problem 71EExplanation The value of pH of solution when 0.0 ​mL NaOH has been added is. 1.0_ . Given: The...Chapter 15, Problem 119CWPChapter 16, Problem 1RQExplanation To determine: The solubility product of CaC2O4 . The concentration of Ca2+ is 4.8×10−5...Chapter 16, Problem 26EChapter 16, Problem 31EChapter 16, Problem 32EChapter 16, Problem 39EChapter 16, Problem 40EChapter 16, Problem 41EChapter 16, Problem 44EChapter 16, Problem 57EChapter 16, Problem 74EChapter 16, Problem 107CPChapter 16, Problem 108CPChapter 17, Problem 1RQChapter 17, Problem 57EChapter 17, Problem 59EChapter 17, Problem 69EChapter 17, Problem 70EChapter 17, Problem 74EChapter 17, Problem 76EChapter 17, Problem 78EChapter 17, Problem 80EChapter 17, Problem 84EChapter 17, Problem 93AEChapter 17, Problem 96AEChapter 17, Problem 100AEChapter 17, Problem 131MPChapter 18, Problem 1RQChapter 18, Problem 18RORRChapter 18, Problem 22RORRChapter 18, Problem 47EChapter 18, Problem 67EChapter 18, Problem 68EChapter 18, Problem 73EChapter 18, Problem 74EChapter 18, Problem 83EChapter 18, Problem 84EChapter 18, Problem 93EChapter 18, Problem 111AEChapter 18, Problem 113AEChapter 18, Problem 144CPExplanation The half cell reactions are, Anode: Hg→Hg2++2e− Eanodeο=0.242 V Cathode: 2Ag++2e−→2Ag...Chapter 18, Problem 153CPChapter 18, Problem 159MPExplanation (a) To define: The term thermodynamic stability. The thermodynamic stability is related...Explanation: Alpha particle is emitted. The parent nuclide is 232Th and the nuclide after the...Explanation The most stable isotope is 81Kr and the hottest one is 73Kr The nuclides having longer...Explanation Given The atomic mass of 232Pu is 3.85285×10−22 g . The mass of a neutron is...Explanation The atomic mass of 11H=1.0078 amu The mass of a neutron is 1.0087 amu . Mass of...Explanation To determine: The decay events per second in a 180−lb person. The number of atoms of 14C...Explanation Given The value of half life of 87Rb is 4.5×109 years . The decay constant is calculated...Explanation The decay constant is calculated by the formula given below. λ=0.693t1/2 Where t1/2 is...Explanation: The zirconium metal is capable of reducing water to form hydrogen gas at standard...Explanation The number of α and β particles produced are 4_ and 2_ . The mass number of 92238U is...Explanation The nuclear reaction for the synthesis of cobalt- 60 is, 2658Fe+201n→ 2760Co+ −10e . The...Chapter 20, Problem 1RQExplanation The valence electron configuration for halogens is ns2np5 . The common halogen elements...The stated reaction is, CH4(g)+H2O(g)⇌CO(g)+3H2(g) Refer to Appendix 4 The value of ΔH°(kJ/mol) for...Chapter 20, Problem 12QExplanation The value of ΔH° for the given reaction is 180 kJ_ . The stated reaction is,...Explanation: The compound XeO4 and IO4− ion are isoelectronic. The molecule xenon tetroxide (XeO4)...Explanation: The Lewis structure, molecular structure, bond angle and hybridization of central atom...Explanation: Hydrogen gas is produced by reacting graphite with water. C(s)+H2O(g)→CO(g)+H2(g) The...Explanation: The number of moles of hydrogen gas is 0.249 mol_. Given Mass of alkaline earth metal...Explanation: Mass of radon (Ra) is 25 g_ . Given Mass of pitch-blende is 1.75×108 g . The conversion...Explanation Given Temperature is 900 K . Pressure of In(CH3)3 is 2.00 atm . Volume of In(CH3)3 is...Chapter 20, Problem 118IPChapter 20, Problem 119IPChapter 21, Problem 1RQExplanation: (I) To determine: The geometry and associated bond angles when a metal ion has a...Valence electrons are filled in four principal orbitals according to the energy levels. The four...EXPLANATION (a) To write: The electron configuration of metal ion in (NH4)2[Fe(H2O)2Cl4] . The...Explanation The complex ion is [Ru(NH3)5Cl]2+. This ion contains positive charge. Oxidation state of...Explanation The complex compound is [Co(NH3)6]Cl2 . Oxidation state of Chlorine ion (Cl−) is −1 ....Explanation The complex compound is [Cr(H2O)5Br]Br2 . Oxidation state of Bromine ion (Br−) is −1 ....Explanation The value of ΔH° for the given reaction is −11 kJ_ . For the reaction,...Explanation The reaction that takes place is, 3Fe2O3(s)+CO(g)→2Fe3O4(s)+CO2(g) Refer to Appendix 4....The given compound is CoCl2.6H2O. It is used in novelty devices that predict rain. The coordination...Explanation The given equations are, Co+3+e−→Co+2 Eο=1.82 V (1) Co2++3en→Co(en)32+ K=1.5×1012 (2)...Chapter 21, Problem 107IPChapter 22, Problem 1RQChapter 22, Problem 5RQChapter 22, Problem 18EChapter 22, Problem 49EExplanation To determine: The monomer of the given polymer. The monomer is vinyl fluoride. It is an...Explanation The correct name of the compound is 2,3,5,6−Tetramethyl−octane whose structure is shown...Explanation The structure of the given compound 2,3,7,8−tetrachloro−dibenzo−p−dioxin is shown in...Chapter 22, Problem 142AEChapter 22, Problem 148AEChapter 22, Problem 158CPExplanation The equilibrium constant for the given reaction is 6.88×10−13_ . The equilibrium...Chapter 22, Problem 162CPExplanation The structure of C5H12 is shown in Figure 1. The structure of C5H12 is, Figure 1 The...Explanation The structure of the polymer of ABS plastic is shown in figure 1. The reaction of Abs...Chapter 22, Problem 171CPExplanation Given Electronic configuration of M+2 is [Ar]3d10. So, atomic number of M is 30. In...Explanation The empirical formula of the given helicene is C5H3 . Helicene is an aromatic compound...The correct responses are urea and Ammonium cyanate. The first organic compound that is synthesized...Explanation Aldohexose is a six carbon aldehyde sugar with an aldehyde group on one end.

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